Calorimetry MCQ Questions & Answers in Heat and Thermodynamics | Physics
Learn Calorimetry MCQ questions & answers in Heat and Thermodynamics are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
31.
A copper ball of mass $$100\,gm$$ is at a temperature $$T.$$ It is dropped in a copper calorimeter of mass $$100\,gm,$$ filled with $$170\,gm$$ of water at room temperature. Subsequently, the temperature of the system is found to be $$75{\,^ \circ }C.$$ $$T$$ is given by (Given : room temperature = $$30{\,^ \circ }C$$ specific heat of copper = $$0.1\,cal/gm{\,^ \circ }C$$ )
A
$$1250{\,^ \circ }C$$
B
$$825{\,^ \circ }C$$
C
$$800{\,^ \circ }C$$
D
$$885{\,^ \circ }C$$
Answer :
$$885{\,^ \circ }C$$
According to principle of calorimetry,
Heat lost = Heat gain
$$\eqalign{
& 100 \times 0.1\left( { - 75} \right) = 100 \times 0.1 \times 45 + 170 \times 1 \times 45 \cr
& 10 - 750 = 450 + 7650 \cr
& 10 = 1200 + 7650 \cr
& = 8850 \cr
& T = 885{\,^ \circ }C \cr} $$
32.
The temperature of equal masses of three different liquids $$A,B$$ and $$C$$ are $${12^ \circ }C,{19^ \circ }C$$ and $$28^ \circ C$$ respectively. The temperature when $$A$$ and $$B$$ are mixed is $$16^ \circ C$$ and when $$B$$ and $$C$$ are mixed is $${23^ \circ }C.$$ The temperature when $$A$$ and $$C$$ are mixed is
A
$${18.2^ \circ }C$$
B
$${22^ \circ }C$$
C
$${20.2^ \circ }C$$
D
$${25.2^ \circ }C$$
Answer :
$${20.2^ \circ }C$$
Heat gain = heat lost
$$\eqalign{
& {C_A}\left( {16 - 12} \right) = {C_B}\left( {19 - 16} \right) \Rightarrow \frac{{{C_A}}}{{{C_B}}} = \frac{3}{4} \cr
& {\text{and}}\,\,{C_B}\left( {23 - 19} \right) = {C_c}\left( {28 - 23} \right) \Rightarrow \frac{{{C_B}}}{{{C_C}}} = \frac{5}{4} \cr
& \Rightarrow \frac{{{C_A}}}{{{C_C}}} = \frac{{15}}{{16}}\,......\left( {\text{i}} \right) \cr} $$
If $$\theta $$ is the temperature when $$A$$ and $$C$$ are mixed then,
$$\eqalign{
& {C_A}\left( {\theta - 12} \right) = {C_C}\left( {28 - \theta } \right) \cr
& \Rightarrow \frac{{{C_A}}}{{{C_C}}} = \frac{{28 - \theta }}{{\theta - 12}}\,......\left( {{\text{ii}}} \right) \cr} $$
On solving equations (i) and (ii) $$\theta = {20.2^ \circ }C$$
33.
If mass-energy equivalence is taken into account, when water is cooled to form ice, the mass of water should
A
increase
B
remain unchanged
C
decrease
D
first increase then decrease
Answer :
decrease
When water is cooled to form ice, energy is released from water in the form of heat. As energy is equivalent to mass therefore when water is cooled to ice, its mass decreases.
34.
Water of volume 2 litre in a container is heated with a coil of $$1\,k W$$ at $$27{\,^ \circ }C.$$ The lid of the container is open and energy dissipates at rate of $$160\, J/s.$$ In how much time temperature will rise from $$27{\,^ \circ }C$$ to $$77{\,^ \circ }C$$ [Given specific heat of water is $$4.2\, kJ/kg$$ ]
A
$$7 \,min$$
B
$$6\, min\, 2\, s$$
C
$$8\, min\, 20\, s$$
D
$$14\, min$$
Answer :
$$8\, min\, 20\, s$$
As shown in the figure, the net heat absorbed by the water to raise its temperature
$$= (1000 - 160) = 840\, J/s$$
Now, the heat required to raise the temperature of water from $$27{\,^ \circ }C$$ to $$77{\,^ \circ }C$$ is
$$\eqalign{
& Q = mc\,\Delta t \cr
& = 2 \times 4200 \times 50\,J \cr} $$
Therefore the time required
$$\eqalign{
& t = \frac{Q}{{840}} \cr
& = \frac{{2 \times 4200 \times 50}}{{840}} \cr
& = 500\,\sec \cr
& = 8\,\min \,20\sec \cr} $$
35.
A beaker contains $$200\,gm$$ of water. The heat capacity of the beaker is equal to that of $$20\,gm$$ of water. The initial temperature of water in the beaker is $${20^ \circ }C.$$ If $$440\,gm$$ of hot water at $${92^ \circ }C$$ is poured in it, the final temperature, neglecting radiation loss, will be nearest to
A
$${58^ \circ }C$$
B
$${68^ \circ }C$$
C
$${73^ \circ }C$$
D
$${78^ \circ }C$$
Answer :
$${68^ \circ }C$$
Let the final temperature be $$T.$$
Then $$200 \times 1 \times \left( {T - 20} \right) + 20 \times \left( {T - 20} \right)$$
$$ = 440\left( {92 - T} \right)$$
Solving it, we get $$T = {68^ \circ }C.$$
36.
A block of ice at $$ - {10^ \circ }C$$ is slowly heated and converted to steam at $${100^ \circ }C.$$ Which of the following curves represents the phenomenon qualitatively?
A
B
C
D
Answer :
1. The temp. of ice changes from $$ - {10^ \circ }C$$ to $${0^ \circ }C.$$
2. Ice at $${0^ \circ }C$$ melts into water at $${0^ \circ }C.$$
3. Water at $${0^ \circ }C$$ changes into water at $${100^ \circ }C.$$
4. Water at $${100^ \circ }C$$ changes into steam at $${100^ \circ }C.$$
37.
The graph, shown in the adjacent diagram, represents the variation of temperature $$(T)$$ of two bodies, $$x$$ and $$y$$ having same surface area, with time $$(t)$$ due to the emission of radiation. Find the correct relation between the emissivity and absorptivity power of the two bodies
The graph shows that for the same temperature difference $$\left( {{T_2} - {T_1}} \right),$$ less time is taken for $$x.$$ This means the emissivity is more for $$x.$$ According to Kirchoff's law, a good emitter is a good absorber as well.
38.
An ideal Black - body at room temperature is thrown into a furnace. It is observed that
A
initially it is the darkest body and at later times the brightest
B
it is the darkest body at all times
C
it cannot be distinguished at all times
D
initially it is the darkest body and at later times it cannot be distinguished
Answer :
initially it is the darkest body and at later times the brightest
Note : According to Kirchoff's law, good absorbers are good emitters as well.
At high temperature (in the furnace), since it absorbs more energy, it emits more radiations as well and hence is the brightest.
39.
$$4200\,J$$ of work is required for
A
increasing the temperature of $$10\,g$$ of water through $${10^ \circ }C$$
B
increasing the temperature of $$100\,g$$ of water through $${10^ \circ }C$$
C
increasing the temperature of $$1\,kg$$ of water through $${10^ \circ }C$$
D
increasing the temperature of $$500\,g$$ of water through $${10^ \circ }C$$
Answer :
increasing the temperature of $$100\,g$$ of water through $${10^ \circ }C$$
Work done to raise the temperature of $$100\,gm$$ water through $${10^ \circ }C$$ is
$$\eqalign{
& W = JQ = 4.2 \times \left( {100 \times {{10}^{ - 3}} \times 1000 \times 10} \right) \cr
& = 4200\,J \cr} $$
40.
Mass of water which absorbs or emits the same amount of heat as is done by the body for the same rise or fall in temperature is known as
A
thermal capacity of the body
B
specific heat capacity of the body
C
latent heat capacity of the body
D
water equivalent of the body
Answer :
water equivalent of the body
Water equivalent is the quantity of water whose thermal capacity is same as the heat capacity of the body.