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131.
Various products formed on oxidation of 2, 5-dimethylhexan-3-one are
\[\begin{align}
& \left( \text{i} \right)C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\,\, \\
C{{H}_{3}}\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,COOH \\
& \left( \text{ii} \right)C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
C{{H}_{3}}\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,C{{H}_{2}}-COOH \\
& \left( \text{iii} \right)C{{H}_{3}}COOH \\
& \left( \text{iv} \right)HCOOH \\
\end{align}\]
A
(i) and (iii)
B
(i), (ii) and (iii)
C
(i), (ii), (iii) and (iv)
D
(iii) and (iv)
Answer :
(i), (ii), (iii) and (iv)
No explanation is given for this question. Let's discuss the answer together.
132.
The final product $$(C)$$ obtained in the reaction sequence is \[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow{PC{{l}_{3}}}\left( A \right)\] \[\xrightarrow[AlC{{l}_{3}}]{{{C}_{6}}{{H}_{6}}}\left( B \right)\xrightarrow[\text{ base, heat}]{N{{H}_{2}}N{{H}_{2}}}\left( C \right)\]
A
B
C
D
Answer :
133.
Tischenko reaction is a modification of :
A
Aldol condensation
B
Claisen condensation
C
Cannizzaro reaction
D
Pinacol-pinacolon reaction
Answer :
Cannizzaro reaction
Tishchenko reaction is a modification of Canizzaro’s reaction. This reaction involves
disproportionation of an aldehyde lacking a hydrogen atom in the alpha position in
the presence of an alkoxide. The reaction product is an ester. Catalysts are aluminium alkoxide or sodium alkoxide.
In Cannizzaro’s reaction the base is sodium hydroxide and the oxidation product is a
carboxylic acid and the reduction product is an alcohol. \[\xrightarrow[50-{{60}^{\circ }},4\,hr]{{{C}_{6}}{{H}_{5}}C{{H}_{2}}ONa}\]
134.
In a set of reactions, acetic acid yielded a product $$D.$$
\[C{{H}_{3}}COOH\xrightarrow{SOC{{l}_{2}}}A\xrightarrow[\text{anhy}\text{.}\,\text{AlC}{{\text{l}}_{3}}]{\text{Benzene}}B\xrightarrow{HCN}C\xrightarrow{HOH}D\]
The structure of $$D$$ would be