P - Block Elements MCQ Questions & Answers in Inorganic Chemistry | Chemistry
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111.
In the reaction, $$2X + {B_2}{H_6} \to {\left[ {B{H_2}\left( {{X_2}} \right)} \right]^ + }{\left[ {B{H_4}} \right]^ - }$$
$$'X'$$ cannot be
112.
In $$SiO_4^{4 - },$$ the tetrahedral molecule, two oxygen atoms are shared in
A
sheet silicates
B
double-chain silicates
C
chain silicates
D
three-dimensional silicates
Answer :
chain silicates
In sheet silicates, three oxygen atoms of each tetrahedra are shared with adjacent $$SiO_4^{4 - }$$ tetrahedra. In chain silicates, two oxygen atoms are shared by each tetrahedra.
113.
The hybridisation state of the central atom and shape of the molecules is given below. Mark the incorrect combination.
A
$$S{O_3} - s{p^2}$$ hybridisation, planar triangular
B
$$S{O_2} - s{p^2}$$ hybridisation, $$V$$ - shaped
C
$${H_2}S{O_4} - s{p^2}$$ hybridisation, $$V$$ - shaped
114.
Which one of the following statements about the zeolite is false?
A
They are used as cation exchangers.
B
Some of the $$SiO_4^{4 - }$$ units are replaced by $$AlO_4^{5 - }$$ and $$AlO_6^{9 - }$$ ions in zeolite.
C
They have open structure which enables them to take up small molecules.
D
Zeolites are aluminosilicates having three dimensional structures.
Answer :
Some of the $$SiO_4^{4 - }$$ units are replaced by $$AlO_4^{5 - }$$ and $$AlO_6^{9 - }$$ ions in zeolite.
Zeolite have $$Si{O_4}$$ and $$Al{O_4}$$ tetrahedrons linked together in a three dimensional open structure in which four or six membered ring predominate. Due to open chain structure they have cavities and can take up water and other small molecules.
115.
Which of the following factors would favour the formation of ammonia in Haber's process?
A
High pressure
B
Low temperature
C
High volume
D
Low pressure
Answer :
High pressure
According to Le Chatelier's principle, high pressure would favour the formation of $$N{H_3}.$$
$${N_{2\left( g \right)}} + 3{H_{2\left( g \right)}} \rightleftharpoons 2N{H_{3\left( g \right)}}$$
The optimum conditions for the production of $$N{H_3}$$ are pressure of $$200 \times {10^5}\,Pa$$ (about 200 atm) and temperature of $$ \sim 700\,K.$$
116.
In the structure of $$PC{l_5},$$ the $$P - C{l_{{\text{axial}}}}$$ bonds are longer than $$P - C{l_{{\text{equatorial}}}}$$ bond because
A
axial bond pairs suffer more repulsion
B
equatorial bond pairs suffer more repulsion
C
axial bond pairs suffer less repulsion
D
unequal bond lengths are more stable
Answer :
axial bond pairs suffer more repulsion
Axial bonds suffer more repulsion thus are longer than equatorial bonds.
117.
Under hydrolytic conditions, the compounds used for preparation of linear polymer and for chain termination, respectively, are
A
$$C{H_3}SiC{l_3}\,{\text{and}}\,Si{\left( {C{H_3}} \right)_4}$$
B
$${\left( {C{H_3}} \right)_2}SiC{l_2}\,{\text{and}}\,{\left( {C{H_3}} \right)_3}SiCl$$
C
$${\left( {C{H_3}} \right)_2}SiC{l_2}\,{\text{and}}\,C{H_3}SiC{l_3}$$
D
$$SiC{l_4}\,{\text{and}}\,{\left( {C{H_3}} \right)_3}SiCl$$
No explanation is given for this question. Let's discuss the answer together.
118.
$${\left( {Me} \right)_2}SiC{l_2}$$ on hydrolysis will produce
A
$${\left( {Me} \right)_2}Si{\left( {OH} \right)_2}$$
B
$$\,{\left( {Me} \right)_2}Si = O$$
C
$$ - {\left[ { - O - {{\left( {Me} \right)}_2}Si - O - } \right]_n} - $$
D
$${\left( {Me} \right)_2}SiCl\left( {OH} \right)$$
Answer :
$$ - {\left[ { - O - {{\left( {Me} \right)}_2}Si - O - } \right]_n} - $$
TIPS/FORMULAE:
It appears at the first sight that $$M{e_2}SiC{l_2}$$ on hydrolysis will produce $$M{e_2}Si{\left( {OH} \right)_2}$$ which ultimately upon loss of water, will form $$M{e_2}Si = O.$$
But silicon atom, because of its very large size in comparison to oxygen, is unable to form $$\pi $$-bond. Thus, the product of hydrolysis is polymeric in nature.
119.
Nitrogen dioxide cannot be obtained by heating :
A
$$KN{O_3}$$
B
$$Pb{\left( {N{O_3}} \right)_2}$$
C
$$Cu{\left( {N{O_3}} \right)_2}$$
D
$$AgN{O_3}$$
Answer :
$$KN{O_3}$$
Only nitrates of heavy metals and lithium decompose on heating to produce $$N{O_2}$$.
120.
A metal, $$M$$ forms chlorides in its $$+2$$ and $$+4$$ oxidation states. Which of the following statements about these chlorides is correct ?
A
$$MC{l_2}$$ is more ionic than $$MC{l_4}$$
B
$$MC{l_2}$$ is more easily hydrolysed than $$MC{l_4}$$
C
$$MC{l_2}$$ is more volatile than $$MC{l_4}$$
D
$$MC{l_2}$$ is more soluble in anhydrous ethanol than $$MC{l_4}$$
Answer :
$$MC{l_2}$$ is more ionic than $$MC{l_4}$$
Metal atom in the lower oxidation state forms the ionic bond and in the higher oxidation
state the covalent bond because higher oxidation state means small size and great
polarizing power and hence greater the covalent character. Hence $$MC{l_2}$$ is more ionic than $$MC{l_4}.$$