Chemical Bonding and Molecular Structure MCQ Questions & Answers in Inorganic Chemistry | Chemistry
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261.
Which of the following statements is not true?
A
Ionic bonds are non-directional while covalent bonds are directional.
B
Formation of $$\pi $$ - bond shortens the distance between the two concerned atoms.
C
Ionic bond is possible between similar and dissimilar atoms.
D
Linear overlapping of atomic $$p$$ - orbitals leads to a sigma bond.
Answer :
Ionic bond is possible between similar and dissimilar atoms.
Ionic bond cannot be formed between two similar atoms.
262.
Hydrogen bond between two atoms is formed due to
A
displacement of electrons towards more electronegative atom resulting in fractional positive charge on hydrogen
B
displacement of electrons towards hydrogen atom resulting in a polar molecule
C
formation of a bond between hydrogen atoms of one molecule and the other
D
existence of an attractive force which binds hydrogen atoms together
Answer :
displacement of electrons towards more electronegative atom resulting in fractional positive charge on hydrogen
No explanation is given for this question. Let's discuss the answer together.
263.
Which one of the following has the regular tetrahedral structure ?
( Atomic nos. : $$B = 5,S = 16,Ni = 28,Xe = 54$$ )
A
$$BF_4^ - $$
B
$$S{F_4}$$
C
$$Xe{F_4}$$
D
$${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$
264.
Which of the following two are isostructural?
A
$$Xe{F_2},\,{\text{and}}\,IF_2^ - $$
B
$$N{H_3},\,{\text{and}}\,B{F_3}$$
C
$$CO_3^{2 - },\,{\text{and}}\,SO_3^{2 - }$$
D
$$PC{l_5},\,{\text{and}}\,IC{l_5}$$
Answer :
$$Xe{F_2},\,{\text{and}}\,IF_2^ - $$
Compounds having same structure and same hybridisation are known as isostructural species. e.g. $$Xe{F_2}$$ and $$IF_2^ - $$ are $$s{p^3}d$$ hybridised and both have linear shape.
$$F - {I^ - } - F\,\,\,\,\,\,\,\,F - Xe - F$$
265.
The bond order in $$NO\,\,{\text{is}}\,\,2.5$$ while that in $$N{O^ + }\,\,{\text{is}}\,\,3$$ . Which of the following statements is true for these two species ?
A
Bond length in $$N{O^ + }\,\,{\text{is}}$$ equal to that in $$NO$$
B
Bond length in $$NO\,$$ is greater than in $$N{O^ + }$$
C
Bond length in $$N{O^ + }$$ is greater than in $$\,NO\,$$
D
Bond length is unpredictable
Answer :
Bond length in $$NO\,$$ is greater than in $$N{O^ + }$$
Now since bond order of $$N{O^ + }\,$$ given (3) is higher than that of $$\,NO$$ $$(\,2.5\,)$$ . Thus bond length of $$N{O^ + }$$ will be shorter.
266.
According to $$VSEPR$$ theory,
A
the shape of the molecule depends upon the bonded electron pairs
B
pair of electrons attract each other in valence shells
C
the pairs of electrons tend to occupy such positions that minimise repulsions
D
the pairs of electrons tend to occupy such positions that minimise distances from each other
Answer :
the pairs of electrons tend to occupy such positions that minimise repulsions
The pairs of electrons tend to occupy such positions that place them farthest from each other and minimise repulsions.
267.
The ion that is isoelectronic with $$CO$$ is
A
$$O_2^ - $$
B
$$N_2^ + $$
C
$$O_2^ + $$
D
$$C{N^ - }$$
Answer :
$$C{N^ - }$$
Isoelectronic species are having same number of electrons.
Number of electrons in $$CO = 6 + 8 = 14$$
Number of electrons in $$O_2^ - = 16 + 1 = 17$$
Number of electrons in $$N_2^ + = 14 - 1 = 13$$
Number of electrons in $$O_2^ + = 16 - 1 = 15$$
Number of electrons in $$C{N^ - } = 6 + 7 + 1 = 14$$
Hence, $$CO$$ isoelectronic with $$C{N^ - }$$ ion.
268.
The types of hybrid orbitals of nitrogen in $$NO_2^ + ,NO_3^ - $$ and $$NH_4^ + $$ respectively are expected to be
A
$$sp,s{p^3}\,{\text{and}}\,s{p^2}$$
B
$$sp,s{p^2}\,{\text{and}}\,s{p^3}$$
C
$$s{p^2},sp\,{\text{and}}\,s{p^3}$$
D
$$s{p^2},s{p^3}\,{\text{and}}\,sp$$
Answer :
$$sp,s{p^2}\,{\text{and}}\,s{p^3}$$
$$X = \frac{1}{2}\left( {VE + MA - c + a} \right)$$
where, $$VE =$$ No. of valence electrons on the central atom.
$$MA =$$ No. of monovalent atoms surrounding the central atom.
$$c =$$ Charge on the cation; $$a =$$ Charge on the anion
$${\text{For}}\,NO_2^ + ,X = \frac{1}{2}\left( {5 + 0 - 1} \right) = 2$$ $$\left( {sp\,{\text{hybrid orbitals}}} \right)$$
$${\text{For}}\,NO_3^ - ,X = \frac{1}{2}\left( {5 + 0 + 1} \right) = 3$$ $$\left( {s{p^2}{\text{hybrid orbitals}}} \right)$$
$${\text{For}}\,NH_4^ + ,X = \frac{1}{2}\left( {5 + 4 - 1} \right) = 4$$ $$\left( {s{p^3}\,{\text{hybrid orbitals}}} \right)$$
269.
Which species has the maximum number of lone pair of electrons on the central atom?
A
$${\left[ {Cl{O_3}} \right]^ - }$$
B
$$Xe{F_4}$$
C
$$S{F_4}$$
D
$${\left[ {{I_3}} \right]^ - }$$
Answer :
$${\left[ {{I_3}} \right]^ - }$$
270.
Which of the following represents the given mode of hybridisation $$s{p^2} - s{p^2} - sp - sp$$ from left to right ?