Learn Carboxylic Acid MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
21.
The relative reactivities of acyl compounds towards nucleophilic substitution are in the order of
In acyl compounds ( i.e. acyl chloride, acid anhydride, ester and amide ) $$RCO-$$ group is same, thus reactivity depends upon the nature of group $$Z$$ \[\left( i.e.\,\,C{{l}^{-}},RCO{{O}^{-}},R'{{O}^{-}},NH_{2}^{-},etc. \right)\]
If group $$Z$$ is a weak base, then it is a strong leaving agent and its reactivity towards nucleophilic substitution is high.
The order of basic nature of $$Z$$ groups is
$$C{l^ - } < RCO{O^ - } < R'{O^ - } > NH_2^ - $$
Thus, order of reactivity is
$$\mathop {RCOCl}\limits_{{\text{Acyl chloride}}} > \mathop {{{\left( {RCO} \right)}_2}O}\limits_{{\text{Acid anhydride}}} > \mathop {RCOOR'}\limits_{{\text{Ester}}} > \mathop {RCON{H_2}}\limits_{{\text{Amide}}} $$
22.
On mixing ethyl acetate with aqueous sodium chloride, the composition of the resultant solution is
A
$$C{H_3}COCl + {C_2}{H_5}OH + NaOH$$
B
$$C{H_3}COONa + {C_2}{H_5}OH$$
C
$$C{H_3}COO{C_2}{H_5} + NaCl$$
D
$$C{H_3}Cl + {C_2}{H_5}COONa$$
Answer :
$$C{H_3}COO{C_2}{H_5} + NaCl$$
Thereis no reaction hence the resultant mixture contains $$C{H_3}COO{C_2}{H_5} + NaCl.$$
23.
In the above sequence of reaction $$X$$ and $$Y$$ are respectively
A
\[{{H}_{2}}/Pt;B{{r}_{2}}\]
B
\[KMn{{O}_{4}};{{H}_{2}}/Pt\]
C
\[KMn{{O}_{3}}\left( aq \right);HI/P\]
D
\[N{{H}_{2}}-N{{H}_{2}}/KOH,HI/P\]
Answer :
\[KMn{{O}_{3}}\left( aq \right);HI/P\]
\[KMn{{O}_{4}}\] converts \[-C{{H}_{3}}\] group of toluene into \[-COOH\] while $$HI$$ reduces \[-COOH\] group into \[-C{{H}_{3}}\] group.
24.
Which lactone is formed by heating the following hydroxy acid ?
A
B
C
D
Answer :
25.
The correct order of acidity for the following compounds is
A
I > II > III > IV
B
III > I > II > IV
C
III > IV > II > I
D
I > III > IV > II
Answer :
I > II > III > IV
∴ acidity order is I > II > III > IV
26.
Carboxylic acid group does not give the usual addition and elimination reactions of aldehydes and ketones because
A
$$O–H$$ bond is more polar than group
B
carboxylate ion gets ionised
C
carboxylate ion gets stabilised by resonance
D
it exists as $$-COOH$$ and there is no carbonyl group
Answer :
carboxylate ion gets stabilised by resonance
Due to resonance in carboxylate ion, the double bond character of $$C=O$$ bond in carboxylic acids is greatly reduced as compared to that in aldehydes and ketones.
27.
Compound \[Ph-O\overset{\begin{smallmatrix}
O \\
\parallel
\end{smallmatrix}}{\mathop{-C-}}\,Ph\] can be prepared by the reaction of ________.
A
phenol and benzoic acid in the presence of $$NaOH$$
B
phenol and benzoyl chloride in the presence of pyridine
C
phenol and benzoyl chloride in the presence of $$ZnC{l_2}$$
D
phenol and benzaldehyde in the presence of palladium
Answer :
phenol and benzoyl chloride in the presence of pyridine
No explanation is given for this question. Let's discuss the answer together.
28.
Consider the following transformations \[C{{H}_{3}}COOH\xrightarrow{CaC{{O}_{3}}}A\xrightarrow{Heat}\] \[B\xrightarrow[NaOH]{{{I}_{2}}}C\] The molecular formula of $$C$$ is
A
B
C
D
Answer :
29.
Which of the following orders of relative strengths of acids is correct ?
A
$$FC{H_2}COOH > ClC{H_2}COOH$$ $$ > BrC{H_2}COOH$$
B
$$ClC{H_2}COOH > BrC{H_2}COOH$$ $$ > FC{H_2}COOH$$
C
$$BrC{H_2}COOH > ClC{H_2}COOH$$ $$ > FC{H_2}COOH$$
D
$$ClC{H_2}C{O_2}H > FC{H_2}COOH$$ $$ > BrC{H_2}COOH$$