States of Matter Solid, Liquid and Gas MCQ Questions & Answers in Physical Chemistry | Chemistry
Learn States of Matter Solid, Liquid and Gas MCQ questions & answers in Physical Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
171.
Which curve in figure represents the curve of ideal gas ?
A
$$B$$ only
B
$$C$$ and $$D$$ only
C
$$E$$ and $$F$$ only
D
$$A$$ and $$B$$ only
Answer :
$$B$$ only
For ideal gas $$PV=$$ constant at all pressures
172.
A graph is plotted between pressure and volume at different temperatures. On the basis of the graph what changes will you observe in the volume if
(i) the pressure is increased at constant temperature.
(ii) the temperature is decreased at constant pressure.
A
volume increases in both the cases
B
volume decreases in both the cases
C
volume increases in (i) and decreases in (ii)
D
volume decreases in (i) and increases in (ii).
Answer :
volume decreases in both the cases
Volume decreases when pressure is increased at constant temperature. When temperature is decreased at constant pressure, the volume decreases.
173.
At 1 atmospheric pressure and $$0{\,^ \circ }C,$$ certain mass of a gas measures $$0.4\,L.$$ Keeping the pressure constant, if the temperature is increased to $$273{\,^ \circ }C,$$ what will be its volume ?
174.
When a sample of gas is compressed at constant temperature from $$15\,atm$$ to $$60\,atm,$$ its volume changes from $$76\,c{m^3}$$ to $$20.5\,c{m^3}.$$ Which of the following statements are possible explanations of this behaviour?
(i) The gas behaves non-ideally
(ii) The gas dimerises
(iii) The gas is adsorbed into the vessel walls
A
(i), (ii) and (iii)
B
(i) and (ii) only
C
(ii) and (iii) only
D
(i) only
Answer :
(i) only
$$\eqalign{
& {\text{Given,}}\,{P_1} = 15\,atm,\,{P_2} = 60\,atm \cr
& {V_1} = 76\,c{m^3},\,{V_2} = 20.5\,c{m^3}. \cr} $$
If the gas is an ideal gas, then according to Boyle's law, it must follow the equation,
$$\eqalign{
& {P_1}{V_1} = {P_2}{V_2} \cr
& {P_1} \times {V_1} = 15 \times 76 = 1140 \cr
& {P_2} \times {V_2} = 60 \times 20.5 = 1230 \cr
& \therefore \,\,{P_1}{V_1} \ne {P_2}{V_2} \cr} $$
∴ The gas behaves non-ideally.
The given information is not sufficient to comment on other statements.
175.
At $$NTP$$ the volume of a gas is $$40\,mL.$$ If pressure is increased to $$800\,mm$$ of $$Hg$$ at the same temperature, what will be the volume of the gas ?
176.
Which of the following phenomena does not involve surface tension ?
A
Mercury drops acquire spherical shape.
B
Liquids tend to rise in the capillary.
C
A liquid flows over a fixed surface.
D
Moist soil grains are pulled together.
Answer :
A liquid flows over a fixed surface.
Liquids tend to minimise their surface due to surface tension.
177.
In the corrections made to ideal gas equation for real gases, the reductions in pressure due to forces of attractions between the molecules is directly proportional to
178.
Which of the following expressions correctly represents the relationship between the average molar kinetic energy, $$\overline {KE} $$ of $$CO$$ and $${N_2}$$ molecules at the same temperature?
A
$$\overline {KE} co < {\overline {KE} _{{N_2}}}$$
B
$$\overline {KE} co > {\overline {KE} _{{N_2}}}$$
C
$$\overline {KE} co = {\overline {KE} _{{N_2}}}$$
D
Cannot be predicted unless volumes of the gases are given
Answer :
$$\overline {KE} co = {\overline {KE} _{{N_2}}}$$
$$KE = \frac{3}{2}RT$$ ( for one mole of a gas )
The temperature is constant and kinetic energy is independent on molecular weights. So,
$$\overline {KE} co = {\overline {KE} _{{N_2}}}$$
179.
For a real gas $$\left( {mol.\,mass = 60} \right)$$ if density at critical point is $$0.80\,g/c{m^3}$$ and its $${T_c} = \frac{{4 \times {{10}^5}}}{{821}}K,$$ then van der waals’ constant a $$\left( {{\text{in}}\,atm\,{L^2}\,mo{l^{ - 2}}} \right)$$ is
180.
At constant volume, for a fixed number of moles of a gas the pressure of the gas increases with rise in temperature due to
A
Increase in average molecular speed
B
Increased rate of collisions amongst molecules
C
Increase in molecular attraction
D
Decrease in mean free path
Answer :
Increase in average molecular speed
Due to increase in the temperature, the kinetic energy of the gas molecules increases resulting in an increase in average molecular speed. The molecules are bombarded to the walls of the container with a greater velocity resulting in an increase in pressure.