Biomolecules MCQ Questions & Answers in Organic Chemistry | Chemistry
Learn Biomolecules MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
261.
The given structures (I) and (II) represent configuration of the simplest sugar glyceraldehyde. Which of the following statements is not correct for the structures?
\[\underset{\left( \text{I} \right)}{\mathop{\underset{\begin{smallmatrix}
|\,\,\,\, \\
\,\,\,\,\,\,C{{H}_{2}}OH
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,CHO \\
|\,\,\,\,
\end{smallmatrix}}{\mathop{H-C-OH}}}\,}}\,\,\,\,\,\,\,\underset{\left( \text{II} \right)}{\mathop{\underset{\begin{smallmatrix}
\,\,\,\,| \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{2}}OH
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,\,\,\,\,\,\,\,CHO \\
\,\,\,\,|
\end{smallmatrix}}{\mathop{HO-C-H}}}\,}}\,\]
A
(I) represents $$D$$ - form while (II) represents $$L$$ - form of glyceraldehyde.
B
The sugars having same configuration as $$D$$ - glyceraldehyde are designated as $$D$$ - sugars.
C
Natural glucose and fructose are $$D$$ - forms.
D
$$D$$ is dextrorotatory while $$L$$ is laevorotatory enantiomer.
Answer :
$$D$$ is dextrorotatory while $$L$$ is laevorotatory enantiomer.
$$D$$ - represents $$-OH$$ group on the right side of lowest
asymmetric $$C$$ - atom while $$L$$ represents $$-OH$$ group on the left.
262.
Primary structure of a protein is
A
sequence in which $$\alpha $$ - amino acids are linked to one another
B
sequence in which amino acids of one polypeptide chain are joined to other chain
C
the folding patterns of polypeptide chains
D
the pattern in which the polypeptide chains are arranged
Answer :
sequence in which $$\alpha $$ - amino acids are linked to one another
The sequence in which the $$\alpha $$ - amino acids are linked to one another in a protein molecule is called its primary structure.
263.
$$\alpha - D - \left( + \right) - $$ glucose and $$\beta - D - \left( + \right) - $$ glucose are
A
conformers
B
epimers
C
anomers
D
enatiomers
Answer :
anomers
Since $$\alpha - D - \left( + \right) - $$ glucose and
$$\beta - D - \left( + \right) - $$ glucose differ in configuration at $$C - 1$$ atom so they are anomers.
NOTE : Anomers are those diastereomers that differ in configuration at $$C - 1$$ atom.
ie., (C) in the correct answer.
264.
The secondary structure of a protein refers to
A
fixed configuration of the polypeptide backbone
B
$$\alpha - $$ helical backbone
C
hydrophobic interactions
D
sequence of $$\alpha - $$ amino acids.
Answer :
$$\alpha - $$ helical backbone
The secondary structure of protein refers to the shape in which a long peptide chain can exist. There are two different conformations of the peptide linkage present in protein, these are $$\alpha - $$ helix and $$\beta - $$ conformation. The $$\alpha - $$ helix always has a right handed arrangement. In $$\beta - $$ conformation all peptide chains are streched out to nearly maximum extension and then laid side by side and held together by intermolecular hydrogen bonds. The structure resembles the pleated folds of drapery and therefore is known as $$\beta - $$ pleated sheet.
265.
Which one of the following is not correct?
A
$$D\left( - \right)$$ Fructose exists in furanose structure.
B
$$D\left( + \right)$$ Glucose exists in pyranose structure.
C
In sucrose the two monosaccharides are held together by peptide linkage.
D
Maltose is a reducing sugar.
Answer :
In sucrose the two monosaccharides are held together by peptide linkage.
The linkage between monosaccharide units is called glycosidic linkage.
266.
The predominant form of histamine present in human blood is $$\left( {p{K_a},\,{\text{Histidine}} - 6.0} \right)$$
A
B
C
D
Answer :
siucture of histamine
Blood is slightly basic in nature $$\left( {7.35\,pH} \right).$$ At this $$pH,$$ terminal $$N{H_2}$$ will get protonated due to more basic nature.
∴ Predominant structure of histamine is
267.
Glucose on prolonged heating with $$HI$$ gives :
A
$$n\, - $$ Hexane
B
1 - Hexene
C
Hexanoic acid
D
6 - iodohexanal
Answer :
$$n\, - $$ Hexane
268.
Compounds $$I$$ and $$II$$ may be grouped as
A
diastereomers
B
epimers
C
$$C–2$$ epimers
D
all of the three.
Answer :
all of the three.
When structures $$I$$ and $$II$$ are $$C–2$$ epimers, it implies that these are epimers and diastereomers too.
269.
Bases common to $$RNA$$ and $$DNA$$ are
A
adenine, guanine, cytosine
B
adenine, uracil, cytosine
C
adenine, guanine, thymine
D
guanine, uracil, thymine
Answer :
adenine, guanine, cytosine
Adenine, guanine and cytosine are present in both $$RNA$$ and $$DNA. \, DNA$$ contains thymine while $$RNA$$ contains uracil.
270.
During the process of digestion, the proteins present in food materials are hydrolysed to amino acids. The two enzymes involved in the process
\[\text{Proteins}\xrightarrow{\text{Enzyme}\left( \text{A} \right)}\text{Polypeptides}\] \[\xrightarrow{\text{Enzyme}\left( \text{B} \right)}\text{Amino acids,}\] are respectively
A
amylase and maltase
B
diastase and lipase
C
pepsin and trypsin
D
invertase and zymase
Answer :
pepsin and trypsin
In the process of digestion the proteins present in food material are hydrolysed to amino acid. In this process two enzymes pepsin and trypsin are involved as follows :