S - Block Elements MCQ Questions & Answers in Inorganic Chemistry | Chemistry
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91.
A chloride dissolves appreciably in cold water. When placed on a $$Pt$$ wire in bunsen flame, no distinctive colour is noted. Which cation could be present ?
A
$$B{e^{2 + }}$$
B
$$B{a^{2 + }}$$
C
$$P{b^{2 + }}$$
D
$$C{a^{2 + }}$$
Answer :
$$B{e^{2 + }}$$
Due to very high $$I.E.$$ of $$Be,$$ its valence electrons require high energy to remove (excite) which is not available in bunsen flame hence $$B{e^{2 + }}\,ions$$ do not impart colour to the flame.
92.
Which one of the following atoms will have the smallest size ?
A
$$Mg$$
B
$$Na$$
C
$$Be$$
D
$$Li$$
Answer :
$$Be$$
Atomic size increases down the group and decreases in period from left to right. So, $$Be$$ is smallest in size in these elements.
93.
$$BeO$$ is insoluble but $$BaO$$ is soluble as
A
lattice energy of $$BeO$$ is higher than $$BaO$$ due to small size of $$B{e^{2 + }}$$ ion and its covalent nature
B
hydration energy of $$BeO$$ is lower than $$BaO$$ due to small size $$B{e^{2 + }}$$ ion
C
$$BeO$$ is amphoteric in nature while $$BaO$$ is basic
D
$$BeO$$ forms hydrated salts while $$BaO$$ forms anhydrous salts
Answer :
lattice energy of $$BeO$$ is higher than $$BaO$$ due to small size of $$B{e^{2 + }}$$ ion and its covalent nature
The lattice energy of $$BeO$$ is higher than $$BaO$$ due to small size of $$B{e^{2 + }}$$ ion. $$BeO$$ is covalent while $$BaO$$ is ionic in nature.
94.
Which of the following atoms has the highest first ionization energy?
A
$$K$$
B
$$Sc$$
C
$$Rb$$
D
$$Na$$
Answer :
$$Sc$$
Alkali metals have the lowest ionization energy in each period on the other hand $$Sc$$ is a $$d$$ - block element. Transition metals have smaller atomic radii and higher nuclear charge leading to high ionisation energy.
95.
Which of the following statements is correct ?
A
Sodium carbonate decomposes on heating.
B
Sodium bicarbonate is more soluble in water than potassium bicarbonate.
C
Sodium when heated with excess of $${O_2},$$ gives peroxide.
D
Lithium halides are highly ionic in nature.
Answer :
Sodium when heated with excess of $${O_2},$$ gives peroxide.
Only (C) is the correct statement, others are incorrect and these are corrected as
(A) Lithium carbonate decomposes on heating.
(B) Potassium bicarbonate is more soluble in water than sodium bicarbonate.
(D) Lithium halides are highly covalent in nature.
96.
$$M{g_2}{C_3}$$ reacts with water forming propyne gas. $$C_3^{4 - }\,ions$$ has :
97.
Fill up the blanks with appropriate choices.
Lithium and magnesium react slowly with water. Their hydroxides are $$\underline {\left( {\text{i}} \right)} $$ soluble in water. Carbonates of $$Li$$ and $$Mg$$ $$\underline {\left( {{\text{ii}}} \right)} $$ easily on heating. Both $$LiCl$$ and $$MgC{l_2}$$ are $$\underline {\left( {{\text{iii}}} \right)} $$ in ethanol and are $$\underline {\left( {{\text{iv}}} \right)} .$$ They crystallise from their aqueous solutions as $$\underline {\left( {\text{v}} \right)} .$$
(i)
(ii)
(iii)
(iv)
(v)
(a)
more
do not decompose
soluble
hygroscopic
hydrates
(b)
less
decompose
soluble
deliquescent
hydrates
(c)
freely
sublime
insoluble
deliquescent
anhydrous
(d)
freely
decompose
soluble
hygroscopic
crystals
A
(a)
B
(b)
C
(c)
D
(d)
Answer :
(b)
No explanation is given for this question. Let's discuss the answer together.
98.
The order of solubility of lithium halides in non polar solvents follows the order
A
$$LiI > LiBr > LiCl > LiF$$
B
$$LiF > LiI > LiBr > LiCl$$
C
$$LiCl > LiF > LiI > LiBr$$
D
$$LiBr > LiCl > LiF > LiI$$
Answer :
$$LiI > LiBr > LiCl > LiF$$
As the size of the anion increases from $${F^ - }$$ to $${I^ - },$$ the covalent character increase and hence the solubility in non -polar solvent increases $$LiI > LiBr > LiCl > LiF$$
99.
Which one of the following properties of alkali metals increases in magnitude as the
atomic number rises ?
A
lonic radius
B
Melting point
C
Electronegativity
D
First ionisation energy
Answer :
lonic radius
The ionic radii of alkali metal increases as the atomic number increases when we move from top to bottom because on moving down the group, there is a increase in the number of shells and therefore, ionic radii increases.
100.
Which one is the correct statement with reference to the solubility of $$MgS{O_4}$$ in water ?
A
$$SO_4^{2 - }\,ions$$ mainly contributes towards hydration energy
B
Sizes of $$M{g^{2 + }}$$ and $$SO_4^{2 - }$$ are similar
C
Hydration energy of $$MgS{O_4}$$ is higher in comparison to its lattice energy
D
lonic potential ( charge/radius ratio ) of $$M{g^{2 + }}$$ is very low
Answer :
Hydration energy of $$MgS{O_4}$$ is higher in comparison to its lattice energy
$$MgS{O_4}$$ is soluble in water because it have hydration energy more than lattice energy.
$$ \bullet M{g^{2 + }}\,ions$$ mainly contributes towards hydration energy
$$ \bullet $$ size of $$SO_4^{2 - }\,ion$$ is greation than $$M{g^{2 + }}\,ions.$$