Aldehyde and Ketone MCQ Questions & Answers in Organic Chemistry | Chemistry
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71.
The carbonyl compound producing an optically active product by reaction with $$LiAl{H_4}$$ is
A
propanone
B
butanone
C
3-pentanone
D
benzophenone
Answer :
butanone
No explanation is given for this question. Let's discuss the answer together.
72.
The enolic form of acetone contains
A
9 sigma bonds, 1 pi - bond and 2 lone pairs
B
8 sigma bonds, 2 pi - bonds and 2 lone pairs
C
10 sigma bonds, 1 pi-bond and 1 lone pair
D
9 sigma bonds, 2 pi - bonds and 1 lone pair
Answer :
9 sigma bonds, 1 pi - bond and 2 lone pairs
No. of $$\sigma $$ bonds in enolic form: 3 + 1 + 1 + 1 + 1 + 2 = 9
No. of $$\pi $$ bonds in enolic form : 1
No. of lone pairs of electrons in enolic form = 2
73.
$$m{\text{ - }}$$ Chlorobenzaldehyde on reaction with conc. $$KOH$$ at room temperature gives
A
potassium $$m{\text{ - }}$$chlorobenzoate and
$$m{\text{ - }}$$hydroxybenzaldehyde
B
$$m{\text{ - }}$$hydroxybenzaldehyde and $$m{\text{ - }}$$chlorobenzyl alcohol
C
$$m{\text{ - }}$$chlorobenzyl alcohol and $$m{\text{ - }}$$hydroxybenzyl alcohol
D
potassium $$m{\text{ - }}$$chlorobenzoate and $$m{\text{ - }}$$chlorobenzyl
alcohol.
77.
Addition of water to alkynes occurs in acidic medium and in the presence of $$H{g^{2 + }}$$ ions as a catalyst. Which of the following products will be formed on addition of water to but-1-yne under these conditions?
A
\[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}\overset{\begin{smallmatrix}
O \\
\parallel
\end{smallmatrix}}{\mathop{-C-}}\,H\]
B
\[C{{H}_{3}}-C{{H}_{2}}\overset{\begin{smallmatrix}
O \\
\parallel
\end{smallmatrix}}{\mathop{-C-}}\,C{{H}_{3}}\]
C
\[C{{H}_{3}}-C{{H}_{2}}\overset{\begin{smallmatrix}
O \\
\parallel
\end{smallmatrix}}{\mathop{-C-}}\,OH+C{{O}_{2}}\]
D
\[C{{H}_{3}}\overset{\begin{smallmatrix}
O \\
\parallel
\end{smallmatrix}}{\mathop{-C-}}\,OH+H\overset{\begin{smallmatrix}
O \\
\parallel
\end{smallmatrix}}{\mathop{-C-}}\,H\]
Answer :
\[C{{H}_{3}}-C{{H}_{2}}\overset{\begin{smallmatrix}
O \\
\parallel
\end{smallmatrix}}{\mathop{-C-}}\,C{{H}_{3}}\]
No explanation is given for this question. Let's discuss the answer together.
78.
The reagents employed to carry the following transformation
A
\[LiAl{{H}_{4}},{{H}_{2}}S{{O}_{4}}/\text{heat}\]
B
\[PCC/C{{H}_{2}}C{{l}_{2}}\,\text{followed by}\,HI{{O}_{4}}\]
C
\[NaB{{H}_{4}}/C{{H}_{3}}OH\,\text{followed by}\,HI{{O}_{4}}\]
D
\[{{O}_{3}}\,\text{followed by}\,{{\left( C{{H}_{3}} \right)}_{2}}S\]
The compounds which contain either $$C{H_3} - CO - $$ group or group give positive
iodoform test. In 2-pentanone, $$\left( {C{H_3}C{H_2}C{H_2}COC{H_3}} \right),C{H_3}CHO$$ and $${C_2}{H_5}OH,$$ required groups are present, thus they give iodoform as follows
$$C{H_3} - COC{H_2} - C{H_2}\,C{H_3} + 3{I_2}$$ \[+4NaOH\to \underset{\begin{smallmatrix}
\text{Iodoform} \\
\text{(yellow ppt}\text{.)}
\end{smallmatrix}}{\mathop{CH{{I}_{3}}\downarrow }}\,\] $$ + C{H_3}C{H_2}C{H_2}COONa + 3NaI$$ $$ + 3{H_2}O$$
$$C{H_3}\,CHO + 3{I_2} + 4NaOH \to $$ \[\underset{\begin{smallmatrix}
\text{Iodoform} \\
\text{(yellow ppt)}
\end{smallmatrix}}{\mathop{CH{{I}_{3}}}}\,\downarrow +HCOONa+3NaI\] $$ + 3{H_2}O$$
\[{{C}_{2}}{{H}_{5}}OH\xrightarrow{{{I}_{2}}}C{{H}_{3}}CHO\]
$$C{H_3}CHO + 3{I_2} + 4NaOH \to $$ \[\underset{\text{Iodoform}}{\mathop{CH{{I}_{3}}\downarrow }}\,\,+HCOONa+3NaI+3{{H}_{2}}O\]
But due to absence of
group in 3-pentanone, it does not give iodoform.
80.
Correct order of reactivity of following compounds towards Grignard reagent ?
A
I > II > III
B
II > I > III
C
II > III > I
D
I > III > II
Answer :
II > I > III
\[-C{{H}_{3}}\] group give $$+M$$ and $$+I$$ but $$+M$$ work only at ortho and para position. Reactivity \[\propto \] positive charge on carbonyl carbon so that's why reactivity II > I > III.