Semiconductors and Electronic Devices MCQ Questions & Answers in Modern Physics | Physics
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131.
The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than $$2480\,nm$$ is incident on it. The band gap in $$\left( {eV} \right)$$ for the semiconductor is
A
$$2.5\,eV$$
B
$$1.1\,eV$$
C
$$0.7\,eV$$
D
$$0.5\,eV$$
Answer :
$$0.5\,eV$$
Band gap = energy of photon of wavelength $$2480\,nm.$$ So,
$$\eqalign{
& \Delta E = \frac{{hc}}{\lambda } = \left( {\frac{{6.63 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{2480 \times {{10}^{ - 9}}}}} \right) \times \frac{1}{{1.6 \times {{10}^{ - 19}}}}eV \cr
& = 0.5\,eV \cr} $$
132.
Which of the following gates corresponds to the truth table given below?
Inputs
Output
A
B
Y
1
1
0
1
0
1
0
1
1
0
0
1
A
NAND
B
OR
C
AND
D
XOR
Answer :
NAND
Truth table for NAND gate is developed by inverting the outputs of the AND gate with NOT gate. Output from a NAND gate is always 1 except when all the inputs are 1. Diagrametic representation of NAND gate is
133.
In the energy band diagram of a material shown below, the open circles and filled circles denote holes and electrons respectively. The material is a/an
A
$$p$$-type semiconductor
B
insulator
C
metal
D
$$n$$-type semiconductor
Answer :
$$p$$-type semiconductor
Since in the given diagram. we see that there are more number of holes so it is $$'p'$$ type semiconductor.
134.
If a small amount of antimony is added to germanium crystal
A
the antimony becomes an acceptor atom
B
there will be more free electrons than holes in the semiconductor
C
its resistance is increased
D
it becomes a $$p$$-type semiconductor
Answer :
there will be more free electrons than holes in the semiconductor
When a small amount of antimony is added to germanium crystal, the crystal becomes $$n$$-type semiconductor, because antimoney is a pentavalent substrate.
135.
Symbolic representation of four logic gates are shown as
Pick out which ones are for AND, NAND and NOT gates, respectively.
A
(iii), (ii) and (i)
B
(iii), (ii) and (iv)
C
(ii), (iv) and (iii)
D
(ii), (iii) and (iv)
Answer :
(ii), (iv) and (iii)
The symbols given in problem are
(i) OR (ii) AND (iii) NOT (iv) NAND
136.
The current voltage relation of a diode is given by $$I = \left( {{e^{1000V/T}} - 1} \right)mA,$$ where the applied voltage $$V$$ is in volts and the temperature $$T$$ is in degree kelvin. If a student makes an error measuring $$ \pm 0.01\,V$$ while measuring the current of $$5\,mA$$ at $$300\,K,$$ what will be the error in the value of current in $$mA$$ ?
A
$$0.2\,mA$$
B
$$0.02\,mA$$
C
$$0.5\,mA$$
D
$$0.05\,mA$$
Answer :
$$0.2\,mA$$
The current voltage relation of diode is
$$\eqalign{
& I = \left( {{e^{1000\frac{V}{T}}} - 1} \right)mA\,\left( {{\text{given}}} \right) \cr
& {\text{When, }}I = 5\;mA,{e^{^{1000\frac{V}{T}}}} = 6\;mA \cr
& {\text{Also, }}dI = \left( {{e^{^{1000\frac{V}{T}}}}} \right) \times \frac{{1000}}{T}\,\,\,\,\left( {{\text{By exponential function}}} \right) \cr
& = \left( {6\;mA} \right) \times \frac{{1000}}{{300}} \times \left( {0.01} \right) \cr
& = 0.2\;mA \cr} $$
137.
The plate resistance of a triode is $$3 \times {10^3}ohms$$ and its mutual conductance is $$1.5 \times {10^{ - 3}}amp/volt.$$ The amplification factor of the triode is
138.
A working transistor with its three legs marked $$P, Q$$ and $$R$$ is tested using a multimeter. No conduction is found between $$P$$ and $$Q.$$ By connecting the common (negative) terminal of the multimeter to $$R$$ and the other (positive) terminal to $$P$$ or $$Q,$$ some resistance is seen on the multimeter. Which of the following is true for the transistor?
A
It is an npn transistor with $$R$$ as base
B
It is a pnp transistor with $$R$$ as collector
C
It is a pnp transistor with $$R$$ as emitter
D
It is an npn transistor with $$R$$ as collector
Answer :
It is an npn transistor with $$R$$ as base
It is a $$n-p-n$$ transistor with $$R$$ as base.
139.
In a triode, $${g_m} = 2 \times {10^{ - 3}}oh{m^{ - 1}};\mu = 42;$$ resistance of load, $$R = 50\,kilo\,ohm.$$ The voltage amplification obtained from this triode will be
140.
This question has Statement - 1 and Statement - 2. Of the
four choices given after the statements, choose the one
that best describes the two statements. Statement - 1 : Sky wave signals are used for long distance radio communication. These signals are in general, less stable than ground wave signals. Statement - 2 : The state of ionosphere varies from hour to hour, day to day and season to season.
A
Statement - 1 is true, Statement - 2 is true, Statement - 2 is the correct explanation of Statement - 1.
B
Statement - 1 is true, Statement - 2 is true, Statement - 2 is not the correct explanation of Statement - 1.
C
Statement - 1 is false, Statement - 2 is true.
D
Statement - 1 is true, Statement - 2 is false.
Answer :
Statement - 1 is true, Statement - 2 is true, Statement - 2 is not the correct explanation of Statement - 1.
For long distance communication, sky wave signals are used.
Also, the state of ionosphere varies every time. So, both statements are correct.