Co - ordination Compounds MCQ Questions & Answers in Inorganic Chemistry | Chemistry

Learn Co - ordination Compounds MCQ questions & answers in Inorganic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.

241. Which of the following sets of examples and geometry of the compounds is not correct?

A Octahedral $$ - {\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }},{\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }}$$
B Square planar $$ - {\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2\_}},{\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]^{2 + }}$$
C Tetrahedral $$ - \left[ {Ni{{\left( {CO} \right)}_4}} \right],{\left[ {ZnC{l_4}} \right]^{2 - }}$$
D Trigonal bipyramidal $$ - {\left[ {Fe{{\left( {N{H_3}} \right)}_6}} \right]^{2 + }},{\left[ {CuC{l_4}} \right]^{2 - }}$$
Answer :   Trigonal bipyramidal $$ - {\left[ {Fe{{\left( {N{H_3}} \right)}_6}} \right]^{2 + }},{\left[ {CuC{l_4}} \right]^{2 - }}$$

242. The oxidation states of $$Cr$$  in $$\left[ {Cr{{\left( {{H_2}O} \right)}_6}} \right]C{l_3},\left[ {Cr{{\left( {{C_6}{H_6}} \right)}_2}} \right]$$       and $${K_2}\left[ {Cr{{\left( {CN} \right)}_2}{{\left( O \right)}_2}{{\left( O \right)}_2}\left( {N{H_3}} \right)} \right]$$       respectively are :

A $$ + 3, + 4,\,{\text{and}}\, + 6$$
B $$ + 3, + 2,\,{\text{and}}\, + 4$$
C $$ + 3,0,\,{\text{and}}\, + 6$$
D $$ + 3,0,\,{\text{and}}\, + 4$$
Answer :   $$ + 3,0,\,{\text{and}}\, + 6$$

243. $$\left[ {C{o_2}{{\left( {CO} \right)}_8}} \right]$$   displays :

A one $$Co – Co$$   bond, six terminal $$CO$$  and two bridging $$CO$$
B one $$Co – Co$$   bond, four terminal $$CO$$  and four bridging $$CO$$
C no $$Co – Co$$   bond, six terminal $$CO$$  and two bridging $$CO$$
D no $$Co – Co$$   bond, four terminal $$CO$$  and four bridging $$CO$$
Answer :   one $$Co – Co$$   bond, six terminal $$CO$$  and two bridging $$CO$$

244. The name of complex ion, $${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }}$$   is

A hexacyanoiron (III) ion
B hexacyanitoferrate (III) ion
C tricyanoferrate (III) ion
D hexacyanidoferrate (III) ion
Answer :   hexacyanidoferrate (III) ion

245. Which one of the following octahedral complexes will not show geometrical isomerism? ( $$A$$ and $$B$$  are monodentate ligands )

A $$\left[ {M{A_4}{B_2}} \right]$$
B $$\left[ {M{A_5}B} \right]$$
C $$\left[ {M{A_2}{B_4}} \right]$$
D $$\left[ {M{A_3}{B_3}} \right]$$
Answer :   $$\left[ {M{A_5}B} \right]$$

246. The degenerate orbitals of $${\left[ {Cr{{\left( {{H_2}O} \right)}_6}} \right]^{3 + }}\,{\text{are:}}$$

A $${d_{xz}}\,{\text{and}}\,{d_{yz}}$$
B $${d_{yz}}\,{\text{and}}\,{d_{{z^2}}}$$
C $${d_{{z^2}}}\,{\text{and}}\,{d_{xz}}$$
D $${d_{{x^2} - {y^2}\,}}\,{\text{and}}\,{d_{xy}}$$
Answer :   $${d_{xz}}\,{\text{and}}\,{d_{yz}}$$

247. $$\left[ {Co{{\left( {N{H_3}} \right)}_4}{{\left( {N{O_2}} \right)}_2}} \right]Cl$$      exhibits

A linkage isomerism, ionization isomerism and geometrical isomerism
B ionization isomerism, geometrical isomerism and optical isomerism
C linkage isomerism, geometrical isomerism and optical isomerism
D linkage isomerism, ionization isomerism and optical isomerism
Answer :   linkage isomerism, ionization isomerism and geometrical isomerism

248. Which of the following is a tridentate ligand?

A $$EDT{A^{4 - }}$$
B $$\left( {COO} \right)_2^{2 - }$$
C $${\text{dien}}$$
D $$NO_2^ - $$
Answer :   $${\text{dien}}$$

249. Which of the following compounds is not coloured ?

A $$N{a_2}\left[ {CuC{l_6}} \right]$$
B $$N{a_2}\left[ {CdC{l_4}} \right]$$
C $${K_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]$$
D $${K_3}\left[ {Fe{{\left( {CN} \right)}_6}} \right]$$
Answer :   $$N{a_2}\left[ {CdC{l_4}} \right]$$

250. For the reaction of the type $$M + 4L \rightleftharpoons M{L_4}$$

A larger the stability constant, lower the proportion of $$M{L_4}$$  that exists in solution
B larger the stability constant, higher the proportion of $$M{L_4}$$  that exists in solution
C smaller the stability constant, higher the proportion of $$M{L_4}$$  that exists in solution
D None of the above
Answer :   larger the stability constant, higher the proportion of $$M{L_4}$$  that exists in solution