Learn Organic Compounds Containing Nitrogen MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
261.
Which one of the following reducing agents is likely to be most effective in bringing about the following change?
\[R\overset{\begin{smallmatrix}
O \\
\parallel
\end{smallmatrix}}{\mathop{-C-}}\,N{{H}_{2}}\to RC{{H}_{2}}N{{H}_{2}}\]
A
$${H_2} - Ni$$
B
$$NaB{H_4}$$
C
$$LiAl{H_4}$$
D
$$Na - {\text{Alcohol}}$$
Answer :
$$LiAl{H_4}$$
No explanation is given for this question. Let's discuss the answer together.
262.
Benzylamine may be alkylated as shown in the following equation :
$${C_6}{H_5}C{H_2}N{H_2} + R - X \to $$ $${C_6}{H_5}C{H_2}NHR$$
Which of the following alkyl halides is best suited for this reaction through $${S_N}1$$ mechanism?
A
$$C{H_3}Br$$
B
$${C_6}{H_5}Br$$
C
$${C_6}{H_5}C{H_2}Br$$
D
$${C_2}{H_5}Br$$
Answer :
$${C_6}{H_5}C{H_2}Br$$
$${C_6}{H_5}C{H_2}Br$$ is best suited for this reaction through $${S_N}1$$ mechanism as the carbocation $$({C_6}{H_5}\mathop C\limits^ + {H_2})$$ formed is resonance stabilized.
263.
Predict about the relative boiling point of the following two amines.
A
Boiling point of I > II
B
Boiling point of II > I
C
Both should have equal boiling points
D
It can’t be predicted
Answer :
Boiling point of II > I
In II, intermolecular $$H$$ - bonding between similar molecules is possible, while this is not so in I.
264.
In a reaction of aniline a coloured product $$C$$ was obtained.
The structure of $$C$$ would be :
A
B
C
D
Answer :
The reaction can be completed as follows :
265.
Which of the following will form isocyanide on reaction with $$CHC{l_3}$$ and $$KOH?$$
A
$${C_6}{H_5}NHC{H_3}$$
B
$$C{H_3}{C_6}{H_4}N{H_2}$$
C
$${C_6}{H_5}NH{C_4}{H_9}$$
D
$${C_6}{H_5}N{\left( {{C_2}{H_5}} \right)_2}$$
Answer :
$$C{H_3}{C_6}{H_4}N{H_2}$$
Only primary amine will give positive carbylamine reaction when heated with $$CHC{l_3}$$ and alcoholic $$KOH.$$
266.
Identify the reagents $$X, Y$$ and $$Z$$ for the following products.
$$X$$
$$Y$$
$$Z$$
(a)
$${I_2},$$ warm
$$KCN,$$ warm
$$NaOH,$$ warm
(b)
$$CuI$$
$$NaCN$$
$$KOH$$
(c)
$$KI,$$ warm
$$CuCN$$
$${H_2}O,$$ warm
(d)
$$AgI,$$ warm
$$AgCN,$$ warm
$$KOH,$$ boil
A
(a)
B
(b)
C
(c)
D
(d)
Answer :
(c)
No explanation is given for this question. Let's discuss the answer together.
267.
Considering the basic strength of amines in aqueous solution which one has the smallest $$p{K_b}$$ value?
A
$${\left( {C{H_3}} \right)_2}NH$$
B
$$C{H_3}N{H_2}$$
C
$${\left( {C{H_3}} \right)_3}N$$
D
$${C_6}{H_5}N{H_2}$$
Answer :
$${\left( {C{H_3}} \right)_2}NH$$
Arylamines are less basic than alkyl amines and even ammonia. This is due to resonance. In aryl amines the lone pair of electrons on $$N$$ is partly shared with the ring and is thus less available for sharing with a proton. In alkylamines, the electron releasing alkyl group increases the electron density on nitrogen atom and thus also increases the ability of amine for protonation. Hence more the no. of alkyl groups higher should be the basicity of amine. But a slight discrepancy occurs in case of trimethyl amines due to steric effect. Hence the correct order is
$${\left( {C{H_3}} \right)_2}NH > C{H_3}N{H_2} > {\left( {C{H_3}} \right)_3}N > {C_6}{H_5}N{H_2}$$
268.
Primary amines on reaction with nitrous acid form ________. For the test of primary amines ________ reaction is used. Primary amines are ________ basic than ammonia.
A
carboxylic acids, Hoffmann, less
B
alcohols, carbylamine, less
C
alcohols, carbylamine, more
D
hydroxylamines, carbylamine, less
Answer :
alcohols, carbylamine, more
No explanation is given for this question. Let's discuss the answer together.
269.
$$'Z'$$ in the following sequence of reactions is
\[{{C}_{6}}{{H}_{6}}\xrightarrow[\Delta ]{HN{{O}_{3}}/{{H}_{2}}S{{O}_{4}}}W\xrightarrow{Zn/HCl}\] \[X\xrightarrow[HCl]{NaN{{O}_{2}}}Y\xrightarrow{{{H}_{2}}O/{{H}_{3}}P{{O}_{2}}}Z\]
A
B
C
D
Answer :
270.
Which of the following is the weakest $${\rm{Br\ddot onsted}}$$ base?
A
B
C
D
Answer :
is the weakest $${\rm{Br\ddot onsted}}$$ base due to delocalisation of lone pair of electrons of $$N$$ - atom into the benzene ring.