Electrophilic Aromatic Substitution (Haloalkanes and Haloarenes) MCQ Questions & Answers in Organic Chemistry | Chemistry
Learn Electrophilic Aromatic Substitution (Haloalkanes and Haloarenes) MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
181.
On treating a mixture of two alkyl halides with sodium metal in dry ether, 2-methylpropane was obtained. The alkyl halides are
A
2-chloropropane and chloromethane
B
2-chloropropane and chloroethane
C
chloromethane and chloroethane
D
chloromethane and 1-chloropropane
Answer :
2-chloropropane and chloromethane
182.
Which of the following reactions will give the major and minor products?
\[C{{H}_{3}}-C{{H}_{2}}-\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\,\,\, \\
Br\,\,\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{CH-}}\,C{{H}_{3}}\xrightarrow[\text{heat}]{alc.\,KOH}\]
$$C{H_3} - \mathop {CH = CH}\limits_{\left( A \right)} - C{H_3} + C{H_3}$$ $$ - \mathop {C{H_2} - CH}\limits_{\left( B \right)} = C{H_2}$$
A
$$(A)$$ is major product and $$(B)$$ is minor product.
B
$$(A)$$ is minor product and $$(B)$$ is major product.
C
Both $$(A)$$ and $$(B)$$ are major products.
D
Only $$(B)$$ is formed and $$(A)$$ is not formed.
Answer :
$$(A)$$ is major product and $$(B)$$ is minor product.
According to Saytzeff's rule, the more substituted product is more stable and is formed as major product. Hence $$(A)$$ is the major product (80%) while $$(B)$$ is the minor (20%) and less stable product.
183.
In a nucleophilic substitution reaction : \[R-Br+C{{l}^{-}}\xrightarrow{DMF}R-Cl+B{{r}^{-}},\] Which one of the following undergoes complete inversion of configuration ?
A
$${C_6}{H_5}CH{C_6}{H_5}Br$$
B
$${C_6}{H_5}C{H_2}Br$$
C
$${C_6}{H_5}CHC{H_3}Br$$
D
$${C_6}{H_5}CC{H_3}{C_6}{H_5}Br$$
Answer :
$${C_6}{H_5}CHC{H_3}Br$$
$${C_6}{H_5}CHC{H_3}Br$$ being an optically active secondary alkyl bromide undergoes $${S_N}2$$ nucleophilic substitution reaction. Hence it undergoes complete inversion of configuration.
184.
Which of the following will give enantiomeric pair on reaction with water due to presence of asymmetric carbon atom?
A
\[{{C}_{2}}{{H}_{5}}\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\, \\
{{C}_{2}}{{H}_{5}}\,\,\,
\end{smallmatrix}}{\overset{\begin{smallmatrix}
{{C}_{2}}{{H}_{5}}\, \\
|\,\,\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{-\,\,C-Br}}}\,\]
B
\[{{C}_{2}}{{H}_{5}}\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,
\end{smallmatrix}}{\overset{\begin{smallmatrix}
{{C}_{2}}{{H}_{5}} \\
|\,\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{-\,\,C-Cl}}}\,\]
C
\[{{C}_{2}}{{H}_{5}}\underset{\begin{smallmatrix}
| \\
\,\,\,\,C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
H \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,I\]
D
\[C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\, \\
{{C}_{2}}{{H}_{5}}\,\,\,
\end{smallmatrix}}{\overset{\begin{smallmatrix}
C{{H}_{3}} \\
|\,\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{-\,\,C-Br}}}\,\]
186.
Chlorobenzne reacts with trichloro acetaldehyde in the presence of $${H_2}S{O_4}.$$
The major product formed is :
A
B
C
D
Answer :
Chloral on reaction with chlorobenzene in the presence of a catalytic amount of
sulphuric acid forms $$DDT$$ ( dichlorodiphenyl Trichloro ethane ).
187.
The major product formed when 1, 1, 1-trichloro-propane is treated with aqueous potassium
hydroxide is :
A
Propyne
B
1-Propanol
C
2-Propanol
D
Propionic acid
Answer :
Propionic acid
188.
Pure $$\left( S \right) - C{H_3}C{H_2}CHBrC{H_3}$$ is subjected to monobromination to form several isomers of $${C_4}{H_8}B{r_2}.$$ Which of the following is not produced?
A
B
C
D
Answer :
$$C{H_3}C{H_2}\dot CBrC{H_3}$$ is quite unstable. hence cannot be produced.
189.
The end product $$(Q)$$ in the following sequence of reactions is
A
B
C
D
Answer :
190.
In the following pairs of halogen compounds, which compound undergoes faster $${S_N}1$$ reaction?
A
B
C
D
Answer :
No explanation is given for this question. Let's discuss the answer together.