Kinetic Theory of Gases MCQ Questions & Answers in Heat and Thermodynamics | Physics
Learn Kinetic Theory of Gases MCQ questions & answers in Heat and Thermodynamics are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
111.
The equation of state for $$5\,g$$ of oxygen at a pressure $$P$$ and temperature $$T,$$ when occupying a volume $$V,$$ will be
where $$R$$ is the gas constant.
112.
$$N$$ molecules each of mass $$m$$ of a gas $$A$$ and $$2N$$ molecules each of mass $$2\,m$$ of gas $$B$$ are contained in the same vessel which is maintained at temperature $$T.$$ The mean square velocity of molecules of $$B$$ type is $${v^2}$$ and the mean square rectangular component of the velocity of $$A$$ type is denoted by $${\omega ^2}.$$ Then $$\frac{{{\omega ^2}}}{{{v^2}}}$$ is
A
$$2$$
B
$$1$$
C
$$\frac{1}{3}$$
D
$$\frac{2}{3}$$
Answer :
$$\frac{2}{3}$$
Mean kinetic energy of the two types of molecules should be equal. The mean From question, square velocity of $$A$$ type molecules $$ = {\omega ^2} + {\omega ^2} + {\omega ^2} = 3{\omega ^2}$$
Therefore, $$\frac{1}{2}m\left( {3{\omega ^2}} \right) = \frac{1}{2}\left( {2m} \right){v^2}$$
This gives $$\frac{{{\omega ^2}}}{{{v^2}}} = \frac{2}{3}$$