Hydrocarbons (Alkane, Alkene and Alkyne) MCQ Questions & Answers in Organic Chemistry | Chemistry
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1.
The major product obtained in the following reaction
A
B
C
D
Answer :
The ring $$B$$ has $$o/p$$ directing and $$(A)$$ has $$m$$ - directing group. Hence the product will be
2.
Which of these will not react with acetylene ?
A
$$NaOH$$
B
ammonical $$AgN{O_3}$$
C
$$Na$$
D
$$HCl$$
Answer :
$$NaOH$$
Acetylene reacts with the other three as :
\[CH\equiv CH\xrightarrow{\left[ AgN{{O}_{3}}+N{{H}_{4}}OH \right]}\underset{\text{white ppt}\text{.}}{\mathop{AgC\equiv CAg}}\,+N{{H}_{4}}N{{O}_{3}}\]
3.
In the presence of platinum catalyst , hydrocarbon $$A$$ adds hydrogen to form $$n$$ - hexane. When hydrogen bromide is added to $$A$$ instead of hydrogen only a single bromo compound is formed. Which of the following is $$A?$$
4.
The ozonolysis product$$(s)$$ of the following reaction is(are)
\[C{{H}_{3}}C{{H}_{2}}-C\equiv CH\xrightarrow[\left( \text{ii} \right)\,{{H}_{2}}O]{\left( \text{i} \right)\,{{O}_{3}}}\] \[\text{Product}\left( s \right)\]
A
$$C{H_3}COC{H_3}$$
B
$$C{H_3}COC{H_3} + HCHO$$
C
$$C{H_3}COOH + HCOOH$$
D
$$C{H_3}C{H_2}COOH + HCOOH$$
Answer :
$$C{H_3}C{H_2}COOH + HCOOH$$
No explanation is given for this question. Let's discuss the answer together.
5.
The product of the reaction between ethyl benzene and $$N$$ - bromosuccinamide is
A
B
C
D
Answer :
6.
Identify the reagent from the following list which can easily
distinguish between 1 - butyne and 2 - butyne
A
bromine, $$CC{l_4}$$
B
$${H_2}$$ Lindlar catalyst
C
dilute $${H_2}S{O_4},HgS{O_4}$$
D
ammonical $$C{u_2}C{l_2}$$ solution
Answer :
ammonical $$C{u_2}C{l_2}$$ solution
In 1 - butyne terminal hydrogen is acidic where as in 2 -butyne there is no terminal hydrogen. Thus 2 - butyne will not react with ammonical $$C{u_2}C{l_2}.$$ While 1 - butyne, being terminal alkyne, will give red ppt. with ammonical cuprous chloride
7. \[\xrightarrow[Zn]{{{O}_{3}}}A\xrightarrow[\text{Or}\,\,LiAl{{H}_{4}}]{{{H}_{3}}Ni}B\xrightarrow[\Delta ]{H+}\left( C \right);\] Product $$(C)$$ of the reaction is
A
B
C
D
Answer :
8.
Which of the following is an aromatic species ?
A
B
C
D
Answer :
An aromatic compound have cyclic clouds of delocalised $$\left( {4n + 2} \right)\pi $$ electrons above and below the plane of the molecule. Among the given three compounds, only compound (C) satisfies these conditions.
Carbon bearing $$ - N{O_2}$$ ( or $$ - C{H_3}$$ ) group is $$s{p^3}$$ hybridised and does not have a $$p$$ orbital with the result delocalisation of $$\pi $$ electrons over the complete ring is interrupted.
$$4\pi $$ electrons and 2 non-bonding electrons ( present in $$p$$ orbital of $$N$$ ) form a cyclic cloud of $$6\pi $$ electrons
Greater the $$s$$ - character of $$C$$ - atom in hydrocarbons, greater the electronegativity of that carbon and thus greater the acidic nature of the $$H$$ attached to electronegative carbon.
$${\text{Thus,}}\,\,\,CH \equiv CH > C{H_3}C \equiv $$ $$CH > C{H_2} = C{H_2} > C{H_3} - C{H_3}$$