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101.
The oxidation state of nitrogen is correctly given for
It is an oxidation reaction. Reduction takes place at cathode.
106.
Consider the following reaction,
Select the incorrect statement.
A
It is not a disproportionation reaction.
B
It is intramolecular redox reaction.
C
$$O{H^ - }$$ is a reducing as well as oxidising agent.
D is a reducing as well as oxidising agent.
Answer :
$$O{H^ - }$$ is a reducing as well as oxidising agent.
One $$CHO$$ is oxidised to $$CO{O^ - }$$ and one $$CHO$$ is reduced to $$C{H_2}OH.$$
Thus, it is not a disproportionation reaction. It is intramolecular redox reaction. Thus, options (A) and (B) are true and is reducing as well as oxidising agent.
Thus, (D) is also true. Thus, (C) is incorrect.
107.
Which of the following involves transfer of five electrons ?
A
$$MnO_4^ - \to M{n^{2 + }}$$
B
$$CrO_4^{2 - } \to C{r^{3 + }}$$
C
$$MnO_4^{2 - } \to Mn{O_2}$$
D
$$C{r_2}O_7^{2 - } \to 2C{r^{3 + }}$$
Answer :
$$MnO_4^ - \to M{n^{2 + }}$$
$$O.N.$$ of $$Mn$$ in $$MnO_4^ - $$ is +7 and in $$M{n^{2 + }}$$ it is +2 The difference is of 5 electrons.
108.
Indicate whether the following conversions represent an oxidation, a reduction or none ( neither oxidation nor reduction ).
$$\eqalign{
& \left( {\text{i}} \right)HC{l_3}\,\,{\text{to}}\,\,HCl{O_4} \cr
& \left( {{\text{ii}}} \right)NH_4^ + \,{\text{to}}\,N{H_3} \cr
& \left( {{\text{iii}}} \right)N{O_2}\,\,{\text{to}}\,\,{N_2}{O_4} \cr
& \left( {{\text{iv}}} \right)HSO_3^ - \,{\text{to}}\,\,SO_4^{2 - } \cr
& \left( {\text{v}} \right){H_2}{O_2}\,\,{\text{to}}\,\,{H_2}O \cr} $$
(i)
(ii)
(iii)
(iv)
(v)
(a)
Oxidation
Reduction
None
None
Oxidation
(b)
Oxidation
None
None
Oxidation
Reduction
(c)
Reduction
Oxidation
Reduction
None
Reduction
(d)
Oxidation
Reduction
None
Reduction
Reduction
A
(a)
B
(b)
C
(c)
D
(d)
Answer :
(b)
109.
The oxidation number of $$Fe$$ in $$N{a_2}\left[ {Fe{{\left( {CN} \right)}_5}NO} \right]$$ is