Co - ordination Compounds MCQ Questions & Answers in Inorganic Chemistry | Chemistry
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241.
Which of the following sets of examples and geometry of the compounds is not correct?
242.
The oxidation states of $$Cr$$ in $$\left[ {Cr{{\left( {{H_2}O} \right)}_6}} \right]C{l_3},\left[ {Cr{{\left( {{C_6}{H_6}} \right)}_2}} \right]$$ and $${K_2}\left[ {Cr{{\left( {CN} \right)}_2}{{\left( O \right)}_2}{{\left( O \right)}_2}\left( {N{H_3}} \right)} \right]$$ respectively are :
A
one $$Co – Co$$ bond, six terminal $$CO$$ and two bridging $$CO$$
B
one $$Co – Co$$ bond, four terminal $$CO$$ and four bridging $$CO$$
C
no $$Co – Co$$ bond, six terminal $$CO$$ and two bridging $$CO$$
D
no $$Co – Co$$ bond, four terminal $$CO$$ and four bridging $$CO$$
Answer :
one $$Co – Co$$ bond, six terminal $$CO$$ and two bridging $$CO$$
244.
The name of complex ion, $${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }}$$ is
A
hexacyanoiron (III) ion
B
hexacyanitoferrate (III) ion
C
tricyanoferrate (III) ion
D
hexacyanidoferrate (III) ion
Answer :
hexacyanidoferrate (III) ion
Key Concept When complex ion is an anion, the name of the metal ends with suffix -ate along with its oxidation number in the complex ion.
$${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }} = $$ Hexacyanoferrate (III) ion
245.
Which one of the following octahedral complexes will not show geometrical
isomerism? ( $$A$$ and $$B$$ are monodentate ligands )
A
$$\left[ {M{A_4}{B_2}} \right]$$
B
$$\left[ {M{A_5}B} \right]$$
C
$$\left[ {M{A_2}{B_4}} \right]$$
D
$$\left[ {M{A_3}{B_3}} \right]$$
Answer :
$$\left[ {M{A_5}B} \right]$$
$$\left[ {M{A_5}B} \right]$$ due to absence of symmetry of $$B$$ cannot exist in the form of $$cis - trans - {\text{isomer}}{\text{.}}$$
246.
The degenerate orbitals of $${\left[ {Cr{{\left( {{H_2}O} \right)}_6}} \right]^{3 + }}\,{\text{are:}}$$
A
$${d_{xz}}\,{\text{and}}\,{d_{yz}}$$
B
$${d_{yz}}\,{\text{and}}\,{d_{{z^2}}}$$
C
$${d_{{z^2}}}\,{\text{and}}\,{d_{xz}}$$
D
$${d_{{x^2} - {y^2}\,}}\,{\text{and}}\,{d_{xy}}$$
Answer :
$${d_{xz}}\,{\text{and}}\,{d_{yz}}$$
$$C{r^{3 + }}$$ has $${d^3}$$ configuration and forms an octahedral inner orbitals complex.
The set of degenerate orbitals are $$\left( {{d_{xy}},{d_{yz}}\,{\text{and}}\,{d_{xz}}} \right)$$ and $$\left( {{d_{{x^2} - {y^2}\,}}\,{\text{and}}\,{d_{{z^2}}}} \right).$$
A
linkage isomerism, ionization isomerism and geometrical isomerism
B
ionization isomerism, geometrical isomerism and optical isomerism
C
linkage isomerism, geometrical isomerism and optical isomerism
D
linkage isomerism, ionization isomerism and optical isomerism
Answer :
linkage isomerism, ionization isomerism and geometrical isomerism
The given compound may have linkage isomerism due to presence of $$N{O_2}$$ group which may be in the form $$ - N{O_2}$$ or $$ - ONO.$$ $$\left[ {Co{{\left( {N{H_3}} \right)}_4}{{\left( {N{O_2}} \right)}_2}} \right]Cl$$ $$\& \left[ {CO{{\left( {N{H_3}} \right)}_4}{{\left( {ONO} \right)}_2}} \right]Cl$$ It may have ionisation isomerism due to presence of two ionisable groups $$ - N{O_2}$$ $$\& - Cl.$$
$$\left[ {Co{{\left( {N{H_3}} \right)}_4}Cl\left( {N{O_2}} \right)} \right]N{O_2}$$ $$\& \left[ {Co\left( {N{H_3}} \right){{\left( {N{O_2}} \right)}_2}} \right]Cl$$ It may have geometrical isomerism in the form of cis trans form as follows :
248.
Which of the following is a tridentate ligand?
A
$$EDT{A^{4 - }}$$
B
$$\left( {COO} \right)_2^{2 - }$$
C
$${\text{dien}}$$
D
$$NO_2^ - $$
Answer :
$${\text{dien}}$$
Dien (Diethylenetriamine) has the following structure.
$${H_2}\ddot N - C{H_2} - C{H_2} - \ddot NH - $$ $$C{H_2} - C{H_2} - \ddot N{H_2}$$
249.
Which of the following compounds is not coloured ?
A
$$N{a_2}\left[ {CuC{l_6}} \right]$$
B
$$N{a_2}\left[ {CdC{l_4}} \right]$$
C
$${K_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]$$
D
$${K_3}\left[ {Fe{{\left( {CN} \right)}_6}} \right]$$
Answer :
$$N{a_2}\left[ {CdC{l_4}} \right]$$
$$N{a_2}\left[ {CdC{l_4}} \right]$$ does not contain any unpaired electron hence colourless
250.
For the reaction of the type $$M + 4L \rightleftharpoons M{L_4}$$
A
larger the stability constant, lower the proportion of $$M{L_4}$$ that exists in solution
B
larger the stability constant, higher the proportion of $$M{L_4}$$ that exists in solution
C
smaller the stability constant, higher the proportion of $$M{L_4}$$ that exists in solution
D
None of the above
Answer :
larger the stability constant, higher the proportion of $$M{L_4}$$ that exists in solution
For the reaction of the type $$M + 4L \rightleftharpoons M{L_4},$$ larger the stability constant, the higher the proportion of $$M{L_4}$$ that exists in solution.