Learn Organic Compounds Containing Nitrogen MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
171.
Which of the following methods can be used to carry out the following conversions?
(i)
(ii)
(iii)
(a)
$$B{r_2}/KOH$$
$$CHC{l_3}/KOH$$
$${H_2}/Pd$$
(b)
$$KCN$$
$${H_2}/Pd$$
$$Sn/HCl$$
(c)
$$CuCN$$
$${H_2}O/{H^ + }$$
$${H_2}/Pd$$
(d)
$$HN{O_3}/{H_2}S{O_4}$$
$${\left( {C{H_3}CO} \right)_2}O$$
$$Fe/HCl$$
A
(a)
B
(b)
C
(c)
D
(d)
Answer :
(a)
172.
The correct order of increasing reactivity of $$C-X$$ bond towards nucleophile in the following compounds is
A
I < II < IV < III
B
II < III < I < IV
C
IV < III < I < II
D
III < II < I < IV
Answer :
I < II < IV < III
Key Idea Alkyl halides are more reactive towards nucleophilic substitution. Reactivity depends upon the stability of carbocation intermediate formed.
Among the given halides, aryl halide $$\left( {{C_6}{H_5}X} \right)$$ is least reactive towards nucleophile as in it the $$C - X$$ bond acquire some double bond character due to resonance. Presence of electron withdrawing groups like $$ - N{O_2}$$ at $$ortho$$ and $$para$$ - positions facilitate the nucleophilic displacement of $$-X$$ of aryl halide. Among alkyl halides, $${3^ \circ }$$ halides are more reactive as compared to $${2^ \circ }$$ halides due to the formation of more stable carbocation. Hence, the order of reactivity of $$C-X$$ bond towards nucleophile is as follows :
173.
A compound with molecular mass 180 is acylated with $$C{H_3}COCl$$ to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is :
A
2
B
5
C
4
D
6
Answer :
5
Now since the molecular mass increases by 42 unit as a result of the reaction of one mole of $$C{H_3}COCl$$ with one - $$N{H_2}$$ group and the given increase in mass is 210. hence the number of $$ - N{H_2}$$ group is $$ = \frac{{210}}{{42}} = 5$$
174.
In the chemical reaction, $$C{H_3}C{H_2}N{H_2} + CHC{l_3} + 3KOH$$ $$ \to \left( A \right) + \left( B \right) + 3{H_2}O,$$ the compounds $$\left( A \right)$$ and $$\left( B \right)$$ are respectively
A
$${C_2}{H_5}NC\,{\text{and}}\,3KCl$$
B
$${C_2}{H_5}CN\,{\text{and}}\,3KCl$$
C
$$C{H_3}C{H_2}CON{H_2}\,{\text{and}}\,3KCl$$
D
$${C_2}{H_5}NC\,{\text{and}}\,{K_2}C{O_3}$$
Answer :
$${C_2}{H_5}NC\,{\text{and}}\,3KCl$$
This is carbylamine reaction.
\[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}+CHC{{l}_{3}}+3KOH\,\,\to \,{{C}_{2}}{{H}_{5}}NC+3KCl+3{{H}_{2}}O\]
175.
Which of the following is the strongest base ?
A
B
C
D
Answer :
Aliphatic amines are stronger base than aromatic amines. Further the order $${2^ \circ } > {1^ \circ } > {3^ \circ } > N{H_3}$$
176.
The product $$'D'$$ in the following sequence of reactions is \[\xrightarrow[\left( aq. \right)]{B{{r}_{2}}}A\xrightarrow[HCl]{NaN{{O}_{2}}}B\xrightarrow{HB{{F}_{4}}}\] \[C\xrightarrow{\text{heat}}D\]
A
2, 4, 6 - tribromofluorobenzene
B
fluorobenzene
C
$$p$$ - bromofluorobenzene
D
tribromobenzene
Answer :
2, 4, 6 - tribromofluorobenzene
177.
Which of the following compounds is the weakest $${\rm{Br\ddot onsted}}$$ base?
A
B
C
D
Answer :
Amines are stronger $${\rm{Br\ddot onsted}}$$ bases than alcohols and phenols as they have tendency to accept a proton.
Phenols are more acidic than alcohols, thus, phenol has least tendency to accept a proton hence, is the weakest $${\rm{Br\ddot onsted}}$$ base.
178.
Acetanilide on nitration followed by alkaline hydrolysis mainly gives
A
$$o$$ - Nitroacetanilide
B
$$p$$ - Nitroaniline
C
$$m$$ - Nitroaniline
D
2, 4, 6 - Trinitroaniline
Answer :
$$p$$ - Nitroaniline
179.
Match the compounds given in column I with column II and mark the appropriate choice.
Column I
Column II
a.
Benzenesulphonyl chloride
1.
Zwitter ion
b.
Sulphanilic acid
2.
Hinsberg's reagent
c.
Alkyldiazonium salts
3.
Dyes
d.
Aryldiazonium salts
4.
Conversion to alcohols
A
a - 4, b - 3, c - 1, d - 2
B
a - 2, b - 4, c - 3, d - 1
C
a - 2, b - 1, c - 4, d - 3
D
a - 2, b - 3, c - 4, d - 1
Answer :
a - 2, b - 1, c - 4, d - 3
No explanation is given for this question. Let's discuss the answer together.
180.
In the reaction shown below, the major product(s) formed is/are \[\xrightarrow[C{{H}_{2}}C{{l}_{2}}]{\text{acetic}\,\text{anhydride}}\text{product}\left( \text{S} \right)\]
A
B
C
D
Answer :
Acetylation takes place when amine ( not amide ) combines with acetyl chloride or acetic anhydride.