Alcohol, Phenol and Ether MCQ Questions & Answers in Organic Chemistry | Chemistry
Learn Alcohol, Phenol and Ether MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
11.
Consider the following reaction,
\[\text{Phenol}\xrightarrow{Zn\,\text{dust}}X\xrightarrow[\text{anhyd}\text{. }AlC{{l}_{3}}]{C{{H}_{3}}Cl}\] \[Y\xrightarrow{\text{ alkaline }KMn{{O}_{4}}}Z\]
The product $$Z$$ is
A
benzaldehyde
B
benzoic acid
C
benzene
D
toluene
Answer :
benzoic acid
12.
Conversion of phenol to salicylic acid and to salicylaldehyde is known as (respectively)
A
Reimer-Tiemann reaction and Kolbe's reaction
B
Williamson's synthesis and Hydroboration-oxidation
C
Kolbe's reaction and Williamson's synthesis
D
Kolbe's reaction and Reimer-Tiemann reaction
Answer :
Kolbe's reaction and Reimer-Tiemann reaction
No explanation is given for this question. Let's discuss the answer together.
13.
Propan-1-$$ol$$ may be prepared by reaction of propene with
A
B
C
D
Answer :
Hydroboration-oxidation reaction
14.
Ethanol can be prepared more easily by which reaction ?
$$\left( {\text{i}} \right)C{H_3}C{H_2}Br + {H_2}O \to $$ $$C{H_3}C{H_2}OH$$
$$\left( {{\text{ii}}} \right)C{H_3}C{H_2}Br + A{g_2}O$$ $$\left( {{\text{in boiling water}}} \right) \to C{H_3}C{H_2}OH$$
A
by (i) reaction
B
by (ii) reaction
C
Both reactions proceed at same rate
D
by none
Answer :
by (ii) reaction
Heavy metal ions, particularly $$A{g^ + },$$ catalyse $${S_N}1$$ reaction because of the presence of empty orbital.
\[C{{H}_{3}}C{{H}_{2}}Br+A{{g}^{+}}\rightleftharpoons {{\left[ C{{H}_{3}}C{{H}_{2}}\cdot \cdot \cdot X\cdot \cdot Ag \right]}^{+}}\xrightarrow[\left( -AgX \right)]{\text{slow}}C{{H}_{3}}CH_{2}^{+}\xrightarrow[\text{from}\,{{H}_{2}}O]{O{{H}^{-}}}C{{H}_{3}}C{{H}_{2}}OH\]
15.
Correct increasing order of acidity is as follows
A
$${H_2}O,{C_2}{H_2},{H_2}C{O_3},{\text{phenol}}$$
B
$${C_2}{H_2},{H_2}O,{H_2}C{O_3},{\text{phenol}}$$
C
$${\text{phenol}},{C_2}{H_2},{H_2}C{O_3},{H_2}O$$
D
$${C_2}{H_2},{H_2}O,{\text{phenol}},{H_2}C{O_3}$$
Such questions can be solved by considering the relative basic character of their conjugated bases which for $${H_2}O,{C_2}{H_2},{H_2}C{O_3}$$ and $${C_6}{H_5}OH$$ are $$^ - OH,HC \equiv C\mathop :\limits^ - ,HCO_3^ - ,{C_6}{H_5}{O^ - }$$
More the possibility for the dispersal of the negative charge, weaker will be the base. Thus the relative basic character of the four bases is
Thus the acidic character of the four corresponding acids will be
\[{{H}_{2}}C{{O}_{3}}>{{C}_{6}}{{H}_{5}}OH>{{H}_{2}}O>HC\equiv CH\]
16.
The enzyme which hydrolysis triglycerides into fatty acids and glycerol is called
A
maltase
B
lipase
C
zymase
D
pepsin
Answer :
lipase
17.
Compound $$(X)$$ is
A
B
C
D
Answer :
18.
2 - chloro - 2 - methylpentane on reaction with sodium methoxidein methanol yields :
A
(3) only
B
(1) and (2)
C
All of these
D
(1) and (3)
Answer :
(3) only
When fert - alkyl halides are used in Williamson synthesis elimination occurs rather than substitution resulting into formation of alkene. Here alkoxide ion
abstract one of the $$\beta - $$ hydrogen atom along with acting as a nucleophile.
19.
The main product of the following reaction is
\[{{C}_{6}}{{H}_{5}}C{{H}_{2}}CH\left( OH \right)CH{{\left( C{{H}_{3}} \right)}_{2}}\xrightarrow{\text{conc}\text{.}\,\,{{H}_{2}}S{{O}_{4}}}?\]
A
B
C
D
Answer :
Whenever dehydration can produce two different alkenes, major product is formed according to Saytzeff rule i.e. more substituted alkene ( alkene having lesser number of hydrogen atoms on the two doubly bonded carbon atoms ) is the major product.
Such reactions which can produce two or more structural isomers but one of them in greater amounts than the other are called regioselective ; in case a
reaction is 100% regioselective, it is termed as regiospecific.
In addition to being regioselective, alcohol dehydrations are stereoselective ( a reaction in which a single starting material can yield two or more stereoisomeric products, but gives one of them in greater amount than any other ).
20.
Correct order of boiling points among following is $$\mathop {C{H_3}{{\left( {C{H_2}} \right)}_3}C{H_3},}\limits_{\left( X \right)} \mathop {{C_2}{H_5}O{C_2}{H_5},}\limits_{\left( Y \right)} $$ $$\mathop {C{H_3}{{\left( {C{H_2}} \right)}_3}OH}\limits_{\left( Z \right)} $$
A
X > Y > Z
B
Y > X > Z
C
Z > X > Y
D
Z > Y > X
Answer :
Z > X > Y
No explanation is given for this question. Let's discuss the answer together.