Learn Redox Reaction MCQ questions & answers in Physical Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
151.
Which of the following statements is not true?
A
In a chemical reaction, oxidation is always accompanied by reduction.
B
When a negative ion changes to neutral species, the process is oxidation.
C
Oxidising agent has a tendency to lose electrons.
D
Conversion of Conversion of $$MnO_4^{2 - }$$ to $$MnO_4^ - $$ is oxidation.
Answer :
Oxidising agent has a tendency to lose electrons.
Oxidising agent has a tendency to gain electrons.
152.
In the conversion of $$B{r_2}$$ to $$BrO_3^ - ,$$ the oxidation state of $$Br$$ changes from
A
+1 to +5
B
0 to -3
C
+2 to +5
D
0 to +5
Answer :
0 to +5
$$B{r_2} \to BrO_3^ - $$
For $$B{r_2},$$ oxidation number = 0
For $$BrO_3^ - ,$$ oxidation number, $$x + \left( { - 6} \right) = - 1 \Rightarrow x = + 5$$
153.
When $$Mn{O_2}$$ salt is fused with a mixture of $$KN{O_3}$$ and solid $$KOH$$ the oxidation number of $$Mn$$ changes from + 4 to
$$\mathop {Ca}\limits^{ + 2} \mathop C\limits^{ + 4} \mathop {{O_3}}\limits^{ - 2} \to \mathop {CaO}\limits^{ + 2 - 2} + \mathop {C{O_2}}\limits^{ + 4 - 2} $$
Since there is no change in oxidation number of any species, it is not a redox reaction.
155.
In the balanced chemical reaction $$IO_3^ - + a{I^ - } + b{H^ - } \to c{H_2}O + d{I_2}$$
$$a, b, c$$ and $$d,$$ respectively, correspond to
A
5, 6, 3, 3
B
5, 3, 6, 3
C
3, 5, 3, 6
D
5, 6, 5, 5
Answer :
5, 6, 3, 3
The balanced equation is
156.
Which of the following reactions shows the reducing property of $$S{O_2}?$$
$$\left( {\text{i}} \right)C{l_2} + S{O_2} \to S{O_2}C{l_2}$$
$$\left( {{\text{ii}}} \right)2{H_2}S + S{O_2} \to 3S + 2{H_2}O$$
$$\left( {{\text{iii}}} \right)2FeC{l_3} + S{O_2} + 2{H_2}O \to $$ $$2FeC{l_2} + {H_2}S{O_4} + 2HCl$$
$$\left( {{\text{iv}}} \right)S{O_2} + {H_2}O \to {H_2}S{O_3}$$
A
(i) only
B
(ii) and (iii)
C
(ii) and (iv)
D
(i), (ii) and (iv)
Answer :
(ii) and (iii)
157.
Which of the following elements does not show disproportionation tendency?
A
$$Cl$$
B
$$Br$$
C
$$F$$
D
$$I$$
Answer :
$$F$$
Oxidation state of $$F$$ is fixed (-1) hence, it does not show disproportionation tendency.
158.
Which of the following represents a redox reaction?
A
$$NaOH + HCl \to NaCl + {H_2}O$$
B
$$BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + 2HCl$$
C
$$CuS{O_4} + 2{H_2}O \to Cu{\left( {OH} \right)_2} + {H_2}S{O_4}$$
D
$$Zn + 2HCl \to ZnC{l_2} + {H_2}$$
Answer :
$$Zn + 2HCl \to ZnC{l_2} + {H_2}$$
(A) and (B) are neutralisation reactions. The oxidation state of $$Cu$$ is +2 in both reactant and product, and $$SO_4^{2 - }\,ion$$ does not change. In option (D) is a redox reaction.
$$\eqalign{
& Zn \to Z{n^{2 + }} + 2{e^ - }\left( {{\text{Oxidation}}} \right) \cr
& 2{H^ + } + 2{e^ - } \to {H_2}\left( {{\text{Reduction}}} \right) \cr} $$
159.
For the reaction : $${I^ - } + ClO_3^ - + {H_2}S{O_4} \to $$ $$C{l^ - } + HSO_4^ - + {I_2}$$
The incorrect statement in the balanced equation is
A
stoichiometric coefficient of $$HSO_4^ - $$ is 6
B
iodide is oxidised
C
sulphur is reduced
D
$${H_2}O$$ is one of the products
Answer :
sulphur is reduced
The balanced chemical equation is
160.
Oxidation number of sulphur in peroxomono-sulphuric acid $$\left( {{H_2}S{O_5}} \right)$$ is
A
+ 4
B
+ 2
C
+ 6
D
- 2
Answer :
+ 6
\[{{H}_{2}}S{{O}_{5}};\,H-O-\underset{\begin{smallmatrix}
\downarrow \\
O
\end{smallmatrix}}{\overset{\begin{smallmatrix}
O \\
\uparrow
\end{smallmatrix}}{\mathop{S}}}\,-O-O-H\]
Oxidation number of $$O$$ in peroxo linkage = - 1
Oxidation number of other $$O$$ atoms = - 2
$$ + 2 + x - 6 - 2 = 0\,\,{\text{or}}\,\,x = + 6$$