P - Block Elements MCQ Questions & Answers in Inorganic Chemistry | Chemistry
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611.
Which of the following is used as protective shields in nuclear industries?
A
$$^{27}Al$$
B
$$^{10}B$$
C
$$^{16}O$$
D
$$^{14}C$$
Answer :
$$^{10}B$$
Boron steel or boron carbide rods are used to control the nuclear reactions. Boron has a very high cross-section to capture the neutrons.
612.
Which of the following is a Lewis acid?
A
$$AlC{l_3}$$
B
$$MgC{l_2}$$
C
$$CaC{l_2}$$
D
$$BaC{l_2}$$
Answer :
$$AlC{l_3}$$
$$AlC{l_3}$$ is electron deficient, hence acts as Lewis acid.
613.
Aqueous solution of ammonia consists of
A
$${H^ + }$$
B
$$O{H^ - }$$
C
$$NH_4^ + $$
D
$$NH_4^ + \,{\text{and}}\,O{H^ - }$$
Answer :
$$NH_4^ + \,{\text{and}}\,O{H^ - }$$
When ammonia dissolve in water, it form ammonium hydroxide which is ionise as given below
$$N{H_3} + {H_2}O \to N{H_4}OH \rightleftharpoons NH_4^ + + O{H^ - }$$
614.
\[\begin{align}
& M{{g}_{3}}{{B}_{2}}\xrightarrow{HC{{l}_{\left( aq \right)}}}\left[ X \right]+MgC{{l}_{2}} \\
& \left[ X \right]+{{H}_{2}}O\xrightarrow{HC{{l}_{\left( aq \right)}}}\left[ Y \right]+{{H}_{2}} \\
\end{align}\]
For $$\left[ X \right]$$ and $$\left[ Y \right]$$ the incorrect choice is
A
$$\left[ X \right]$$ is $${B_2}{H_6}$$ and $$\left[ Y \right]$$ is $${H_3}B{O_3}$$
B
$$\left[ X \right]$$ with air and $$\left[ Y \right]$$ on strong heating ( red heat ) give same compound
C
In $$\left[ Y \right],$$ boron completes its octet by removing $${H^ + }$$ from water molecule
D
None of these
Answer :
None of these
\[\begin{align}
& M{{g}_{3}}{{B}_{2}}+6HC{{l}_{\left( aq \right)}}\to \underset{\left( X \right)}{\mathop{{{B}_{2}}{{H}_{6}}}}\,+3MgC{{l}_{2}} \\
& \underset{\left( X \right)}{\mathop{{{B}_{2}}{{H}_{6}}}}\,+6{{H}_{2}}O\to \underset{\left( Y \right)}{\mathop{2{{H}_{3}}B{{O}_{3}}}}\,+6{{H}_{2}} \\
& \underset{\left( X \right)}{\mathop{{{B}_{2}}{{H}_{6}}}}\,+3{{O}_{2}}\to {{B}_{2}}{{O}_{3}}+3{{H}_{2}}O \\
& \underset{\left( Y \right)}{\mathop{{{H}_{3}}B{{O}_{3}}}}\,\xrightarrow{\Delta }{{B}_{2}}{{O}_{3}} \\
\end{align}\]
In $$Y,B$$ completes it octet by removing \[{{H}^{+}}\] from water molecule.
616.
Which of the following statements is not correct for nitrogen?
A
Its electronegativity is very high
B
$$d$$-orbitals are available for bonding
C
It is a typical non-metal
D
Its molecular size is small
Answer :
$$d$$-orbitals are available for bonding
Nitrogen does not have vacant $$d$$-orbital in its outermost shell.
$$N\left( 7 \right) = 1{s^2},2{s^2}2{p^3}$$
617.
Bleaching powder reacts with a few drops of $$conc.$$ $$HCl$$ to give
A
chlorine
B
hypochlorous acid
C
calcium oxide
D
oxygen
Answer :
chlorine
When bleaching powder reacts with $$HCl,$$ it form chlorine gas.
$$CaOC{l_2} + 2HCl \to CaC{l_2} + {H_2}O + C{l_2}$$
618.
A solution of $$KBr$$ is treated with each of the following.
Which one would liberate bromine
A
$$C{l_2}$$
B
$$HI\,$$
C
$${I_2}$$
D
$$S{O_2}$$
Answer :
$$C{l_2}$$
$$\because \,C{l_2}$$ is more reactive than bromine
619.
Bond angle in $${H_2}O\left( {{{104.5}^ \circ }} \right)$$ is higher than the bond angle of $${H_2}S\left( {{{92.1}^ \circ }} \right).$$ The difference is due to
A
$$O$$ is diatomic and $$S$$ is tetra-atomic
B
difference in electronegativity of $$S$$ and $$O$$
C
difference in oxidation states of $$S$$ and $$O$$
D
difference in shapes of hybrid orbitals of $$S$$ and $$O.$$
Answer :
difference in electronegativity of $$S$$ and $$O$$
No explanation is given for this question. Let's discuss the answer together.
620.
Which of the following oxides is anhydride of nitrous acid?