According to 'Distribution law' in set theory the given both statements are wrong.
Statement 1 - Distribution law
Statement 2 - Distribution law
12.
For a set $$A,$$ consider the following statements :
$$\eqalign{
& 1.\,\,A \cup P\left( A \right) = P\left( A \right) \cr
& 2.\,\,\left\{ A \right\} \cap P\left( A \right) = A \cr
& 3.\,\,P\left( A \right) - \left\{ A \right\} = P\left( A \right) \cr} $$
where $$P$$ denotes power set.
Which of the statements given above is/are correct ?
A
1 only
B
2 only
C
3 only
D
1, 2 and 3
Answer :
1 only
Since, Power set is the collection of all the subsets of the set $$A$$ therefore $$AUP\left( A \right) = P\left( A \right)$$
$$\therefore $$ statement (1) is correct.
13.
If $$P\left( A \right)$$ denotes the power set of $$A$$ and $$A$$ is the void set, then what is the number of elements in $$P\left\{ {P\left\{ {P\left\{ {P\left( A \right)} \right\}} \right\}} \right\}\,?$$
A
0
B
1
C
4
D
16
Answer :
16
Since, $$A$$ is void set therefore the number of elements in power set of $$A$$ is $$1.$$
$$\therefore \,P\left\{ {P\left( A \right)} \right\} = {2^1} = 2$$
because, if set $$A$$ has $$n$$ elements then $$P\left( A \right)$$ has $${2^n}$$ elements.
$$\eqalign{
& \Rightarrow \,P\left\{ {P\left\{ {P\left( A \right)} \right\}} \right\} = {2^2} = 4 \cr
& \Rightarrow P\left\{ {P\left\{ {P\left\{ {P\left( A \right)} \right\}} \right\}} \right\}\, = {2^4} = 16 \cr} $$
14.
Which of the following sets is a finite set ?
A
$$A = \left\{ {x:x\, \in \,Z{\text{ and }}{x^2} - 5x + 6 = 0} \right\}$$
B
$$B = \left\{ {x:x\, \in \,Z{\text{ and }}{x^2}{\text{ is even}}} \right\}$$
C
$$D = \left\{ {x:x\, \in \,Z{\text{ and }}x > - 10} \right\}$$
15.
The relation $$R$$ defined on the set $$A = \left\{ {1,\,2,\,3,\,4,\,5} \right\}$$ by $$R = \left\{ {\left( {x,\,y} \right):\left| {{x^2} - {y^2}} \right| < 16} \right\}$$ is given by :
16.
Let $$U$$ be the universal set and $$A \cup B \cup C = U.$$ Then $$\left\{ {\left( {A - B} \right) \cup \left( {B - C} \right) \cup \left( {C - A} \right)} \right\}'$$ is equal to :
A
$$A \cup B \cup C$$
B
$$A \cup \left( {B \cap C} \right)$$
C
$$A \cap B \cap C$$
D
$$A \cap \left( {B \cup C} \right)$$
Answer :
$$A \cap B \cap C$$
$${\left( {A - B} \right) \cup \left( {B - C} \right) \cup \left( {C - A} \right)}$$ is represented by the shaded portion in the figure. The unshaded portion is $$A \cap B \cap C.$$
$$\therefore \left\{ {\left( {A - B} \right) \cup \left( {B - C} \right) \cup \left( {C - A} \right)} \right\}' = A \cap B \cap C.$$
17.
The relation $$R$$ defined in $$A = \left\{ {1,\,2,\,3} \right\}$$ by $$aRb,$$ if $$\left| {{a^2} - {b^2}} \right| \leqslant 5.$$ Which of the following is false ?
18.
Let $$X = \left\{ {1,\,2,\,3,\,4,\,5} \right\}$$ and $$Y = \left\{ {1,\,3,\,5,\,7,\,9} \right\},$$ which of the following is not relation from $$X$$ to $$Y$$ ?
A
$${R_1} = \left\{ {\left( {x,\,y} \right):y = x + 2,\,x\, \in \,X,\,y\, \in \,Y} \right\}$$
$$\eqalign{
& {R_1}{\text{ is a relation from }}X{\text{ to }}Y{\text{ because }}{R_1} \subseteq X \times Y \cr
& {R_2}{\text{ is a relation from }}X{\text{ to }}Y{\text{ because }}{R_2} \subseteq X \times Y \cr
& {R_3}{\text{ is a relation from }}X{\text{ to }}Y{\text{ because }}{R_3} \subseteq X \times Y \cr
& {R_4}{\text{ is not a relation from }}X{\text{ to }}Y{\text{ because }}\left( {2,\,4} \right),\left( {7,\,9} \right) \notin \,X \times Y \cr} $$
19.
The Cartesian product of two sets $$P$$ and $$Q,$$ i.e., $$P \times Q = \phi ,$$ if :
A
either $$P$$ or $$Q$$ is the null set
B
neither $$P$$ nor $$Q$$ is the null set
C
Both (A) and (B)
D
none of these
Answer :
either $$P$$ or $$Q$$ is the null set
If either $$P$$ or $$Q$$ is the null set, then $$P \times Q$$ will be an empty set, i.e., $$P \times Q = \phi .$$
20.
Let $$f:\left\{ {2,\,3,\,4,\,5} \right\} \to \left\{ {3,\,4,\,5,\,9} \right\}$$ and $$g:\left\{ {3,\,4,\,5,\,9} \right\} \to \left\{ {7,\,11,\,15} \right\}$$ be functions defined as $$f\left( 2 \right) = 3f\left( 3 \right) = 4,\,f\left( 4 \right) = f\left( 5 \right) = 5,\,g\left( 3 \right) = g\left( 4 \right) = 7,$$ and $$g\left( 5 \right) = g\left( 9 \right) = 11.$$ Then $$gof\left( 5 \right)$$ is equal to :