Chemical Kinetics MCQ Questions & Answers in Physical Chemistry | Chemistry
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201.
The reaction of hydrogen and iodine monochloride is given as $${H_2}\left( g \right) + 2ICl\left( g \right) \to $$ $$2HCl\left( g \right) + {I_2}\left( g \right)$$
This reaction is of first order with respect to $${H_2}\left( g \right)$$ and $$ICl\left( g \right),$$ following mechanisms were proposed
Mechanism $$A$$
$${H_2}\left( g \right) + 2ICl\left( g \right) \to $$ $$2HCl\left( g \right) + {I_2}\left( g \right)$$
Mechanism $$B$$
$${H_2}\left( g \right) + ICl\left( g \right) \to $$ $$HCl\left( g \right) + HI\left( g \right),{\text{slow}}$$
$$HI\left( g \right) + ICl\left( g \right) \to $$ $$HCl\left( g \right) + {I_2}\left( g \right),{\text{fast}}$$
Which of the above mechanism $$(s)$$ can be consistent with the given information about the reaction?
A
Only $$B$$
B
Both $$A$$ and $$B$$
C
Neither $$A$$ nor $$B$$
D
Only $$A$$
Answer :
Only $$B$$
In the reactions which take place in a number of steps, the slowest step is known as the rate
determining step. Hence, rate of reaction always depends on slow step.
$${H_2}\left( g \right) + ICl\left( g \right) \to HCl\left( g \right) + HI\left( g \right)$$ is first order reaction with respect to $${H_2}$$ and $$ICl.$$ Thus, the mechanism $$B$$ will be more consistent with the given information.
202.
If half-life of a substance is 5 yrs, then the total amount of substance left after 15 years, when initial amount is 64 grams is
A
16 grams
B
2 grams
C
32 grams
D
8 grams.
Answer :
8 grams.
$${t_{\frac{1}{2}}} = 5$$ years, $$T = 15$$ years hence total number of half life periods $$ = \frac{{15}}{5} = 3.$$
$$\therefore \,\,{\text{Amount}}\,{\text{left}} = \frac{{64}}{{{{\left( 2 \right)}^3}}} = 8g$$
203.
The overall rate of a reaction is governed by
A
the rate of fastest intermediate step
B
the sum of the rates of all intermediate steps
C
the average of the rates of all the intermediate steps
D
the rate of slowest intermediate step
Answer :
the rate of slowest intermediate step
The slowest step is rate determining step.
204.
For the reaction $$A + B \to C + D.$$ The variation of the concentration of the products is given by the curve
A
$$Z$$
B
$$Y$$
C
$$W$$
D
$$X$$
Answer :
$$Y$$
The curve $$Y$$ shows the increase in concentration of products with time.
205.
A graph of volume of hydrogen released vs time for the reaction between zinc and dil. $$HCl$$ is given in figure. On the basis of this mark the correct option.
A
Average rate upto 40 seconds is $$\frac{{{V_3} - {V_2}}}{{40}}$$
B
Average rate upto 40 seconds is $$\frac{{{V_3} - {V_2}}}{{40 - 30}}$$
C
Average rate upto 40 seconds is $$\frac{{{V_3}}}{{40}}$$
D
Average rate upto 40 seconds is $$\frac{{{V_3} - {V_1}}}{{40 - 20}}$$
Answer :
Average rate upto 40 seconds is $$\frac{{{V_3}}}{{40}}$$
Average rate of reaction upto 40 sec $$ = \frac{{{V_3} - {V_0}}}{{40 - 0}} = \frac{{{V_3}}}{{40}}$$
206.
In a reaction, $$2X \to Y,$$ the concentration of $$X$$ decreases from $$0.50\,M$$ to $$0.38\,M$$ in $$10\,\min .$$ What is the rate of reaction in $$M\,{s^{ - 1}}$$ during this interval?
207.
In the presence of an acid, the initial concentration of cane sugar was reduced from $$0.20$$ to $$0.10\,M$$ in 5 hours and from $$0.2$$ to $$0.05\,M$$ in 10 hours. The reaction is of :
208.
The half-life of the reaction $$X \to Y,$$ following first order kinetics, when the initial concentration of $$X$$ is $$0.01\,mol\,{L^{ - 1}}$$ and initial rate is \[0.00352\,mol\,{{L}^{-1}}\,{{\min }^{-1}}\] will be
A
$$19.69\,\min .$$
B
$$1.969\,\min .$$
C
$$7.75\,\min .$$
D
$$77.5\,\min .$$
Answer :
$$1.969\,\min .$$
$$\eqalign{
& \frac{{dx}}{k} = k\left[ X \right]\,{\text{(For a first order reaction)}} \cr
& 0.00352 = k \times 0.01 \Rightarrow k = 0.352 \cr
& {t_{\frac{1}{2}}} = \frac{{0.693}}{k} = \frac{{0.693}}{{0.352}} = 1.969\,\min . \cr} $$
209.
Which one of the following statements is not correct?
A
Catalyst does not initiate any reaction
B
The value of equilibrium constant is changed in the presence of a catalyst in the reaction equilibrium
C
Enzymes catalyse mainly biochemical reaction
D
Coenzymes increase the catalytic activity of enzyme
Answer :
The value of equilibrium constant is changed in the presence of a catalyst in the reaction equilibrium
For a reversible reaction, it accelerates the speed of forward as well as backward reaction to the same extent. Hence, it does not disturb the equilibrium, i.e. does not change the equilibrium constant of the reaction but helps to attain the equilibrium faster.
210.
In a reaction, $$2A \to $$ products, the concentration
of $$A$$ decreases from $$0.50\,M$$ to $$0.38\,M$$ in
$$10\,\min .$$ What is the rate of reaction $$\left( {{\text{in}}\,M\,{s^{ - 1}}} \right)$$ during this interval ?