Co - ordination Compounds MCQ Questions & Answers in Inorganic Chemistry | Chemistry

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251. The number of unpaired electrons in the complex ion $${\left[ {Co{F_6}} \right]^{3 - }}$$  is ( At. no. of $$Co = 27$$  )

A 3
B 2
C 4
D 0
Answer :   4

252. When one mole of each of the following complexes is treated with excess of $$AgN{O_3},$$  which will give maximum amount of $$AgCl?$$

A $$\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]C{l_3}$$
B $$\left[ {Co{{\left( {N{H_3}} \right)}_5}Cl} \right]C{l_2}$$
C $$\left[ {Co{{\left( {N{H_3}} \right)}_4}C{l_2}} \right]Cl$$
D $$\left[ {Co{{\left( {N{H_3}} \right)}_3}C{l_3}} \right]$$
Answer :   $$\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]C{l_3}$$

253. In the separation of $$C{u^{2 + }}$$  and $$C{d^{2 + }}$$  of IInd group in qualitative analysis of cations, tetrammine copper (II) sulphate and tetrammine cadmium (II) sulphate react with $$KCN$$  to form the corresponding cyano complexes, which one of the following pairs of the complexes and their relative stability enables the separation of $$C{u^{2 + }}$$  and $$C{d^{2 + }}?$$

A $${K_3}\left[ {Cu{{\left( {CN} \right)}_4}} \right]:$$    less stable and $${K_2}\left[ {Cd{{\left( {CN} \right)}_4}} \right]:$$    more stable
B $${K_3}\left[ {Cu{{\left( {CN} \right)}_4}} \right]:$$    more stable and $${K_2}\left[ {Cd{{\left( {CN} \right)}_4}} \right]:$$    less stable
C $${K_2}\left[ {Cu{{\left( {CN} \right)}_4}} \right]:$$    less stable and $${K_2}\left[ {Cd{{\left( {CN} \right)}_4}} \right]:$$    more stable
D $${K_2}\left[ {Cu{{\left( {CN} \right)}_4}} \right]:$$    more stable and $${K_2}\left[ {Cd{{\left( {CN} \right)}_4}} \right]:$$    less stable
Answer :   $${K_3}\left[ {Cu{{\left( {CN} \right)}_4}} \right]:$$    more stable and $${K_2}\left[ {Cd{{\left( {CN} \right)}_4}} \right]:$$    less stable

254. The value of the 'spin only' magnetic moment for one of the following configurations is 2.84 $$BM.$$  The correct one is

A $${d^4}$$  ( in strong ligand field )
B $${d^4}$$  ( in weak ligand field )
C $${d^3}$$  ( in weak as well as in strong fields )
D $${d^5}$$  ( in strong ligand field )
Answer :   $${d^4}$$  ( in strong ligand field )

255. Give reason for the statement, $${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$   is diamagnetic while $${\left[ {NiC{l_4}} \right]^{2 - }}$$  is paramagnetic in nature.

A In $${\left[ {NiC{l_4}} \right]^{2 - }},$$   no unpaired electrons are present while in $${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$   two unpaired electrons are present.
B In $${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }},$$    no unpaired electrons are present while in $${\left[ {NiC{l_4}} \right]^{2 - }}$$  two unpaired electrons are present.
C $${\left[ {NiC{l_4}} \right]^{2 - }}$$  shows $$ds{p^2}$$  hybridisation hence it is paramagnetic.
D $${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$   shows $$s{p^3}$$  hybridisation hence it is diamagnetic.
Answer :   In $${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }},$$    no unpaired electrons are present while in $${\left[ {NiC{l_4}} \right]^{2 - }}$$  two unpaired electrons are present.

256. $$CrC{l_3} \cdot 6{H_2}O$$    exists in different isomeric forms which show different colours like violet and green. This is due to

A ionisation isomerism
B coordination isomerism
C optical isomerism
D hydrate isomerism
Answer :   hydrate isomerism

257. In solid $$CuS{O_4}.5{H_2}O$$    copper is coordinated to

A 4 water molecules
B 5 water molecules
C one sulphate molecule
D one water molecule
Answer :   4 water molecules

258. What is the magnetic moment (spin only) and hybridisation of the brown ring complex $$\left[ {Fe{{\left( {{H_2}O} \right)}_5}NO} \right]S{O_4}?$$

A $$\sqrt 3 BM,s{p^3}{d^2}$$
B $$\sqrt 3 BM,{d^2}s{p^3}$$
C $$\sqrt {15} BM,s{p^3}{d^2}$$
D $$\sqrt {15} BM,{d^2}s{p^3}$$
Answer :   $$\sqrt {15} BM,s{p^3}{d^2}$$

259. When $$1\,mol\,CrC{l_3} \cdot 6{H_2}O$$     is treated with excess of $$AgN{O_3},3\,mol$$    of $$AgCl$$  are obtained. The formula of the complex is

A $$\left[ {CrC{l_3}{{\left( {{H_2}O} \right)}_3}} \right] \cdot 3{H_2}O$$
B $$\left[ {CrC{l_2}{{\left( {{H_2}O} \right)}_4}} \right]Cl \cdot 2{H_2}O$$
C $$\left[ {CrCl{{\left( {{H_2}O} \right)}_5}} \right]C{l_2} \cdot {H_2}O$$
D $$\left[ {Cr{{\left( {{H_2}O} \right)}_6}} \right]C{l_3}$$
Answer :   $$\left[ {Cr{{\left( {{H_2}O} \right)}_6}} \right]C{l_3}$$

260. The magnetic moment of the complex anion $${\left[ {Cr\left( {NO} \right)\left( {N{H_3}} \right){{\left( {CN} \right)}_4}} \right]^{2 - }}$$      is :

A 5.91$$\,BM$$
B 3.87$$\,BM$$
C 1.73$$\,BM$$
D 2.82$$\,BM$$
Answer :   2.82$$\,BM$$