Biomolecules MCQ Questions & Answers in Organic Chemistry | Chemistry
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41.
\[D-\left( + \right)-\] Glucose \[\xrightarrow{5{{\left( C{{H}_{3}}CO \right)}_{2}}O}D-\left( + \right)-\] Glucose pentaacetate
Which statement is true about glucose pentaacetate ?
A
It will react with phenylhydrazine but not with Tollens’ reagent.
B
It will react with Tollens’ reagent but not with phenylhydrazine.
C
It will react with both of the above mentioned reagents.
D
It will react neither with phenylhydrazine nor with Tollens’ reagent.
Answer :
It will react neither with phenylhydrazine nor with Tollens’ reagent.
During acetylation of \[\left( + \right)-\] glucose, it is the \[{{C}_{1}}-OH\] of the hemiacetal that is acetylated and not the \[{{C}_{5}}-OH\] that forms the ring ( cyclic structure ). Since equilibrium with the open - chain aldehyde is prevented, the
penta-acetate does not respond the aldehydic reactions.
42.
If one strand of $$DNA$$ has the sequence $$ATGCTTGA,$$ the sequence in the complimentary strand would be
A
$$TCCGAACT$$
B
$$TACGTAGT$$
C
$$TACGAATC$$
D
$$TACGAACT$$
Answer :
$$TACGAACT$$
In a $$DNA$$ molecule, $$A = T,C \equiv G.$$
So, the complimentary sequence of $$ATGCTTGA$$ is $$TACGAACT.$$
43.
Among the naturally occurring carbohydrates, furanose ring is found in the
A
glucose unit of cane sugar
B
glucose unit of cellulose
C
fructose unit of cane sugar
D
galactose unit of lactose
Answer :
fructose unit of cane sugar
Furanose ring is found in the fructose unit of cane sugar. In cane sugar, the fructose molecule has a five-membered ring structure (furanose ring).
44.
Which of the following evolves carbon dioxide, on oxidation with periodate ?
A
B
C
D
Answer :
A ketonic group having $$-OH$$ group on both sides is removed as $$C{O_2}$$ during oxidation with periodate.
45.
Match the column I with column II and mark the appropriate choice.
Column I
Column II
a.
Peptide linkage
1.
Inversion
b.
Nucleic acid
2.
Polysaccharide
c.
Hydrolysis of cane sugar
3.
Proteins
d.
Starch
4.
Nucleotides
A
a - 2, b - 1, c - 3, d - 4
B
a - 4, b - 1, c - 2, d - 3
C
a - 3, b - 4, c - 1, d - 2
D
a - 1, b - 3, c - 4, d - 2
Answer :
a - 3, b - 4, c - 1, d - 2
No explanation is given for this question. Let's discuss the answer together.
46.
Match the vitamins given in column I with the deficiency diseases caused by it given in column II and mark the appropriate choice.
Column I
Column II
a.
Vitamin $${B_1}$$
1.
Convulsions
b.
Vitamin $${B_2}$$
2.
Pernicious anaemia
c.
Vitamin $${B_{12}}$$
3.
Beri-beri
d.
Vitamin $${B_6}$$
4.
Cheilosis
A
a - 4, b - 3, c - 1, d - 2
B
a - 1, b - 4, c - 3, d - 2
C
a - 2, b - 1, c - 4, d - 3
D
a - 3, b - 4, c - 2, d - 1
Answer :
a - 3, b - 4, c - 2, d - 1
No explanation is given for this question. Let's discuss the answer together.
47.
In reference to biological role, $$C{a^{2 + }}$$ $$ions$$ are important in
A
triggering the contraction of muscles
B
generating the right electrode potential across cell membrane
C
hydrolysis of $$ATP$$
D
defence mechanism
Answer :
generating the right electrode potential across cell membrane
The $$C{a^{2 + }}$$ $$ion$$ generates the right electrical potential across cell membrane.
48.
A unit in nucleic acid which contains 'base-sugar phosphate' unit is called
A
nucleotide
B
nucleoside
C
phosphotide
D
polypeptide
Answer :
nucleotide
When nucleoside ( a unit formed by attachment of a base to sugar ) is linked to phosphoric acid, the unit formed is called nucleotide.
49.
A nucleoside on hydrolysis gives
A
an aldopentose and a nitrogenous base
B
an aldopentose and phosphoric acid
C
an aldopentose, a nitrogenous base phosphoric acid
D
a nitrogenous base and phosphoric acid
Answer :
an aldopentose and a nitrogenous base
Nucleoside is a unit formed by the attachment of a base to an aldopentose sugar.
50.
Which of the following compounds is found abundantly in nature?
A
Fructose
B
Starch
C
Glucose
D
Cellulose
Answer :
Cellulose
Cellulose is abundantly found in nature. It is the main constituent of plant cells.