P - Block Elements MCQ Questions & Answers in Inorganic Chemistry | Chemistry
Learn P - Block Elements MCQ questions & answers in Inorganic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
251.
An element of group 14 forms two oxides one of which is highly poisonous and neutral. Other oxide can be easily liquefied and compressed to give a
solid which is used as a refrigerant under the name of drikold. The element and the oxides are
A
$$Si,SiO,Si{O_2}$$
B
$$Pb,PbO,Pb{O_2}$$
C
$$C,CO,C{O_2}$$
D
$$Sn,SnO,Sn{O_2}$$
Answer :
$$C,CO,C{O_2}$$
$$C$$ forms two oxides $$CO$$ and $$C{O_2}.$$ $$CO$$ is neutral and poisonous. $$C{O_2}$$ can be compressed as a refrigerant dry ice or solid $$C{O_2}.$$ $$SiO$$ is unstable. $$SnO$$ and $$PbO$$ are amphoteric in nature.
252.
Catenation i.e., linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order
A
$$C > Si > Ge > Sn$$
B
$$C > > Si > Ge \approx Sn$$
C
$$Si > C > Sn > Ge$$
D
$$Ge> Sn > Si > C$$
Answer :
$$C > > Si > Ge \approx Sn$$
As we go down the group, the atomic size increases and electronegativity decreases and thereby, tendency to show catenation decreases. Hence, the order of catenation is $$C > > Si > Ge \approx Sn.$$
253.
Match the column I with column II and mark the appropriate choice.
Column I
Column II
a.
$$Cl{F_3}$$
1.
Pentagonal bipyramidal
b.
$$I{F_5}$$
2.
Square pyramidal
c.
$$I{F_7}$$
3.
Bent T-shaped
d.
$$BrF$$
4.
Linear
A
a - 3, b - 1, c - 4, d - 2
B
a - 1, b - 2, c - 3, d - 4
C
a - 2, b - 4, c - 3, d - 1
D
a - 3, b - 2, c - 1, d - 4
Answer :
a - 3, b - 2, c - 1, d - 4
No explanation is given for this question. Let's discuss the answer together.
254.
Boric acid is an acid because its molecule
A
contains replaceable $${H^ + }$$ ion
B
gives up a proton
C
accepts $$O{H^ - }$$ from water releasing proton
D
combines with proton from water molecule
Answer :
accepts $$O{H^ - }$$ from water releasing proton
No explanation is given for this question. Let's discuss the answer together.
255.
Which of the following statements regarding sulphur is incorrect?
A
$${S_2}$$ molecule is paramagnetic.
B
The vapour at $${200^ \circ }C$$ consists mostly of $${{\text{S}}_8}$$ rings.
C
At $${600^ \circ }C$$ the gas mainly consists of $${S_2}$$ molecules.
D
The oxidation state of sulphur is never less than $$ + 4$$ in
its compounds.
Answer :
The oxidation state of sulphur is never less than $$ + 4$$ in
its compounds.
Oxidation of sulphur varies from $$ - 2\,{\text{to}}\, + 6$$ in its various compounds.
256.
$$FeC{l_3}$$ solution on reaction with $$S{O_2}$$ changes to
258.
In $$B{X_3},B - X$$ distance is shorter than what is expected theoretically because $$\left( {X = F,Cl , Br,I} \right)$$
A
$$s{p^3}$$ hybridisation of $$B$$ is responsible for shorter $$B - X$$ distance.
B
$$B - X$$ has a double bond character due to back - bonding.
C
Dimerisation takes place in $$B{X_3}$$ which is responsible for shorter $$B - X$$ distance.
D
Due to large size of $$X, B - X$$ distance decreases
Answer :
$$B - X$$ has a double bond character due to back - bonding.
Due to back - bonding, $$B - X$$ in $$B{X_3}$$ has double bond character which because of resonance results in shorter $$B - X$$ distance.
259.
Which one of the following arrangements represents the correct order of electron gain enthalpy ( with negative sign ) of the given atomic species ?
A
$$Cl < F < S < O$$
B
$$O < S < F < Cl$$
C
$$S < O < Cl < F$$
D
$$F < Cl < O < S$$
Answer :
$$O < S < F < Cl$$
The correct order of electron gain enthalpy or (electron affinity) is
$$O < S < F < Cl$$
( Value of electron affinity in $$eV$$ ) 1.48 2.07 3.45 3.61
260.
The incorrect statement regarding above reactions is :