Chemical Kinetics MCQ Questions & Answers in Physical Chemistry | Chemistry

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241. Which of the following will react at the highest rate?

A $$1{\text{ }}mole$$  of $$A$$  and $$1{\text{ }}mole$$  of $$B$$  in a $$1{\text{ - }}L$$  vessel
B $$2{\text{ }}mole$$  of $$A$$  and $$2{\text{ }}mole$$  of $$B$$  in a $$2{\text{ - }}L$$  vessel
C $$3{\text{ }}mole$$  of $$A$$  and $$3{\text{ }}mole$$  of $$B$$  in a $$3{\text{ - }}L$$  vessel
D All would react at the same rate
Answer :   All would react at the same rate

242. For an exothermic chemical reaction occurring two steps as
$$\eqalign{ & \left( {\text{i}} \right)A + B \to X\left( {{\text{slow}}} \right) \cr & \left( {{\text{ii}}} \right)X \to AB\left( {{\text{fast}}} \right) \cr} $$
The progress of the reaction can be best described by

A Chemical Kinetics mcq option image
B Chemical Kinetics mcq option image
C Chemical Kinetics mcq option image
D Chemical Kinetics mcq option image
Answer :   Chemical Kinetics mcq option image

243. The hypothetical reaction $${A_2} + {B_2} \to 2AB;$$    follows the following mechanism \[{{A}_{2}}\xrightarrow{\text{Fast}}A+A,\]    \[A+{{B}_{2}}\xrightarrow{\text{Slow}}AB+B,A+B\xrightarrow{\text{Fast}}AB\cdot \]
The order of the overall reaction is

A $$0$$
B $$1$$
C $$2$$
D $$\frac{3}{2}$$
Answer :   $$\frac{3}{2}$$

244. The activation energy of the reaction, $$A + B \to C + D + 38\,kcal$$      is $$20\,kcal.$$  What would be the activation energy of the following reaction.
$$C + D \to A + B$$

A 20$$\,kcal$$
B - 20$$\,kcal$$
C 18$$\,kcal$$
D 58$$\,kcal$$
Answer :   58$$\,kcal$$

245. Find the values of $$A, B$$  and $$C$$  in the following table for the reaction $$X + Y \to Z.$$   The reaction is of first order $$w.r.t$$  $$X$$ and zero order $$w.r.t.$$  $$Y.$$
Exp.
$$\left[ X \right]\left( {mol\,{L^{ - 1}}} \right)$$
$$\left[ Y \right]\left( {mol\,{L^{ - 1}}} \right)$$
Initial rate $$\left( {mol\,{L^{ - 1}}\,{s^{ - 1}}} \right)$$
1.
0.1
0.1
$$2 \times {10^{ - 2}}$$
2.
$$A$$
0.2
$$4 \times {10^{ - 2}}$$
3.
0.4
0.4
$$B$$
4.
$$C$$
0.2
$$2 \times {10^{ - 2}}$$

A $$A = 0.2\,mol\,{L^{ - 1}},$$    $$B = 8 \times {10^{ - 2}}\,mol\,{L^{ - 1}}\,{s^{ - 1}},$$      $$C = 0.1\,mol\,{L^{ - 1}}$$
B $$A = 0.4\,mol\,{L^{ - 1}},$$    $$B = 4 \times {10^{ - 2}}\,mol\,{L^{ - 1}}\,{s^{ - 1}},$$      $$C = 0.2\,mol\,{L^{ - 1}}$$
C $$A = 0.2\,mol\,{L^{ - 1}},$$    $$B = 2 \times {10^{ - 2}}\,mol\,{L^{ - 1}}{s^{ - 1}},$$      $$C = 0.4\,mol{L^{ - 1}}$$
D $$A = 0.4\,mol\,{L^{ - 1}},$$    $$B = 2 \times {10^{ - 2}}\,mol\,{L^{ - 1}}\,{s^{ - 1}},$$      $$C = 0.4\,mol\,{L^{ - 1}}$$
Answer :   $$A = 0.2\,mol\,{L^{ - 1}},$$    $$B = 8 \times {10^{ - 2}}\,mol\,{L^{ - 1}}\,{s^{ - 1}},$$      $$C = 0.1\,mol\,{L^{ - 1}}$$

246. The rate of the reaction : $$C{H_3}COO{C_2}{H_5} + NaOH \to $$      $$C{H_3}COONa + {C_2}{H_5}OH$$      is given by the equation, $${\text{rate}} = k\left[ {C{H_3}COO{C_2}{H_5}} \right]\left[ {NaOH} \right]$$
If concentration is expressed in $$mol/L,$$  the units of $$k$$ are

A $$mo{l^{ - 2}}\,{L^2}\,{s^{ - 1}}$$
B $$mol\,{L^{ - 1}}\,{s^{ - 1}}$$
C $$L\,mo{l^{ - 1}}\,{s^{ - 1}}$$
D $${s^{ - 1}}$$
Answer :   $$L\,mo{l^{ - 1}}\,{s^{ - 1}}$$

247. A reaction having equal energies of activation for forward and reverse reaction has :

A $$\Delta G = 0$$
B $$\Delta H = 0$$
C $$\Delta H = \Delta G = \Delta S = 0$$
D $$\Delta S = 0$$
Answer :   $$\Delta H = 0$$

248. If the rate of a reaction is equal to the rate constant, the order of the reaction is

A 2
B 3
C 0
D 1
Answer :   0

249. For the reaction, $${N_2}{O_5}\left( g \right) \to 2N{O_2}\left( g \right) + \frac{1}{2}{O_2}\left( g \right)$$      The value of rate of disappearance of $${N_2}{O_5}$$  is given as $$6.25 \times {10^{ - 3}}mol\,{L^{ - 1}}{s^{ - 1}}.$$     The rate of formation of $$N{O_2}$$  and $${O_2}$$  is given respectively as

A $$6.25 \times {10^{ - 3}}mol\,{L^{ - 1}}{s^{ - 1}}\,{\text{and}}\,6.25 \times {10^{ - 3}}mol\,{L^{ - 1}}{s^{ - 1}}$$
B $$1.25 \times {10^{ - 2}}mol\,{L^{ - 1}}{s^{ - 1}}\,{\text{and}}\,3.125 \times {10^{ - 3}}mol\,{L^{ - 1}}{s^{ - 1}}$$
C $$6.25 \times {10^{ - 3}}mol\,{L^{ - 1}}{s^{ - 1}}\,{\text{and}}\,3.125 \times {10^{ - 3}}mol\,{L^{ - 1}}{s^{ - 1}}$$
D $$1.25 \times {10^{ - 2}}mol\,{L^{ - 1}}{s^{ - 1}}\,{\text{and}}\,6.25 \times {10^{ - 3}}mol\,{L^{ - 1}}{s^{ - 1}}$$
Answer :   $$1.25 \times {10^{ - 2}}mol\,{L^{ - 1}}{s^{ - 1}}\,{\text{and}}\,3.125 \times {10^{ - 3}}mol\,{L^{ - 1}}{s^{ - 1}}$$

250. For the reaction system : $$2NO\left( g \right) + {O_2}\left( g \right) \to 2\,N{O_2}\left( g \right)$$       volume is suddenly reduced to half its value by increasing the pressure on it. If the reaction is of first order with respect to $${O_2}$$  and second order with respect to $$NO,$$  the rate of reaction will

A diminish to one-eighth of its initial value
B increase to eight times of its initial value
C increase to four times of its initial value
D diminish to one-fourth of its initial value
Answer :   increase to eight times of its initial value