Radiation MCQ Questions & Answers in Heat and Thermodynamics | Physics
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51.
A black body at $${227^ \circ }C$$ radiates heat at the rate of $$7cal\,c{m^{ - 2}}{s^{ - 1}}.$$ At a temperature of $${727^ \circ }C,$$ the rate of heat radiated in the same units will be
52.
A kettle with 3 litre water at $${27^ \circ }C$$ is heated by operating coil heater of power $$2\,kW.$$ The heat is lost to the atmosphere at constant rate $$130\,J/\sec,$$ when its lid is open. In how much time will water heated to $${97^ \circ }C$$ with the lid open? (specific heat of water $$= 4.2\,kJ/kg$$ )
A
$$472\,\sec $$
B
$$693\,\sec $$
C
$$912\,\sec $$
D
$$1101\,\sec $$
Answer :
$$472\,\sec $$
By the law of conservation of energy, energy given by heater must be equal to the sum of energy gained by water and energy lost from the lid.
$$\eqalign{
& Pt = ms\Delta \theta + {\text{energy}}\,{\text{lost}} \cr
& 2000t = 3 \times 4.2 \times {10^3} \times \left( {97 - 27} \right) + 130t \cr
& \Rightarrow t = 472\sec \cr} $$
53.
A body cools in a surrounding which is at a constant temperature of $${\theta _0}.$$ Assume that it obeys Newton’s law of cooling. Its temperature $$\theta $$ is plotted against time $$t.$$ Tangents are drawn to the curve at the points $$P\left( {\theta = {\theta _2}} \right)$$ and $$Q\left( {\theta = {\theta _1}} \right).$$ These tangents meet the time axis at angle of $${\phi _2}$$ and $${\phi _1},$$ as shown, then
55.
The wavelength corresponding to maximum intensity of radiation emitted by a source at temperature $$2000\,K$$ is $$\lambda ,$$ then what is the wavelength corresponding to maximum intensity of radiation at temperature $$3000\,K$$ ?
A
$$\frac{2}{3}\lambda $$
B
$$\frac{{16}}{{81}}\lambda $$
C
$$\frac{{81}}{{16}}\lambda $$
D
$$\frac{4}{3}\lambda $$
Answer :
$$\frac{2}{3}\lambda $$
Wien’s displacement law is given by
$${\lambda _m}T = $$ constant
$${\lambda _m} = $$ Maximum wavelength radiation
$$T =$$ temperature of the body
So for two different cases, i.e. at two different temperatures
or $${\lambda _1}{T_1} = {\lambda _2}{T_2}$$
$${\lambda _2} = {\lambda _1}\left( {\frac{{{T_1}}}{{{T_2}}}} \right)$$
Given, $${T_1} = 2000\,K,{T_2} = 3000\,K,{\lambda _1} = \lambda $$
$$\therefore {\lambda _2} = \lambda \times \frac{{2000}}{{3000}} = \frac{2}{3}\lambda $$
56.
If a piece of metal is heated to temperature $${\theta}$$ and then allowed to cool in a room which is at temperature $${\theta _0},$$ the graph between the temperature $$T$$ of the metal and time $$t$$ will be closest to
A
B
C
D
Answer :
According to Newton’s law of cooling, the temperature goes on decreasing with time non-linearly.
57.
An ideal Black-body at room temperature is thrown into a furnace. It is observed that
A
initially it is the darkest body and at later times the brightest
B
it is the darkest body at all times
C
it cannot be distinguished at all times
D
initially it is the darkest body and at later
Answer :
initially it is the darkest body and at later times the brightest
According to Kirchoff's law, good absorbers are good emitters as well.
At high temperature (in the furnace), since it absorbs more energy, it emits more radiations as well and hence is the brightest.