Isomerism MCQ Questions & Answers in Organic Chemistry | Chemistry
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11.
The number of structural isomers for $${C_6}{H_{14}}$$ is :
A
4
B
3
C
6
D
5
Answer :
5
12.
An isomer of ethanol is :
A
methanol
B
diethyl ether
C
acetone
D
dimethyl ether
Answer :
dimethyl ether
$$\mathop {C{H_3} - O - C{H_3}}\limits_{{\text{dimethyl ether}}} \,{\text{is an isomer of}}\,\mathop {C{H_3}C{H_2}OH}\limits_{{\text{ethanol}}} $$
13.
1-Butene and cyclobutane show
A
position isomerism
B
ring-chain isomerism
C
functional isomerism
D
metamerism
Answer :
ring-chain isomerism
No explanation is given for this question. Let's discuss the answer together.
14.
The alcohol product$$(s)$$ of the reduction of 2-methyl-3-pentanone with $$LiAl{H_4}$$ is (are)
A
a single enantiomer
B
racemic mixture
C
two diastereoisomers
D
two structural isomers
Answer :
racemic mixture
The resulting compound is $${C_3}{H_7}CH\left( {OH} \right){C_2}{H_5}$$ which is optically inactive and reaction leads the racemisation.
15.
Which of the following is an isomer of ethanol?
A
Methanol
B
Acetone
C
Diethylether
D
Dimethylether
Answer :
Dimethylether
Ether and alcohol are functional isomers.
16.
In the given conformation, if $${C_2}$$ is rotated about $${C_2} - {C_3}$$ bond anticlockwise by an angle of $${120^ \circ }$$ then the conformation
obtained is
A
fully eclipsed conformation
B
partially eclipsed conformation
C
gauche conformation
D
staggered conformation
Answer :
gauche conformation
TIPS/Formulae :
Any conformation between two extreme positions i.e. eclipsed and staggered is known as Gauche or Skew from.
17.
The number of stereoisomers possible for a compound of
the molecular formula $$C{H_3} - CH = CH - CH\left( {OH} \right) - Me$$ is :
A
2
B
4
C
6
D
3
Answer :
4
exhibits both geometrical as well as optical isomerism.
$$\eqalign{
& cis - R \cr
& cis - S \cr
& trans - R \cr
& trans - S \cr} $$
18.
The number of structural and configurational isomers of a bromo compound, $${C_5}{H_9}Br,$$ formed by the addition of $$HBr$$ to 2-pentyne respectively are
A
1 and 2
B
2 and 4
C
4 and 2
D
2 and 1
Answer :
2 and 4
Addition of $$HBr$$ to 2-pentyne gives two structural isomers (i) and (ii).
\[C{{H}_{3}}-C\equiv C-C{{H}_{2}}C{{H}_{3}}\xrightarrow{HBr}\] $$C{H_3}C\left( {Br} \right)\mathop = \limits_{\left( {\text{i}} \right)} CHC{H_2}C{H_3} + C{H_3}CH$$ $$\mathop = \limits_{\left( {{\text{ii}}} \right)} C\left( {Br} \right)C{H_2}C{H_3}$$
Each one of these will exist as a pair of geometrical isomers as shown below :
Thus, there are two structural and four configurational isomers.
19.
Which of the following is correct set of physical properties of the geometrical isomers ?
A
(a)
B
(b)
C
(c)
D
(d)
Answer :
(c)
In compounds
I has more dipole moment than II, hence its boiling point will be higher. Melting point depends on symmetry, therefore I has higher melting point than II. Steric crowding in II is more than in I therefore I is more stable than II.
20.
The number of isomers for the compound with molecular
formula $${C_2}BrClFI$$ is
A
3
B
4
C
5
D
6
Answer :
6
Number of isomers (six) can be derived by keeping the
position of any one halogen (say $$Br$$ ) fixed and changing
the position of the other halogen one by one.