P - Block Elements MCQ Questions & Answers in Inorganic Chemistry | Chemistry
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571.
In compounds of type $$EC{l_3},$$ where $$E = B,P,$$ $$As$$ or $$Bi,\,$$ the angles $$Cl - E - Cl$$ for different $$E$$ are in the order
A
$$\,B > P = As = Bi$$
B
$$B > P > As > Bi$$
C
$$B < P = As = Bi$$
D
$$B < P < As < Bi$$
Answer :
$$B > P > As > Bi$$
$$BC{l_3},\,\,H = \frac{1}{2}\left( {3 + 3 + 0 - 0} \right) = 3;\,s{p^2}\,{\text{hybridization}}$$
$$\left( {{\text{bond}}\,{\text{angle}} = {{120}^ \circ }} \right)$$ similarly $$PC{l_3}\,AsC{l_3}$$ and $$BiC{l_3}$$ are found to have $$s{p^3}$$ hybridized central atom with one lone pair of electrons on the central atom. The bond angle \[\le {{109}^{\circ }}28',\] since the central atoms belong to the same group, the bond angle of the chlorides decreases as we go down the group. Thus the order of bond angle is, $$BC{l_3} > PC{l_3} > AsC{l_3} > BiC{l_3}.\,$$
572.
Identify $$X$$ and $$Y$$ in the following reaction : \[BC{{l}_{3}}+N{{H}_{4}}Cl\xrightarrow[{{C}_{6}}{{H}_{5}}Cl]{{{140}^{\circ }}C}X\] \[\xrightarrow{NaB{{H}_{4}}}Y\]
573.
Xenon has closed shell configuration but is known to give compounds with fluorine because
A
$$Xe$$ atom has large size and lower ionisation potential as compared to other noble gases
B
$$Xe$$ has unpaired electrons which can form covalent bonds
C
$$Xe$$ has highest boiling point hence it can form compounds with fluorine
D
fluorine is the smallest element hence it can react with all noble gases
Answer :
$$Xe$$ atom has large size and lower ionisation potential as compared to other noble gases
No explanation is given for this question. Let's discuss the answer together.
574.
Which of the following structure is similar to graphite?
A
$$BN$$
B
$$B$$
C
$${B_4}C$$
D
$${B_2}{H_6}$$
Answer :
$$BN$$
Boron nitride $${\left( {BN} \right)_x}$$ resembles with graphite in structure as shown below
575.
The correct order of increasing electron affinity of halogens is
A
$$I < Br < Cl$$
B
$$Br < I < Cl$$
C
$$Cl < Br < I$$
D
$$I < Cl < Br$$
Answer :
$$I < Br < Cl$$
Electron affinity decreases down the group as atomic size increases.
576.
The following acids have been arranged in order of decreasing acid strength. Identify the correct order.
$$\eqalign{
& \left( {\text{i}} \right)ClOH \cr
& \left( {{\text{ii}}} \right)BrOH \cr
& \left( {{\text{iii}}} \right)IOH \cr} $$
A
(i) > (ii) > (iii)
B
(ii) > (i) > (iii)
C
(iii) > (ii) > (i)
D
(i) > (iii) > (ii)
Answer :
(i) > (ii) > (iii)
No explanation is given for this question. Let's discuss the answer together.
577.
Match the column I with column II and mark the appropriate choice.
Column I
Column II
a.
Coal gas
1.
$$CO + {H_2}$$
b.
Synthesis gas
2.
$$C{H_4}$$
c.
Producer gas
3.
$${H_2} + C{H_4} + CO$$
d.
Natural gas
4.
$$CO + {N_2}$$
A
a - 1, b - 2, c - 3, d - 4
B
a - 3, b - 1, c - 4, d - 2
C
a - 4, b - 3, c - 2, d - 1
D
a - 1, b - 3, c - 2, d - 4
Answer :
a - 3, b - 1, c - 4, d - 2
No explanation is given for this question. Let's discuss the answer together.
578.
The tendency of group 14 elements to show + 2 oxidation state increases in the order of
A
$$C < Si < Sn < Pb < Ge$$
B
$$C < Si < Ge < Sn < Pb$$
C
$$Ge < Sn < Pb < C < Si$$
D
$$Pb < Sn < Ge < C < Si$$
Answer :
$$C < Si < Ge < Sn < Pb$$
The tendency to show + 2 oxidation state increases down the group. It is due to inability of $$n{s^2}$$ electrons of valence shell to participate in bonding.
579.
In qualitative analysis when $${H_2}S$$ is passed through an aqueous solution of salt acidified with \[dil.HCl,\] a black precipitate is obtained. On boiling the precipitate with \[dil.HN{{O}_{3}},\] it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives _________.
A
deep blue precipitate of $$Cu{\left( {OH} \right)_2}$$
B
deep blue solution of $${\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]^{2 + }}$$
C
deep blue solution of $$Cu{\left( {N{O_3}} \right)_2}$$
D
deep blue solution of $$Cu{\left( {OH} \right)_2} \cdot Cu{\left( {N{O_3}} \right)_2}$$
Answer :
deep blue solution of $${\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]^{2 + }}$$