S - Block Elements MCQ Questions & Answers in Inorganic Chemistry | Chemistry
Learn S - Block Elements MCQ questions & answers in Inorganic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
141.
Which of the carbonates given below is unstable in air and is kept in $$C{O_2}$$ atmosphere to avoid decomposition?
A
$$BeC{O_3}$$
B
$$MgC{O_3}$$
C
$$CaC{O_3}$$
D
$$BaC{O_3}$$
Answer :
$$BeC{O_3}$$
No explanation is given for this question. Let's discuss the answer together.
142.
In crystals which one of the following ionic compounds would you expect maximum distance
between centres of cations and anions?
A
$$LiF$$
B
$$CsF$$
C
$$CsI$$
D
$$LiI$$
Answer :
$$CsI$$
As $$C{s^ + }\,ion$$ has larger size than $$L{i^ + }$$ and $${I^ - }$$ has larger size than $${F^ - },$$ therefore maximum distance between centres of cations and anions is in $$CsI.$$
143.
Beryllium shows diagonal relationship with aluminium. Which of the following similarity is incorrect?
A
$$B{e_2}C$$ like $$A{l_4}{C_3}$$ yields methane on hydrolysis.
B
$$Be$$ like $$Al$$ is rendered passive by $$HN{O_3}.$$
C
$$Be{\left( {OH} \right)_2}$$ like $$Al{\left( {OH} \right)_3}$$ is basic.
D
$$Be$$ forms beryllates and $$Al$$ forms aluminates.
Answer :
$$Be{\left( {OH} \right)_2}$$ like $$Al{\left( {OH} \right)_3}$$ is basic.
Both $$Be{\left( {OH} \right)_2}$$ and $$Al{\left( {OH} \right)_3}$$ are amphoteric in nature.
144.
A solid compound $$'X'$$ on heating gives $$C{O_2}$$ gas and a residue. The residue mixed with water forms $$'Y'.$$ On passing an excess of $$C{O_2}$$ through $$'Y'$$ in water, a clear solution $$'Z',$$ is obtained. On boiling
$$'Z',$$ compound $$'X'$$ is reformed. The compound $$'X'$$ is
A
$$Ca{\left( {HC{O_3}} \right)_2}$$
B
$$CaC{O_3}$$
C
$$N{a_2}C{O_3}$$
D
$${K_2}C{O_3}$$
Answer :
$$CaC{O_3}$$
The given properties coincide with $$CaC{O_3}$$
145.
The formula of soda ash is
A
$$N{a_2}C{O_3} \cdot 10{H_2}O$$
B
$$N{a_2}C{O_3} \cdot 2{H_2}O$$
C
$$N{a_2}C{O_3} \cdot {H_2}O$$
D
$$N{a_2}C{O_3}$$
Answer :
$$N{a_2}C{O_3}$$
No explanation is given for this question. Let's discuss the answer together.
146.
Which is the correct sequence of solubility of carbonates of alkaline earth metals?
Solubility of carbonates decreases on moving down the group as hydration energy decreases.
147.
The pair of compounds which cannot exist together in solution is:
A
$$NaHC{O_3}\,\,{\text{and}}\,NaOH$$
B
$$N{a_2}C{O_3}\,\,{\text{and}}\,NaHC{O_3}$$
C
$$N{a_2}C{O_3}\,\,\operatorname{and} \,NaOH$$
D
$$NaHC{O_3}\,{\text{and}}\,NaCl$$
Answer :
$$NaHC{O_3}\,\,{\text{and}}\,NaOH$$
NOTE: Acidicand basic salts cannot exist together. Since $$NaHC{O_3}$$ is an acid salt of $${H_2}C{O_3},$$ it reacts with $$NaOH$$ to form $$N{a_2}C{O_3}$$ and $$\,{H_2}O.$$
$$NaHC{O_3} + NaOH \to N{a_2}C{O_3} + {H_2}O$$
148.
Which of the following is not the point of difference between $$Be$$ and other alkaline earth metals?
A
It has a tendency to form covalent bonds.
B
It dissolves in alkalies with evolution of hydrogen.
C
Its oxides and hydroxides are amphoteric.
D
Its carbide gives acetylene on hydrolysis.
Answer :
Its carbide gives acetylene on hydrolysis.
$$B{e_2}C$$ gives methane on hydrolysis while other carbides give acetylene.
$$B{e_2}C + 4{H_2}O \to 2Be{\left( {OH} \right)_2} + C{H_4}$$
149.
The ionisation energy of alkali metals decreases from $$Li$$ to $$Cs$$ because
A
the atomic size increases from $$Li$$ to $$Cs$$
B
the distance between nucleus and outermost orbital decreases from $$Li$$ to $$Cs$$
C
electropositive character decreases down the group
D
melting point decreases from $$Li$$ to $$Cs$$
Answer :
the atomic size increases from $$Li$$ to $$Cs$$
Down the group from $$Li$$ to $$Cs,$$ the effect of increasing size outweighs the increasing nuclear charge, and the outermost electron is well screened from the nuclear charge.
150.
A solution of sodium metal in liquid ammonia is strongly reducing due to the presence of
A
sodium atoms
B
sodium hydride
C
sodium amide
D
solvated electrons
Answer :
solvated electrons
The free ammoniated electrons make the solution of $$Na$$ in liquid $$N{H_3}$$ a very powerful reducing agent.
NOTE : The ammonical solution of an alkali metal is rather favoured as a reducing agent than its aqueous solution because in aqueous solution the alkali metal being highly electropositive evolves hydrogen from water (thus $${H_2}O$$ acts as an oxidisng agent) while its solution in ammonia is quite stable, provided no catalyst (transition metal) is present.