Electromagnetic Induction MCQ Questions & Answers in Electrostatics and Magnetism | Physics
Learn Electromagnetic Induction MCQ questions & answers in Electrostatics and Magnetism are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
121.
A rectangular loop has a sliding connector $$PQ$$ of length $$l$$ and resistance $$R\,\Omega $$ and it is moving with a speed $$v$$ as shown. The set-up is placed in a uniform magnetic field going into the plane of the paper. The three currents $${I_1},{I_2}$$ and $$I$$ are
A
$${I_1} = - {I_2} = \frac{{Blv}}{{6R}},I = \frac{{2Blv}}{{6R}}$$
B
$${I_1} = {I_2} = \frac{{Blv}}{{3R}},I = \frac{{2Blv}}{{3R}}$$
C
$${I_1} = {I_2} = I = \frac{{Blv}}{R}$$
D
$${I_1} = {I_2} = \frac{{Blv}}{{6R}},I = \frac{{Blv}}{{3R}}$$
Due to the movement of resistor $$R,$$ an emf equal to $$Blv$$ will be induced in it as shown in figure clearly,
$$I = {I_1} + {I_2}$$
$${\text{Also,}}\,{I_1} = {I_2}$$
Solving the circuit, we get
$$\eqalign{
& {I_1} = {I_2} = \frac{{Blv}}{{3R}} \cr
& {\text{and}}\,I = 2{I_1} = \frac{{2Blv}}{{3R}} \cr} $$
122.
An inductor $$\left( {L = 0.03H} \right)$$ and a resistor $$\left( {R = 0.15\Omega } \right)$$ are connected in series to a battery of $$15V$$ EMF in a circuit shown below. The key $${K_1}$$ has been kept closed for a long time. Then at $$t = 0,$$ $${K_1}$$ is opened and key $${K_2}$$ is closed simultaneously. At $$t = 1 ms,$$ the current in the circuit will be : $$\left( {{e^5} \cong 150} \right)$$
123.
A horizontal straight wire $$20\,m$$ long extending from east to west falling with a speed of $$5.0\,m/s,$$ at right angles to the horizontal component of the earth’s magnetic field $$0.30 \times {10^{ - 4}}\,Wb/{m^2}.$$ The instantaneous value of the e.m.f. induced in the wire will be
124.
A conducting square frame of side $$'a'$$ and a long straight wire carrying current $$I$$ are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity $$'v'.$$ The emf induced in the frame will be proportional to
A
$$\frac{1}{{{x^2}}}$$
B
$$\frac{1}{{{{\left( {2x - a} \right)}^2}}}$$
C
$$\frac{1}{{{{\left( {2x + a} \right)}^2}}}$$
D
$$\frac{1}{{\left( {2x - a} \right)\left( {2x + a} \right)}}$$
Potential difference across $$PQ$$ is
$${V_P} - {V_Q} = {B_1}\left( a \right)v = \frac{{{\mu _0}I}}{{2\pi \left( {x - \frac{a}{2}} \right)}}av$$
Potential difference across side $$RS$$ of frame is
$${V_S} - {V_R} = {B_2}\left( a \right)v = \frac{{{\mu _0}I}}{{2\pi \left( {x + \frac{a}{2}} \right)}}av$$
Hence, the net potential difference in the loop will be
$${V_{{\text{net}}}} = \left( {{V_P} - {V_Q}} \right) - \left( {{V_S} - {V_R}} \right)$$
$$\eqalign{
& = \frac{{{\mu _0}iav}}{{2\pi }}\left[ {\frac{1}{{\left( {x - \frac{a}{2}} \right)}} - \frac{1}{{\left( {x + \frac{a}{2}} \right)}}} \right] \cr
& = \frac{{{\mu _0}iav}}{{2\pi }}\left( {\frac{a}{{\left( {x - \frac{a}{2}} \right)\left( {x + \frac{a}{2}} \right)}}} \right) \cr} $$
Thus, $${V_{{\text{net}}}} \propto \frac{1}{{\left( {2x - a} \right)\left( {2x + a} \right)}}$$
125.
A cylindrical region of radius $$1\,m$$ has instantaneous homogenous magnetic field of $$5T$$ and it is increasing at a rate of $$2T/s.$$ A regular hexagonal loop $$ABCDEFA$$ of side $$1\,m$$ is being drawn in to the region with a constant speed of $$1\,m/s$$ as shown in the figure. What is the magnitude of emf developed in the loop just after the shown instant when the corner $$A$$ of the hexagon is coinciding with the centre of the circle ?
A
$$\frac{5}{{\sqrt 3 }}V$$
B
$$\frac{{2\pi }}{3}V$$
C
$$\left( {5\sqrt 3 + \frac{{2\pi }}{3}} \right)V$$
The induced emf across the ends $$B$$ and $$F$$ due to motion of the loop,
$${e_1} = Bv\left( {BF} \right) = 5 \times 1 \times 2\sin {60^ \circ } = 5\sqrt 3 \,V.$$
The induced emf across the loop due to change in magnetic field
$$\eqalign{
& {e_2} = A\frac{{dB}}{{dt}} = \frac{{\pi {R^2}}}{3}\left( {\frac{{dB}}{{dt}}} \right) = \frac{{\pi {{\left( 1 \right)}^2}}}{3} \times 2 = \frac{{2\pi }}{3}V. \cr
& {\text{So}}\,\,e = {e_1} + {e_2} = \left( {5\sqrt 3 + \frac{{2\pi }}{3}} \right)V. \cr} $$
126.
A small square loop of wire of side $$\ell $$ is placed inside a large square loop of wire of side $$L\left( {L > \ell } \right).$$ The loop are coplanar and their centre coincide. The mutual inductance of the system is proportional to
A
$$\frac{\ell }{L}$$
B
$$\frac{{{\ell ^2}}}{L}$$
C
$$\frac{L}{\ell }$$
D
$$\frac{{{L^2}}}{\ell }$$
Answer :
$$\frac{{{\ell ^2}}}{L}$$
$${\phi _{{\text{total}}}} = {B_{{\text{large}}}}{A_{{\text{small}}}} = \frac{{{\mu _0}}}{{4\pi }}\frac{i}{{\frac{L}{2}}}\left( {2\sin {{45}^ \circ }} \right) \times {\ell ^2}$$
On comparing with $${\phi _{{\text{total}}}} = Mi,$$ we get $$M \propto \frac{{{\ell ^2}}}{L}$$
127.
A thin circular ring of area $$A$$ is perpendicular to uniform magnetic field of induction $$B.$$ A small cut is made in the ring and a galvanometer is connected across the ends such that the total resistance of circuit is $$R.$$ When the ring is suddenly squeezed to zero area, the charge flowing through the galvanometer is
128.
The back e.m.f. in a $$d.c.$$ motor is maximum, when
A
the motor has picked up max speed
B
the motor has just started moving
C
the speed of motor is still on the increase
D
the motor has just been switched off
Answer :
the motor has picked up max speed
The back e.m.f. in a motor is induced e.m.f., which is maximum, when speed of rotation of the coil is maximum.
129.
A wire is bent to form the double loop shown in Fig. There is a uniform magnetic field directed into the plane of the loop. If the magnitude of this field is decreasing, the current will flow from
A
$$a$$ to $$b$$ and $$c$$ to $$d$$
B
$$b$$ to $$a$$ and $$d$$ to $$c$$
C
$$a$$ to $$b$$ and $$d$$ to $$c$$
D
$$b$$ to $$a$$ and $$c$$ to $$d$$
Answer :
$$a$$ to $$b$$ and $$d$$ to $$c$$
By Lenz's law, clockwise current is induced in both loops. Greater the area, large will be the induced emf. Outer loop has greater area.
130.
Two coils, one primary of $$500$$ turns and one secondary of $$25$$ turns, are wound on an iron ring of mean diameter $$20\,cm$$ and cross-sectional area $$12\,c{m^2}.$$ If the permeability of iron is $$800,$$ the mutual inductance is :