Learn Organic Compounds Containing Nitrogen MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
41.
Which of the following will be most stable diazonium salt $$RN_2^ + {X^ - }?$$
A
$$C{H_3}N_2^ + {X^ - }$$
B
$${C_6}{H_5}N_2^ + {X^ - }$$
C
$$C{H_3}C{H_2}N_2^ + {X^ - }$$
D
$${C_6}{H_5}C{H_2}N_2^ + {X^ - }$$
Answer :
$${C_6}{H_5}N_2^ + {X^ - }$$
Diazonium salt containing aryl group directly linked to the nitrogen atom is most stable due to resonance stabilisation between the benzene nucleus and $$N$$ - atom. Diazonium ion act as a electrophile.
42.
Aniline when diazotised in cold and then treated with $$N, N$$ -dimethylaniline gives a coloured product. The structure of this product is
A
B
C
D
Answer :
No explanation is given for this question. Let's discuss the answer together.
43.
Butanonitrile may be prepared by heating :
A
Propyl alcohol with $$KCN$$
B
Butyl alcohol with $$KCN$$
C
Butyl chloride with $$KCN$$
D
Propyl chloride with $$KCN$$
Answer :
Propyl chloride with $$KCN$$
TIPS/Formulae : In the formation of cyanohydrin number of carbon atoms in parent chain increases by one.
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Cl+alc.\,KCN\xrightarrow{{{100}^{\circ }}C}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CN+KCl\]
44.
Which of the following is more basic than aniline?
A
Diphenylamine
B
Triphenylamine
C
$$p$$ - nitroaniline
D
Benzylamine
Answer :
Benzylamine
Benzylamine, $${C_6}{H_5}C{H_2} - \ddot N{H_2}$$ is more basic than aniline because benzyl group $$\left( {{C_6}{H_5}C{H_2} - } \right)$$ is electron donating group due to $$ + I$$ - effect So, it is able to increase the electron density of $$N$$ of $$ - N{H_2}$$ group. Thus, due to higher electron density, rate of donation of free pair of electron is increased, i.e. basic character is higher. Phenyl and nitro group are electron withdrawing groups, so they decreases the electron density on $$N$$ of \[-\ddot{N}{{H}_{2}}\] group. Hence, they are less basic than aniline.
45.
Oxidation of aniline with manganese dioxide and sulphuric acid produces
A
phenyl hydroxylamine
B
nitrobenzene
C
$$p$$-benzoquinone
D
phenol
Answer :
$$p$$-benzoquinone
No explanation is given for this question. Let's discuss the answer together.
46.
In the reaction
the product E is :
A
B
C
D
Answer :
47.
The most reactive amine towards dilute hydrochloric acid is _________.
A
B
C
D
Answer :
In aqueous solution, the most basic amine is $${\left( {C{H_3}} \right)_2}NH$$ and hence it is most reactive towards dilute hydrochloric acid.
48.
Amine that cannot be prepared by Gabrielphthalimide synthesis is
A
aniline
B
benzyl amine
C
methyl amine
D
$$iso$$ - butylamine
Answer :
aniline
Only pure aliphatic $${1^ \circ }$$ amines can be prepared by Gabriel synthesis. Aromatic $${1^ \circ }$$ amines such as aniline, toluidines, etc., cannot be prepared by this method because aryl halides $$\left( {{C_6}{H_5}Cl\,\,{\text{or}}\,\,{C_6}{H_5}Br} \right)$$ do not undergo nucleophilic substitution ( i.e., cleavage of $$C-X$$ bond in haloarene is quite difficult ) with potassium phthalimide under ordinary conditions to give $$N$$ - phenyl phthalimide.
49.
A compound $$(X)$$ with molecular formula $${C_3}{H_9}N$$ reacts with $${C_6}{H_5}S{O_2}Cl$$ to give a solid which is insoluble in alkali. $$(X)$$ is
A
$$C{H_3}C{H_2}C{H_2}N{H_2}$$
B
\[\underset{\begin{smallmatrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}} \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|
\end{smallmatrix}}{\mathop{C{{H}_{3}}-N}}}\,\]
C
$$C{H_3} - NH - C{H_2}C{H_3}$$
D
\[C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
C{{H}_{3}}\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,N{{H}_{2}}\]
Answer :
$$C{H_3} - NH - C{H_2}C{H_3}$$
Since the compound reacts with benzenesulphonyl chloride to give a product which is insoluble in alkali, it shows there is no $$H$$ attached to $$N$$ in the product. Hence, the compound $$X$$ is a secondary amine. \[C{{H}_{3}}-NH-{{C}_{2}}{{H}_{5}}+{{C}_{6}}{{H}_{5}}S{{O}_{2}}Cl\] \[\to \underset{N\text{-Ethyl-}N\text{-methylbenzene sulphonamide}}{\mathop{C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
\,\,\,\,{{C}_{2}}{{H}_{5}}
\end{smallmatrix}}{\mathop{-N-}}\,S{{O}_{2}}{{C}_{6}}{{H}_{5}}}}\,\]
50.
Choose the correct statement from the following.
A
Methyl amine is less soluble than propyl amine.
B
Methyl amine is solid with fishy odour.
C
Aniline gets coloured on storage.
D
Amines are more polar than alcohols.
Answer :
Aniline gets coloured on storage.
Aniline gets coloured on storage due to atmospheric oxidation.