Co - ordination Compounds MCQ Questions & Answers in Inorganic Chemistry | Chemistry

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101. Out of $$TiF_6^{2 - },CoF_6^{3 - },C{u_2}C{l_2}$$      and $$NiCl_4^{2 - }$$  $$\left( {{\text{At}}.\,{\text{no}}{\text{.}}\,\,Z\,\,{\text{of}}\,\,Ti = 22,Co = 27,} \right.$$      $$\left. {Cu = 29,Ni = 28} \right),$$     the colourless species are

A $$TiF_6^{2 - }\,{\text{and}}\,CoF_6^{3 - }$$
B $$C{u_2}C{l_2}\,{\text{and}}\,NiCl_4^{2 - }$$
C $$TiF_6^{2 - }\,{\text{and}}\,C{u_2}C{l_2}$$
D $$CoF_6^{3 - }\,{\text{and}}\,NiCl_4^{2 - }$$
Answer :   $$TiF_6^{2 - }\,{\text{and}}\,C{u_2}C{l_2}$$

102. $$\left[ {Cr{{\left( {{H_2}O} \right)}_6}} \right]C{l_3}$$    ( at. no. of $$Cr =$$  24 ) has a magnetic moment of $$3.83\,B.M.$$   The correct distribution of $$3d$$  electrons in the chromium present in the complex is

A $$3{d_{xy}},3{d_{yz}},3{d_{zx}}$$
B $$3{d_{xy}},3{d_{yz}},3{d_{{z^2}}}$$
C $$3{d_{\left( {{x^2} - {y^2}} \right)}},3{d_{{z^2}}},3{d_{xz}}$$
D $$3{d_{xy}},3{d_{\left( {{x^2} - {y^2}} \right)}},3{d_{yz}}$$
Answer :   $$3{d_{xy}},3{d_{yz}},3{d_{zx}}$$

103. Mark the incorrect match.

A Insulin - Zinc
B Haemoglobin - Iron
C Vitamin $${B_{12}}$$  - Cobalt
D Chlorophyll - Chromium
Answer :   Chlorophyll - Chromium

104. The terminal and bridged $$CO$$  ligands in the compound $$\left[ {C{o_2}{{\left( {CO} \right)}_8}} \right]$$   are respectively

A 0, 2
B 6, 1
C 5, 2
D 6, 2
Answer :   6, 2

105. Nickel $$(Z = 28)$$  combines with a uninegative monodentate ligand to form a diamagnetic complex $${\left[ {Ni{L_4}} \right]^{2 - }}.$$  The hybridisation involved and the number of unpaired electrons present in the complex are respectively :

A $$s{p^3},{\text{two}}$$
B $$ds{p^2},{\text{zero}}$$
C $$ds{p^2},{\text{one}}$$
D $$s{p^3},{\text{zero}}$$
Answer :   $$s{p^3},{\text{two}}$$

106. Among $$\left[ {Ni{{\left( {CO} \right)}_4}} \right],{\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }},{\left[ {NiC{l_4}} \right]^{2 - }}$$       species, the hybridisation states of the $$Ni$$  atom are, respectively ( At. no. of $$Ni= 28$$  )

A $$s{p^3},ds{p^2},ds{p^2}$$
B $$s{p^3},ds{p^2},s{p^3}$$
C $$s{p^3},s{p^3},ds{p^2}$$
D $$ds{p^2},s{p^3},s{p^3}$$
Answer :   $$s{p^3},ds{p^2},s{p^3}$$

107. Which one of the following complexes will have four isomers?

A $$\left[ {Co{{\left( {en} \right)}_3}} \right]C{l_3}$$
B $$\left[ {Co{{\left( {PP{h_3}} \right)}_2}{{\left( {N{H_3}} \right)}_2}C{l_2}} \right]$$
C $$\left[ {Co\left( {en} \right){{\left( {N{H_3}} \right)}_2}C{l_2}} \right]Cl$$
D $$\left[ {Co{{\left( {en} \right)}_2}C{l_2}} \right]Br$$
Answer :   $$\left[ {Co{{\left( {en} \right)}_2}C{l_2}} \right]Br$$

108. The complex ion which has no $$d$$ - electrons in the central metal atom is

A $${\left[ {Mn{O_4}} \right]^ - }$$
B $${\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}$$
C $${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }}$$
D $${\left[ {Cr{{\left( {{H_2}O} \right)}_6}} \right]^{3 + }}$$
Answer :   $${\left[ {Mn{O_4}} \right]^ - }$$

109. Which of the following complexes formed by $$C{u^{2 + }}$$  ions is most stable?

A $$C{u^{2 + }} + 4N{H_3} \rightleftharpoons {\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]^{2 + }},$$       $$\log \,K = 11.6$$
B $$C{u^{2 + }} + 4C{N^ - } \rightleftharpoons {\left[ {Cu{{\left( {CN} \right)}_4}} \right]^{2 - }},$$       $$\log \,K = 27.3$$
C $$C{u^{2 + }} + 2en \rightleftharpoons {\left[ {Cu{{\left( {en} \right)}_2}} \right]^{2 + }},$$       $$\log \,K = 15.4$$
D $$C{u^{2 + }} + 4{H_2}O \rightleftharpoons {\left[ {Cu{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }},$$       $$\log \,K = 8.9$$
Answer :   $$C{u^{2 + }} + 4C{N^ - } \rightleftharpoons {\left[ {Cu{{\left( {CN} \right)}_4}} \right]^{2 - }},$$       $$\log \,K = 27.3$$

110. The most stable ion is

A $${\left[ {Fe{{\left( {OH} \right)}_3}} \right]^{3 - }}$$
B $${\left[ {Fe{{\left( {Cl} \right)}_6}} \right]^{3 - }}$$
C $${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }}$$
D $${\left[ {Fe{{\left( {{H_2}O} \right)}_6}} \right]^{3 + }}$$
Answer :   $${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }}$$