Aldehyde and Ketone MCQ Questions & Answers in Organic Chemistry | Chemistry
Learn Aldehyde and Ketone MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
11.
Phenol reacts with methyl chloroformate in the presence of $$NaOH$$ to form product $$A.$$ $$A$$ reacts with $$B{r_2}$$ to form product $$B.$$ $$A$$ and $$B$$ are respectively :
A
B
C
D
Answer :
12.
Which one of the following undergoes reaction with 50% sodium hyroxide solution to give the corresponding alcohol and acid?
A
Butanal
B
Benzaldehyde
C
Phenol
D
Benzoic acid
Answer :
Benzaldehyde
This reaction is known as cannizzaro’s reaction. In this reaction benzaldehyde in presence of 50%. $$NaOH$$ undergoes disproportionation reaction and form one mol of Benzyl alcohol (Red. product) and one mole of
sod. benzoate (ox. product)
13.
Which of the following gives ethanal $$C{H_3}CHO$$ on acid hydrolysis ?
A
B
C
D
Answer :
14.
Which one of the following will most readily be dehydrated in acidic condition ?
A
B
C
D
Answer :
Compound (A) undergoes dehydration easily as the product obtained is conjugated and thus more stable.
15.
The addition of $$HCN$$ to carbonyl compounds is an example of
A
nucleophilic addition
B
electrophilic addition
C
free radical addition
D
elimination addition
Answer :
nucleophilic addition
Nucleophile attacks at the positive $$C$$ centre of carbonyl group hence the addition is nucleophilic addition.
16.
The starting compounds needed to make the following compound ?
A
benzaldehyde and 3 - pentanone
B
acetophenone and 2 - butanone
C
acetophenone and butanal
D
benzaldehyde and 2 - pentanone
Answer :
benzaldehyde and 3 - pentanone
17.
Aldol condensation will not take place in
A
$$HCHO$$
B
$$C{H_3}CHO$$
C
$$C{H_3}COC{H_3}$$
D
$$C{H_3}C{H_2}CHO$$
Answer :
$$HCHO$$
Aldol condensation in aldehydes is due to presence of $$\alpha $$ - hydiogen atoms. Those aldehydes which does not have $$\alpha $$ - hydrogen atom like $$HCHO,$$ does not give aldol condensation reaction.
18.
Compounds $$(A)$$ and $$(C)$$ in the following reactions are
\[C{H_3}CHO\xrightarrow[{\left( {{\text{ii}}} \right)\,{H_2}O}]{{\left( {\text{i}} \right)\,C{H_3}MgBr}}\left( A \right)\] \[\xrightarrow{{{H_2}S{O_4},\,\Delta }}\left( B \right)\] \[\xrightarrow{{{\text{Hydroboration oxidation}}}}\left( C \right)\]
A
identical
B
positional isomers
C
functional isomers
D
optical isomers
Answer :
positional isomers
19.
The major product of the following reaction sequence is \[\xrightarrow[\left( \text{ii} \right)\frac{HCHO}{{{H}^{+}}\left( \text{catalytic}\,\,\text{amount} \right)}]{\left( \text{i} \right)\frac{HCHO\,\left( \text{excess} \right)}{NaOH,\,\text{heat}}}\]
A
B
C
D
Answer :
20.
There is a large difference in the boiling points of butanal and butan-1-ol due to
A
intermolecular hydrogen bonding in butan-1-ol
B
intramolecular hydrogen bonding in butanal
C
higher molecular mass of butan-1-ol
D
resonance shown by butanal
Answer :
intermolecular hydrogen bonding in butan-1-ol
No explanation is given for this question. Let's discuss the answer together.