Learn Organic Compounds Containing Nitrogen MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
161.
Secondary amines could be prepared by
A
reduction of nitriles
B
Hoffmann bromamide reaction
C
reduction of isonitrile
D
all of these
Answer :
reduction of isonitrile
162.
Match the compounds in List $$I$$ with their nature from List $$II,$$ as seen in aqueous medium
$$\eqalign{
& \,\,\,\,\,\,\,\,\,{\text{List I }}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{List II}} \cr
& {\text{I}}{\text{. Acetamide }}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{A}}{\text{. Acidic}} \cr
& {\text{II}}{\text{. Benzonitrile }}\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{B}}{\text{. Basic}} \cr
& {\text{III}}{\text{. Triethylamine }}\,\,\,\,\,\,{\text{C}}{\text{. Neutral}} \cr
& {\text{IV}}{\text{. Phenol}} \cr} $$
A
I - C; II - C; III - B; IV - A
B
I - B; II - C; III - C; IV - A
C
I - C; II - B; III - B; IV - C
D
I - A; II - A; III - C; IV - B
Answer :
I - C; II - C; III - B; IV - A
Acetamide is basic due to the presence of lone pair of electrons of $$N;$$ it is also acidic because its conjugate base shows resonance.
( more stable due to $$–ve$$ charge on $$O$$ )
Benzonitrile $$\left( {{C_6}{H_5}C \equiv N} \right)$$ acts as an electrophile (Lewis acid) due to electron deficiency of $$C$$ of $$CN$$ as well as nucleophile ( Lewis base ) in nature due to presence of lone pair electrons on $$N;$$ hence it is neutral Triethylamine and phenol are basic and acidic in nature respectively.
163.
In the reaction \[C{{H}_{2}}CN\xrightarrow[NaN{{H}_{2}},\,N{{H}_{3}},\,-{{80}^{\circ }}C]{C{{H}_{3}}Br}\]
the products obtained are
A
B
C
D
Answer :
Nitriles having \[\alpha \] - hydrogen atom form alkyl derivatives with $$RBr$$ in presence of \[NaN{{H}_{2}}/N{{H}_{3}}.\]
164.
Carbylamine test is performed in alcoholic \[KOH\] by heating
a mixture of :
A
chloroform and silver powder
B
trihalogenatedmethane and a primary amine
C
an alkyl halide anda primary amine
D
an alkyl cyanide and a primary amine
Answer :
trihalogenatedmethane and a primary amine
NOTE: Only primary aliphatic and aromatic amines give this test.
\[CH{{X}_{3}}+RN{{H}_{2}}+3KOH\to RNC+3KX+3{{H}_{2}}O\]
165.
The most unlikely representation of resonance structures of $$p $$ - nitrophenoxide ion is
A
B
C
D
Answer :
$$N$$ can't have more than 8 electrons in its valence shell as it does not have any $$d$$ orbital. In (C), $$N$$ has 10 electrons.
166. Product $$P$$ is
A
\[{{\left( C{{H}_{3}} \right)}_{3}}CN{{H}_{2}}\]
B
\[{{\left( C{{H}_{3}} \right)}_{3}}CNHD\]
C
\[{{\left( C{{H}_{3}} \right)}_{3}}CN{{D}_{2}}\]
Remember that in Hofmann rearrangement, the two original $$H$$ atoms of the \[-CON{{H}_{2}}\] group are removed by base \[\left( O{{H}^{-}} \right)\] and new \[H'\text{s}\] are derived from \[{{H}_{2}}O.\]
167.
Primary amines react with benzoyl chloride to give
A
benzamides
B
ethanamides
C
imides
D
imines
Answer :
benzamides
Primary amines react with benzoyl chloride to give benzamides and the reaction is known as benzoylation.
$$\mathop {C{H_3}N{H_2}}\limits_{{\text{Methanamine}}} + \mathop {{C_6}{H_5}COCl}\limits_{{\text{Benzoyl chlorid}}} \to $$ $$\mathop {C{H_3}NHCO{C_6}{H_5} + HCl}\limits_{N{\text{ - Methylbenzamide}}} $$
168.
Which of the following amines will react with cyclohexanone to give enamine ?
A
B
C
D
Answer :
Carbonyl compounds containing at least one $$\alpha $$ - hydrogen atom react with a secondary amine to give enamine
In second case enamine – amine tautomerism is possible and equilibrium lies completely on the imine side.
169.
Aniline reacts with phosgene and $$KOH$$ to form