Hydrocarbons (Alkane, Alkene and Alkyne) MCQ Questions & Answers in Organic Chemistry | Chemistry
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281.
The compound that will react most readily with gaseous bromine has the formula
A
$${C_3}{H_6}$$
B
$${C_2}{H_2}$$
C
$${C_4}{H_{10}}$$
D
$${C_2}{H_4}$$
Answer :
$${C_4}{H_{10}}$$
In gaseous state, $$B{r_2}$$ forms free radicals and saturated hydrocarbons are more prone to have free radical substitutions. As $${C_4}{H_{10}}$$ reacts most readily with gaseous bromine via free radical mechanism as shown below :
$${C_4}{H_{10}} + B{r_2} \to {C_4}{H_9}Br + HBr$$
Therefore, option (C) is correct.
282.
Choose the correct reagents used in the conversion.
\[C{{H}_{2}}=C{{H}_{2}}\xrightarrow{\left( p \right)}\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\, \\
Br\,\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,-\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\, \\
Br\,\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,\] \[\xrightarrow{\left( q \right)}C{{H}_{2}}=CHBr\xrightarrow{\left( r \right)}\] \[CH\equiv CH\xrightarrow{\left( s \right)}\]
$$p$$
$$q$$
$$r$$
$$s$$
(a)
$$B{r_2}$$
$${\text{alc}}.\,KOH$$
$$NaOH$$
$$A{l_2}{O_3}$$
(b)
$$HBr$$
$${\text{alc}}.\,KOH$$
$$Ca{C_2}$$
$$KMn{O_4}$$
(C)
$$HBr$$
$${\text{alc}}.\,KOH$$
$$NaN{H_2}$$
red hot iron tube
(d)
$$B{r_2}$$
$${\text{alc}}.\,KOH$$
$$NaN{H_2}$$
red hot iron tube
A
(a)
B
(b)
C
(c)
D
(d)
Answer :
(d)
No explanation is given for this question. Let's discuss the answer together.
283.
On mercuration-demercuration produces the major product :
A
B
C
D
Answer :
284.
When cyclohexane is poured on water, it floats, because :
A
cyclohexane is in ‘boat’ form
B
cyclohexane is in ‘chair’ form
C
cyclohexane is in ‘crown’ form
D
cyclohexane is less dense than water
Answer :
cyclohexane is less dense than water
The density of cyclohexane is less dense as compared to the water. Hence it floats on water when poured on it.
285.
A compound $$X$$ decolourises $$B{r_2}$$ water and reacts slowly with conc. $${H_2}S{O_4}$$ to givean addition product. $$X$$ reacts with $$HBr$$ to form $$Y.$$ $$Y$$ reacts with $$NaOH$$ to form $$Z.$$ On oxidation $$Z$$ gives hexan-3-one. $$X, Y$$ and $$Z$$ in the reactions are
\[X\xrightarrow{HBr}Y\xrightarrow{NaOH}Z\xrightarrow{\left[ O \right]}\] \[\underset{\begin{align}
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\parallel \\
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
& \,\,\,\,\,\,\,\,\,\,\,\text{Hexan-3-one} \\
& \\
\end{align}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-C-C{{H}_{2}}C{{H}_{3}}}}\,\]
A
Soda lime is a mixture of sodium hydroxide and potassium hydroxide.
B
Methane can be prepared by Wurtz reaction.
C
In alkanes all carbon atoms are $$s{p^3}$$ hybridised.
D
$$neo$$ - Pentane yields three different monochloro derivatives.
Answer :
In alkanes all carbon atoms are $$s{p^3}$$ hybridised.
Soda lime is a mixture of $$NaOH$$ and $$CaO.$$ Methane cannot be obtained by wurtz reaction. The lowest hydrocarbon prepared by Wurtz reaction is ethane.
$$neo$$ - Pentane yields only one monochloro product.
287.
What is the order of reactivity of hydrogen atoms attached to carbon atom in an alkene?
The order of reactivity of hydrogen atoms attached to $$C$$ atom is tertiary > secondary > primary.
288.
In the following reaction,
the major product obtained is
A
B
C
D
Answer :
No explanation is given for this question. Let's discuss the answer together.
289.
Benzene reacts with $$n$$ -propyl chloride in the presence of anhydrous $$AlC{l_3}$$ to give
A
3 - propyl - 1 - chlorobenzene
B
$$n$$ - propyl benzene
C
no reaction
D
$$iso$$ - propyl benzene
Answer :
$$iso$$ - propyl benzene
Electrophilic substitution reaction of benzene ring yields $$iso$$ -propyl benzene.
290.
An alkene having molecular formula $${C_7}{H_{14}}$$ was subjected to ozonolysis in the presence of zinc dust. An equimolar amount of the following two compounds was obtained
The $$IUPAC$$ name of the alkene is