Semiconductors and Electronic Devices MCQ Questions & Answers in Modern Physics | Physics
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61.
A piece of copper and another of germanium are cooled from room temperature to $$77K,$$ the resistance of
A
copper increases and germanium decreases
B
each of them decreases
C
each of them increases
D
copper decreases and germanium increases
Answer :
copper decreases and germanium increases
Copper is a conductor, so its resistance decreases on decreasing temperature as thermal agitation decreases,; whereas germanium is semiconductor therefore on decreasing temperature resistance increases.
62.
The following truth table corresponds to the local gate
Inputs
Output
A
B
Y
0
0
0
0
1
1
1
0
1
1
1
1
A
NAND
B
OR
C
AND
D
XOR
Answer :
OR
It is clear from the truth table that the output is high if any or all of the inputs are high. The only way to get a low output is by having all inputs low. The output Y of an OR gate is low when all inputs are low. The output Y of an OR gate is high, if any or all the inputs are high. So this truth table is of OR gate.
63.
In forward biasing of the $$p-n$$ junction
A
the positive terminal of the battery is connected to $$n$$-side and the depletion region becomes thin
B
the positive terminal of the battery is connected to $$n$$-side and the depletion region becomes thick
C
the positive terminal of the battery is connected to $$p$$-side and the deplection region become thin
D
the positive terminal of the battery is connected to $$p$$-side and the depletion region becomes thick
Answer :
the positive terminal of the battery is connected to $$p$$-side and the deplection region become thin
In forward biasing of $$p-n$$ junction, the positive terminal of the battery is connected to $$p$$-side and the deplection region becomes thin.
64.
A radar has a power of $$1kW$$ and is operating at a frequency of $$10\,GHz.$$ It is located on a mountain top of height $$500\,m.$$ The maximum distance upto which it can detect object located on the surface of the earth (Radius of earth = $$6.4 \times {10^6}m$$ ) is:
A
$$80\,km$$
B
$$16\,km$$
C
$$40\,km$$
D
$$64\,km$$
Answer :
$$80\,km$$
Let $$d$$ is the maximum distance, upto it the objects
From $$\Delta AOC$$
$$\eqalign{
& O{C^2} = A{C^2} + A{O^2} \cr
& {\left( {h + R} \right)^2} = {d^2} + {R^2} \cr
& \Rightarrow {d^2} = {\left( {h + R} \right)^2} - {R^2} \cr
& d = \sqrt {{{\left( {h + R} \right)}^2} - {R^2}} \cr
& d = \sqrt {{h^2} + 2hR} \cr
& d = \sqrt {{{500}^2} + 2 \times 6.4 \times {{10}^6}} = 80\,km \cr} $$
65.
A transistor has $$\beta = 40.$$ A change in base current of $$100\,\mu A,$$ produces change in collector current
A
$$40 \times 100\,{\text{microampere}}$$
B
$$\left( {100 - 40} \right)\,{\text{microampere}}$$
C
$$\left( {100 + 40} \right)\,{\text{microampere}}$$
In cubic crystals, the crystal axes are perpendicular to one another $$\left( {\alpha = \beta = \gamma = {{90}^ \circ }} \right)$$ and the repetitive interval is the same along the three axes $$\left( {a = b = c} \right).$$
67.
If a full wave rectifier circuit is operating from $$50\,Hz$$ mains, the fundamental frequency in the ripple will be
68.
By increasing the temperature, the specific resistance of a conductor and a semiconductor
A
increases for both
B
decreases for both
C
increases, decreases
D
decreases, increases
Answer :
increases, decreases
The resistivity of conductor increases with increase in temperature. The resistivity of semiconductor decreases as the temperature increases.
69.
A full-wave rectifier circuit along with the out-put is shown in Figure. The contribution $$\left( s \right)$$ from the diode 1 is (are)
A
$$C$$
B
$$A,C$$
C
$$B,D$$
D
$$A,B,C,D$$
Answer :
$$A,C$$
As shown in the fig. (i) during one half cycle the polarity
of $$P$$ and $$S$$ are opposite such that diode (1) is reversed biased and hence non conducting.
During the other half cycle, diode (1) gets forward
biased and is conducting. Thus diode (1) conducts in
one half cycle and does not conduct in the other so the
correct option is (B) (A and C.)
70.
A transistor is operated in common emitter configuration at $${V_C} = 2\,V$$ such that a change in the base current from $$100\,\mu A$$ to $$300\,\mu A$$ produces a change in the collector current from $$10\,mA$$ to $$20\,mA.$$ The current gain is
A
50
B
75
C
100
D
25
Answer :
50
The current gain
$$\beta = \frac{{\Delta {I_C}}}{{\Delta {I_B}}} = \frac{{10\,mA}}{{200\,\mu A}} = \frac{{10 \times {{10}^3}}}{{200}} = 50$$