P - Block Elements MCQ Questions & Answers in Inorganic Chemistry | Chemistry
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221.
Fill in the blanks by choosing the appropriate option. $$Conc.\,{H_2}S{O_4}$$ chars paper, wood and sugar by removing $$\underline {\left( {\text{i}} \right)} $$ from them. It is also known as $$\underline {\left( {{\text{ii}}} \right)} .$$ It is manufactured by $$\underline {\left( {{\text{iii}}} \right)} $$ process. It is a strong $$\underline {\left( {{\text{iv}}} \right)} $$ and $$\underline {\left( {\text{v}} \right)} $$ acid.
(i)
(ii)
(iii)
(iv)
(v)
(a)
$${H_2}O$$
oil of vitriol
Contact
Oxidising
Dibasic
(b)
$${O_2}$$
oil of vitriol
oleum
dehydrating
monobasic
(c)
$${H_2}O$$
oil of olay
Solvay
dehydrating
dibasic
(d)
$$S{O_2}$$
oil of winter green
contact
oxidising
monobasic
A
(a)
B
(b)
C
(c)
D
(d)
Answer :
(a)
No explanation is given for this question. Let's discuss the answer together.
222.
Silicon is an important constituent of
A
sand
B
atmosphere
C
plants
D
water bodies
Answer :
sand
Silicon is an important constituent of sand in the form of silica.
223.
Which is the best description of behaviour of bromine in the reaction given below?
$${H_2}O + B{r_2} \to HBr + HOBr$$
A
Only oxidised
B
Only reduced
C
Both oxidised and reduced
D
Only proton accepted
Answer :
Both oxidised and reduced
In the reaction,
$${H_2}O + \mathop B\limits^0 {r_2} \to HO\mathop {Br}\limits^{ + 1} + H\mathop {Br}\limits^{ - 1} $$
The oxidation number of bromine increases from 0 to +1 and decreases from 0 to -1, due to this reason bromine is both oxidised as well as reduced in the above reaction.
224.
$$BC{l_3}$$ is a planar molecule whereas $$NC{l_3}$$ is pyramidal because
A
$$BC{l_3}$$ has no lone pair of electrons but $$NC{l_3}$$ has a lone pair of electrons.
B
$$B - Cl$$ bond is more polar than $$N - Cl$$ bond.
C
nitrogen atom is smaller than boron atom.
D
$$N - Cl$$ bond is more covalent than $$B - Cl$$ bond.
Answer :
$$BC{l_3}$$ has no lone pair of electrons but $$NC{l_3}$$ has a lone pair of electrons.
In $$BC{l_3}$$ there is $$s{p^2}$$ hybridisation (planar) whereas in $$NC{l_3}$$ hybridisation is $$s{p^3}$$ hence shape is pyramidal
225.
The exhibition of highest co-ordination number depends on the availability of vacant orbitals in the central atom. Which of the following elements is not likely to act as central atom in $$MF_6^{3 - }?$$
A
$$B$$
B
$$Al$$
C
$$Ga$$
D
$$In$$
Answer :
$$B$$
Due to non-availability of $$d$$ - orbitals, boron is restricted to a maximum covalence of four ( using $$2s$$ and three $$2p$$ orbitals ) while others $$\left( {Al,Ga,In} \right)$$ can expand their covalence above four by using their $$3d$$ orbitals. Thus, $$B$$ forms only $${\left[ {B{F_4}} \right]^ - }$$ and others form $${\left[ {M{F_6}} \right]^{3 - }}.$$
226.
Under ambient conditions, the total number of gases released
as products in the final step of the reaction scheme shown
below is
A
$$0$$
B
$$1$$
C
$$2$$
D
$$3$$
Answer :
$$2$$
227.
On heating, lead nitrate forms oxides of nitrogen and lead. The oxides formed are _________.
229.
Which is the correct statement for the given acids?
A
Phosphinic acid is a monoprotic acid while phosphonic acid is a diprotic acid
B
Prosphinic acid is a diprotic acid while phosphonic acid is a monoprotic acid
C
Both are triprotic acids
D
Both are diprotic acids
Answer :
Phosphinic acid is a monoprotic acid while phosphonic acid is a diprotic acid
Phosphinic acid
Phosphonic acid
Due to the presence of one replaceable proton in phosphinic acid, it is monoprotic acid. And due to presence of two replaceable proton in phosphonic acid, it is diprotic acid.
230.
The acid having $$\,O - O\,$$ bond is
A
$${H_2}{S_2}{O_3}$$
B
$${H_2}{S_2}{O_6}$$
C
$${H_2}{S_2}{O_8}$$
D
$${H_2}{S_4}{O_6}$$
Answer :
$${H_2}{S_2}{O_8}$$
Among oxyacids of sulphur, only Caro’s acid $$\left( {{H_2}S{O_5}} \right)$$ and Marshall’s acid $$\left( {{H_2}{S_2}{O_8}} \right)$$ have the $$O - O$$ linkage.