Chemical Thermodynamics MCQ Questions & Answers in Physical Chemistry | Chemistry

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41. The enthalpy change for a reaction does not depend upon

A use of different reactants for the same product
B the nature of intermediate reaction steps
C the differences in initial or final temperatures of involved substances
D the physical states of reactants and products
Answer :   the nature of intermediate reaction steps

42. Heat of neutralization of a strong acid $$HA$$  and a weaker acid $$HB$$  with $$KOH$$  are $$ - 13.7$$  and $$ - 12.7\,k\,cal\,mo{l^{ - 1}}.$$    When $$1\,mole$$  of $$KOH$$  was added to a mixture containing $$1\,mole$$  each of $$HA$$  and $$HB,$$ the heat change was $$ - 13.5\,kcal.$$   In what ratio is the base distributed between $$HA$$  and $$HB.$$

A 3 : 1
B 1 : 3
C 4 : 1
D 1 : 4
Answer :   4 : 1

43. If the heat change at constant volume for decomposition of silver oxide is $$80.25\,kJ,$$   what will be the heat change at constant pressure ?

A $$80.25\,kJ$$
B $$ > 80.25\,kJ$$
C $$ < 80.25\,kJ$$
D $$160.50\,kJ$$
Answer :   $$ > 80.25\,kJ$$

44. The pressure-volume work for an ideal gas can be calculated by using the expression $$W = - \int\limits_{{V_t}}^{{V_f}} {{P_{ex}}\,dV.} $$    The work can also be calculated from the $$PV - $$  plot by using the area under the curve within the specified limits. When an ideal gas is compressed (i) reversibly or (ii) irreversibly from volume $${V_i}$$  to $${V_f}.$$  Choose the correct option.

A $${W_{{\text{reversible}}}} = {W_{{\text{irreversible}}}}$$
B $${W_{{\text{reversible}}}} < {W_{{\text{irreversible}}}}$$
C $${W_{{\text{reversible}}}} > {W_{{\text{irreversible}}}}$$
D $${W_{{\text{reversible}}}} = {W_{{\text{irreversible}}}} + {P_{ex}}\,.\Delta V$$
Answer :   $${W_{{\text{reversible}}}} < {W_{{\text{irreversible}}}}$$

45. Dissolution of ammonium chloride in water is an endothermic reaction, yet it is a spontaneous process. This is due to the fact that

A $$\Delta H\,\,{\text{is}}\,\, + ve,\Delta S\,\,{\text{is}}\,\, - ve$$
B $$\Delta H\,\,{\text{is}}\,\, - ve,\Delta S\,\,{\text{is}}\,\, + ve$$
C $$\Delta H\,\,{\text{is}}\,\, + ve,\Delta S\,\,{\text{is}}\,\, + ve\,\,$$     $${\text{and}}\,\,\Delta H < T\Delta S$$
D $$\Delta H\,\,{\text{is}}\,\, + ve\,\,{\text{and}}\,\,\Delta H > T\Delta S$$
Answer :   $$\Delta H\,\,{\text{is}}\,\, + ve,\Delta S\,\,{\text{is}}\,\, + ve\,\,$$     $${\text{and}}\,\,\Delta H < T\Delta S$$

46. For a reaction : $$X \to Y + Z$$
Absolute entropies are $$X = 120\,J\,{K^{ - 1}}\,mo{l^{ - 1}},$$     $$Y = 213.8\,J\,{K^{ - 1}}\,mo{l^{ - 1}}$$     and $$Z = 197.9\,J\,{K^{ - 1}}\,mo{l^{ - 1}}.$$
What will be the entropy change at $$298\,K$$  and $$1\,atm?$$

A $$291.7\,J\,{K^{ - 1}}$$
B $$255\,J\,{K^{ - 1}}$$
C $$213.8\,J\,{K^{ - 1}}$$
D $$257.3\,J\,{K^{ - 1}}$$
Answer :   $$291.7\,J\,{K^{ - 1}}$$

47. The value for $$\Delta U$$  for the reversible isothermal evaporation of $$90\,g$$  water at $$100{\,^ \circ }C$$  will be $$\left( {\Delta {H_{{\text{evap}}}}} \right.$$  of water $$ = 40.8\,kJ\,mo{l^{ - 1}},$$    $$\left. {R = 8.314\,J\,{K^{ - 1}}\,mo{l^{ - 1}}} \right)$$

A $$4800\,kJ$$
B $$188.494\,kJ$$
C $$40.8\,kJ$$
D $$125.03\,kJ$$
Answer :   $$188.494\,kJ$$

48. At what temperature liquid water will be in equilibrium with water vapour ?
$$\Delta {H_{{\text{vap}}}} = 40.73\,kJ\,mo{l^{ - 1}},$$     $$\Delta {S_{{\text{vap}}}} = 0.109\,kJ\,{K^{ - 1}}\,mo{l^{ - 1}}$$

A 282.4$$\,K$$
B 373.6$$\,K$$
C 100$$\,K$$
D 400$$\,K$$
Answer :   373.6$$\,K$$

49. For which of the process, $$\Delta S$$  is negative ?

A $${H_{2\left( g \right)}} \to 2{H_{\left( g \right)}}$$
B $${N_{2\left( {g,1\,atm} \right)}} \to {N_{2\left( {g,8\,atm} \right)}}$$
C $$2S{O_{3\left( g \right)}} \to 2S{O_{2\left( g \right)}} + {O_{2\left( g \right)}}$$
D $${C_{{\text{(diamond)}}}} \to {C_{{\text{(graphite)}}}}$$
Answer :   $${N_{2\left( {g,1\,atm} \right)}} \to {N_{2\left( {g,8\,atm} \right)}}$$

50. For the reactions,
$$\eqalign{ & 2C + {O_2} \to 2\,C{O_2},\,\,\,\,\,\,\,\,\,\Delta H = - 393\,J \cr & 2Zn + {O_2} \to 2ZnO\,;\,\,\,\,\,\,\Delta H = - 412\,J \cr} $$

A carbon can oxidise $$Zn$$
B oxidation of carbon is not feasible
C oxidation of $$Zn$$ is not feasible
D $$Zn$$ can oxidise carbon.
Answer :   $$Zn$$ can oxidise carbon.