Electrochemistry MCQ Questions & Answers in Physical Chemistry | Chemistry

Learn Electrochemistry MCQ questions & answers in Physical Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.

131. $${I_2}\left( s \right)\left| {{I^ - }\left( {0.1\,M} \right)} \right.$$    half cell is connected to a $${H^ + }\left( {aq} \right)\left| {{H_2}\left( {1\,bar} \right)} \right|Pt$$     half cell and $$e.m.f.$$  is found to be $$0.7714\,V.$$  if $$E_{{I_2}\left| {{I^ - }} \right.}^ \circ = 0.535\,V,$$     find the $$pH$$  of $${H^ + }\left| {{H_2}} \right.$$   half-cell.

A 1
B 3
C 5
D 7
Answer :   3

132. The equivalent conductivity of $$\frac{N}{{10}}$$  solution of acetic acid at $${25^ \circ }C$$  is $$14.3\,oh{m^{ - 1}}\,c{m^2}\,equi{v^{ - 1}}.$$     What will be the degree of dissociation of acetic acid?
$$\left( {{ \wedge _{\infty \,\,C{H_3}COOH}} = 390.71\,oh{m^{ - 1}}\,c{m^2}\,equi{v^{ - 1}}} \right)$$

A 3.66 %
B 4.9 %
C 2.12 %
D 0.008 %
Answer :   3.66 %

133. Which of the following reaction is possible at anode?

A $$2C{r^{3 + }} + 7{H_2}O \to C{r_2}{O_7}^{2 - } + 14{H^ + }$$
B $${F_2} \to 2{F^ - }$$
C $$\left( {\frac{1}{2}} \right){O_2} + 2{H^ + } \to {H_2}O$$
D None of these.
Answer :   $$2C{r^{3 + }} + 7{H_2}O \to C{r_2}{O_7}^{2 - } + 14{H^ + }$$

134. The $$e.m.f.$$  of a Daniell cell at $$298\,K$$  is $${E_1}.$$
$$Zn\left| {\mathop {ZnS{O_4}}\limits_{\left( {0.01\,M} \right)} } \right|\left| {\mathop {CuS{O_4}}\limits_{\left( {1.0\,M} \right)} } \right|Cu$$
When the concentration of $${ZnS{O_4}}$$  is $$1.0\,M$$  and that of $${CuS{O_4}}$$  is $$0.01\,M,$$  the $$e.m.f.$$  changed to $${E_2}.$$  What is the relationship between $${E_1}$$  and $${E_2}?$$

A $${E_2} = 0 \ne {E_1}$$
B $${E_1} > {E_2}$$
C $${E_1} < {E_2}$$
D $${E_1} = {E_2}$$
Answer :   $${E_1} > {E_2}$$

135. $${E^ \circ }$$ value of $$\frac{{N{i^{2 + }}}}{{Ni}}$$  is $$ - 0.25\,V$$  and $$\frac{{A{g^ + }}}{{Ag}}$$  is $$ + 0.80\,V.$$  If a cell is made by taking the two electrodes what is the feasibility of the reaction?

A Since $${E^ \circ }$$  value for the cell will be positive, redox reaction is feasible.
B Since $${E^ \circ }$$ value for the cell will be negative, redox reaction is not feasible.
C $$Ni$$  cannot reduce $${A{g^ + }}$$  to $$Ag$$  hence reaction is not feasible.
D $$Ag$$  can reduce $${N{i^{2 + }}}$$ to $$Ni$$  hence reaction is feasible.
Answer :   Since $${E^ \circ }$$  value for the cell will be positive, redox reaction is feasible.

136. Which one of the following pairs of substances on reaction will not evolve $${H_2}$$  gas?

A Iron and $${H_2}S{O_4}\left( {aq} \right)$$
B Iron and steam
C Copper and $$HCl\left( {aq} \right)$$
D Sodium and ethyl alcohol
Answer :   Copper and $$HCl\left( {aq} \right)$$

137. $$\eqalign{ & { \wedge _{ClC{H_2}COONa}} = 224\,oh{m^{ - 1}}\,c{m^2}g\,e{q^{ - 1}}, \cr & { \wedge _{NaCl}} = 38.2\,oh{m^{ - 1}}c{m^2}g\,e{q^{ - 1}}, \cr & { \wedge _{HCl}} = 203\,oh{m^{ - 1}}c{m^2}g\,e{q^{ - 1}}, \cr} $$
What is the value of $${ \wedge _{ClC{H_2}COOH}}$$

A $$288.5\,oh{m^{ - 1}}c{m^2}g\,e{q^{ - 1}}$$
B $$289.5\,oh{m^{ - 1}}c{m^2}g\,e{q^{ - 1}}$$
C $$388.8\,oh{m^{ - 1}}c{m^2}g\,e{q^{ - 1}}$$
D $$59.5\,oh{m^{ - 1}}c{m^2}g\,e{q^{ - 1}}$$
Answer :   $$388.8\,oh{m^{ - 1}}c{m^2}g\,e{q^{ - 1}}$$

138. The Gibbs energy for the decomposition of $$A{{\text{l}}_2}{O_3}$$  at $${500^ \circ }C$$  is as follows :
$$\frac{2}{3}A{{\text{l}}_2}{O_3} \to \frac{4}{3}A{\text{l}} + {O_2},{\Delta _r}G = + 966\,kJ\,mo{l^{ - 1}}$$
The potential difference needed for electrolytic reduction of $$A{{\text{l}}_2}{O_3}$$  at $${500^ \circ }C$$  is at least

A $$4.5 V$$
B $$3.0 V$$
C $$2.5 V$$
D $$5.0 V$$
Answer :   $$2.5 V$$

139. Which of the following is the correct cell representation for the given cell reaction?
$$Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}$$

A $$Zn\left| {Z{n^{2 + }}} \right|\left| {{H^ + }} \right|{H_2}$$
B $$Zn\left| {Z{n^{2 + }}} \right|\left| {{H^ + },{H_2}} \right|Pt$$
C $$Zn\left| {ZnS{O_4}} \right|\left| {{H_2}S{O_4}} \right|Zn$$
D $$Zn\left| {{H_2}S{O_4}} \right|\left| {ZnS{O_4}} \right|{H_2}$$
Answer :   $$Zn\left| {Z{n^{2 + }}} \right|\left| {{H^ + },{H_2}} \right|Pt$$

140. $$HN{O_3}\left( {aq} \right)$$   is titrated with $$NaOH\left( {aq} \right)$$   conductometrically, graphical representation of the titration is :

A Electrochemistry mcq option image
B Electrochemistry mcq option image
C Electrochemistry mcq option image
D Electrochemistry mcq option image
Answer :   Electrochemistry mcq option image