Learn Organic Compounds Containing Nitrogen MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
271.
Which of the following compounds is an enamine ?
A
B
C
D
Answer :
Enamine ( ene for carbon-carbon double bond and amine for amine group ). \[>C=C-N<\]
272.
The correct order of basicities of the following compounds is
A
2 > 1 > 3 > 4
B
1 > 3 > 2 > 4
C
3 > 1 > 2 > 4
D
1 > 2 > 3 > 4
Answer :
1 > 3 > 2 > 4
The protonated form of $$H$$ would be III which is more
stable because here the contributing structures (III) and (IV) are equivalent.
In \[C{{H}_{3}}-\overset{\centerdot \,\centerdot }{\mathop{N}}\,H-C{{H}_{3}},\] the availability of electron pair
increases due to the \[+I\] effect of two \[C{{H}_{3}}\] groups while
in \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}},+I\] effect of only one ethyl group is operative. In the electron availability
on nitrogen decreases due to resonance as shown
below
Therefore, the order of basic strength would be
1 > 3 > 2 > 4 .
273.
Which of the following amines can be resolved into two enantiomers ?
A
I, IV
B
I, II
C
I, III, IV
D
III, IV
Answer :
III, IV
Most of the simple amines those having smaller alkyl ( groups ) can’t be resolved , although they may contain three different alkyl groups.
274.
Among the following,
$$\eqalign{
& \left( {\text{i}} \right)C{H_3}N{H_2} \cr
& \left( {{\text{ii}}} \right){\left( {C{H_3}} \right)_2}NH \cr
& \left( {{\text{iii}}} \right){\left( {C{H_3}} \right)_3}N \cr
& \left( {{\text{iv}}} \right){C_6}{H_5}N{H_2} \cr} $$
Which will give the positive carbylamine test?
A
(i) and (ii) only
B
(i) and (iv) only
C
(ii) and (iv) only
D
(ii) and (iii) only
Answer :
(i) and (iv) only
No explanation is given for this question. Let's discuss the answer together.
275.
Electrophilic substitution of aniline with brominewater at room temperature gives
A
2-bromoaniline
B
3-bromoaniline
C
2, 4, 6-tribromoaniline
D
3, 5, 6-tribromoaniline
Answer :
2, 4, 6-tribromoaniline
276.
Match the column I with column II and mark the appropriate choice.
A
A - iv, B - iii, C - ii, D - i
B
A - iii, B - iv, C - i, D - ii
C
A - ii, B - iii, C - iv, D - i
D
A - i, B - ii, C - iii, D - iv
Answer :
A - iv, B - iii, C - ii, D - i
No explanation is given for this question. Let's discuss the answer together.
277.
The end product $$Z$$ of the reaction :
Ethyl amine \[\xrightarrow{HN{{O}_{2}}}X\xrightarrow{PC{{l}_{5}}}Y\xrightarrow{KCN}Z\] is
A
propanenitrile
B
triethylamine
C
diethylamine
D
propylamine
Answer :
propanenitrile
278.
For carbylamine reaction, we need hot $$alc.$$ $$KOH$$ and
A
any primary amine and chloroform
B
chloroform and silver powder
C
a primary amine and an alkyl halide
D
a mono alkyl amine and trichloromethane
Answer :
any primary amine and chloroform
Aliphatic and aromatic primary amines when warmed with chloroform and an alcoholic solution of $$KOH,$$ form isocyanide or carbylamine which has very unpleasant smell.
\[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}+CHC{{l}_{3}}+3KOH\xrightarrow{\text{warm}}C{{H}_{3}}C{{H}_{2}}NC+3KCl+3{{H}_{2}}O\]
279.
The decomposition of organic compounds, in the presence of oxygen and without the
development of odoriferous substances, is called
A
decay
B
$${N_2}$$ - fixation
C
nitrification
D
denitrification
Answer :
decay
Decomposition of organic compounds in the presence of oxygen is generally called decay. The remaining three reactions takes place in the presence of bacteria.
280.
Match the column I with column II and mark the appropriate choice.
Column I
Column II
a.
Reaction of benzenediazonium chloride with cuprous salts dissolved in the halogen acid
1.
Sandmeyer reaction
b.
Reacion of benzenediazonium chloride with halogen acid in the presence of copper powder
2.
Gatterman reaction
c.
Reaction of amines with chloroform
3.
Hinsberg's reaction
d.
Reaction of amines with benzenesulphonyl chloride
4.
Carbylamine reaction
A
a - 1, b - 2, c - 3, d - 4
B
a - 4, b - 3, c - 2, d - 1
C
a - 3, b - 4, c - 1, d - 2
D
a - 1, b - 2, c - 4, d - 3
Answer :
a - 1, b - 2, c - 4, d - 3
No explanation is given for this question. Let's discuss the answer together.