Aldehyde and Ketone MCQ Questions & Answers in Organic Chemistry | Chemistry
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31.
Which one of the following reactions will not result in the formation of carbon-carbon bond ?
A
Reimer-Tieman reaction
B
Friedel Craft’s acylation
C
Wurtz reaction
D
Cannizzaro reaction
Answer :
Cannizzaro reaction
Canizzaro’s reaction is a disproportionation reaction of aldehyde in which one molecule of aldehyde is reduced to alcohol whereas other is oxidised to salt of carboxylic acid
\[{{C}_{6}}{{H}_{5}}CHO+KOH\to {{C}_{6}}{{H}_{5}}C{{H}_{2}}OH+{{C}_{6}}{{H}_{5}}COOK\]
32.
The major product of the following reaction sequence is
A
B
C
D
Answer :
33.
Which of the following names of the organic compounds is not correctly written?
A
B
C
D
Answer :
34.
The enol form of acetone, after treatment with \[{{D}_{2}}O,\] gives.
A
B
C
D
Answer :
Remember that \[\alpha -H's\] of carbonyl group are easily
replaced by \[D\,\text{of}\,{{D}_{2}}O.\]
35.
Acetaldehyde reacts with
A
only electrophiles
B
only nucleophiles
C
only free radicals
D
both electrophiles and nucleophiles
Answer :
only nucleophiles
The carbonyl group is highly reactive polar group. It is polarised due to the higher
electronegativity of oxygen in comparison to carbon. As a result, the electrons present between carbon and oxygen are more attracted towards oxygen atom. The actual structure may be represented as
Consequently, the carbonyl carbon is positively charged while the oxygen is negatively charged. The positively charged carbon is easily attacked by a nucleophilic reagent $$\left( {N{u^ - }} \right).$$
$$s{p^2}$$ hybridisation planar structure.
$$s{p^3}$$ hybridisation tetrahedral structure.
36.
Identify the final product. \[\xrightarrow[HCl,\,\Delta ]{Zn\left( Hg \right)}\]
A
B
C
D
Answer :
No explanation is given for this question. Let's discuss the answer together.
37.
Acetyl bromide reacts with excess of $$C{H_3}MgI$$ followed by treatment with a saturated solution of $$N{H_4}Cl$$ gives
A
2 - methyl - 2propanol
B
acetamide
C
acetone
D
acetyl iodide
Answer :
2 - methyl - 2propanol
38.
\[\underset{\left( A \right)}{\mathop{{{C}_{16}}{{H}_{16}}}}\,\xrightarrow{{{O}_{3}}}\underset{{{C}_{8}}{{H}_{8}}O}{\mathop{\left( B \right)}}\,\xrightarrow[H{{O}^{-}}/\Delta ]{N{{H}_{2}}-N{{H}_{2}}}\]
reactant $$(A)$$ in this reaction is :
A
B
C
D
Answer :
39.
During reduction of aldehydes with hydrazine and potassium hydroxide, the
first is the formation of
A
B
C
D
Answer :
40.
The most suitable reagent for the conversion of
$$R - C{H_2} - OH \to R - CHO$$ is:
A
$$KMn{O_4}$$
B
$${K_2}C{r_2}{O_7}$$
C
$$Cr{O_3}$$
D
$$PCC$$ ( Pyridinium Chlorochromate )
Answer :
$$PCC$$ ( Pyridinium Chlorochromate )
An excellent reagent for oxidation of $${1^ \circ }$$ alcohols to aldehydes is $$PCC.$$
\[R-C{{H}_{2}}-OH\xrightarrow{PCC}R-CHO\]