Hydrocarbons (Alkane, Alkene and Alkyne) MCQ Questions & Answers in Organic Chemistry | Chemistry
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221.
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\xrightarrow[h\upsilon ]{C{{l}_{2}}}\] \[\underset{\begin{smallmatrix}
\text{(monochlorination} \\
\text{products) }
\end{smallmatrix}}{\mathop{A+B\,\,\,\,\,\,\,\,\,\,\,\,}}\,\]
The approximate ratio of percentage yields of $$A$$ and $$B$$ formed in the above reaction is
A
50 : 50
B
72 : 28
C
45 : 55
D
60 : 40
Answer :
72 : 28
\[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\xrightarrow[h\nu ]{C{{l}_{2}}}\] \[C{{H}_{3}}-C{{H}_{2}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
Cl\,\,\,\,\,
\\
\left( A \right)\,\,\,\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,C{{H}_{3}}\] \[\underset{\left( B \right)}{\mathop{+\,C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-Cl}}\,\]
During chlorination relative rate of abstraction of $$H$$ - atoms from 1°, 2° and 3° carbon atoms are 1 : 3.8 : 5.
$$\eqalign{
& {\text{Product ratio }}A = B = 15.2:6 \cr
& \% \,\,{\text{yield}}\,\,{\text{of}}\,\,A = \frac{{15.2}}{{21.2}} \times 100 = 71.70 \cr
& \% \,\,{\text{yield}}\,\,{\text{of}}\,\,B = \frac{2}{{21.2}} \times 100 = 28.30 \cr} $$
222.
Which of the following will form alkynide ?
A
B
C
D
Answer :
Only 1-Alkynes form alkynides
223.
On mixing a certain alkane with chlorine and irradiating it with ultraviolet light, it forms only one monochloroalkane. This alkane could be
A
pentane
B
isopentane
C
neopentane
D
propane
Answer :
neopentane
In neopentane all the $$H$$ atoms are same $$\left( {{1^ \circ }} \right).$$
\[C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
\,\,\,C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,\,C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{3}}\]
224.
Some $$meta$$ - directing substituents in aromatic substitution are given. Which one is most deactivating?
A
$$ - C \equiv N$$
B
$$ - S{O_3}H$$
C
$$ - COOH$$
D
$$ - N{O_2}$$
Answer :
$$ - N{O_2}$$
The deactivating tendency of given groups follows the order
Thus, $$ - N{O_2}$$ is the most deactivating group.
225.
Which of the following reactions does not show the acidic nature of ethyne?
A
Acetylene reacts with sodamide to form sodium acetylides.
B
When passed through ammoniacal cuprous chloride solution, a red precipitate is formed.
C
Acetylenereacts with chlorine in the dark to form di or tetrachlorides.
D
Acetylene when passed through ammoniacal silver nitrate gives a white precipitate.
Answer :
Acetylenereacts with chlorine in the dark to form di or tetrachlorides.
It is an addition reaction, so it does not show the acidic nature of ethyne.
226.
Match the column I with column II to identify the products of oxidation of alkanes and mark the appropriate choice.
Column I
Column II
a.
\[{\left( {C{H_3}} \right)_3}CH + 2
{O_2}\xrightarrow[{\left[ O \right]}]{{KMn
{O_4}}}\]
No explanation is given for this question. Let's discuss the answer together.
227.
The major product of the following reaction
A
B
C
D
Answer :
228.
At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires $$375 mL$$ air containing 20% $${O_2}$$ by volume for complete combustion. After combustion the gases occupy $$330 mL.$$ Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is :
A
$${C_4}{H_8}$$
B
$${C_4}{H_{10}}$$
C
$${C_3}{H_6}$$
D
$${C_3}{H_8}$$
Answer :
$${C_3}{H_8}$$
$${C_X}{H_{y\left( g \right)}} + \left( {\frac{{4x + y}}{4}} \right){O_{2\left( g \right)}} \to $$ $$xC{O_{2\left( g \right)}} + \frac{y}{2}{H_2}O\left( l \right)$$
$${\text{Volume of }}{{\text{O}}_2}\,{\text{used}} = 375 \times \frac{{20}}{{100}}$$ $$ = 75\,ml$$
$$\eqalign{
& \therefore \,\,{\text{From the reaction of combustion}} \cr
& 1\,ml\,{C_x}{H_y}{\text{ requires = }}\frac{{4x + y}}{4}ml\,{O_2} \cr
& 15ml = 15\left( {\frac{{4x + y}}{4}} \right) = 75 \cr
& {\text{So}},\,4x + y = 20 \cr
& x = 3 \cr
& y = 8 \cr
& \boxed{{C_3}{H_8}} \cr} $$
229.
Which of the following compounds has the lowest boiling point?
A
$$C{H_3}C{H_2}C{H_2}C{H_2}C{H_3}$$
B
$$C{H_3}CH = CH - C{H_2}C{H_3}$$
C
$$C{H_3}CH = CH - CH = C{H_2}$$
D
$$C{H_3}C{H_2}C{H_2}C{H_3}$$
Answer :
$$C{H_3}C{H_2}C{H_2}C{H_3}$$
Boiling points of alkanes increase as the number of carbon atom increases or molecular mass increases. Alkenes have high boiling point, so $$C{H_3}C{H_2}C{H_2}C{H_3}$$ has the lowest boiling point.
230.
Ethane is formed during the formation of chloromethane by chlorination of methane because
A
higher members of the hydrocarbons are generally formed during reactions
B
two methyl free radicals may combine during chlorination to give ethane
C
two chloromethane molecules react to form ethane
D
chlorine free radical reacts with methane to give ethane
Answer :
two methyl free radicals may combine during chlorination to give ethane
Methyl free radicals may react to form ethane.
$$\eqalign{
& \dot C{H_3} + C\dot l \to C{H_3}Cl{\text{ }}\left( {{\text{chloromethane}}} \right) \cr
& {\text{or}}\,\,\dot C{H_3} + \dot C{H_3} \to C{H_3} - C{H_3}\left( {{\text{ethane}}} \right) \cr} $$