Calorimetry MCQ Questions & Answers in Heat and Thermodynamics | Physics
Learn Calorimetry MCQ questions & answers in Heat and Thermodynamics are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
41.
An experiment takes 10 minutes to raise the temperature of water in a container from $${0^ \circ }C$$ to $${100^ \circ }C$$ and another 55 minutes to convert it totally into steam by a heater supplying heat at a uniform rate. Neglecting the specific heat of the container and taking specific heat of water to be $$1\,cal/{g^ \circ }C,$$ the heat of vapourization according to this experiment will come out to be :
A
$$560\,cal/g$$
B
$$550\,cal/g$$
C
$$540\,cal/g$$
D
$$530\,cal/g$$
Answer :
$$550\,cal/g$$
$$\eqalign{
& {\text{As}}\,\,Pt = mC\Delta T \cr
& {\text{So,}}\,P \times 10 \times 60 = mC100\,......\left( {\text{i}} \right) \cr
& {\text{and}}\,P \times 55 \times 60 = mL\,......\left( {{\text{ii}}} \right) \cr} $$
Dividing equation (i) by (ii) we get
$$\eqalign{
& \frac{{10}}{{55}} = \frac{{C \times 100}}{L} \cr
& \therefore L = 550\,cal./g \cr} $$
42.
A student takes $$50\,gm$$ wax (specific heat $$ = 0.6\,kcal/k{g^ \circ }C$$ ) and heats it till it boils. The graph between temperature and time is as follows. Heat supplied to the wax per minute and boiling point are respectively
A
$$500\,cal,{50^ \circ }C$$
B
$$1000\,cal,{100^ \circ }C$$
C
$$1500\,cal,{200^ \circ }C$$
D
$$1000\,cal,{200^ \circ }C$$
Answer :
$$1500\,cal,{200^ \circ }C$$
Since specific heat $$ = 0.6\,kcal/g{ \times ^ \circ }C = 0.6\,cal/g{ \times ^ \circ }C$$
From graph it is clear that in a minute, the temperature is raised from $${0^ \circ }C$$ to $${50^ \circ }C.$$
$$ \Rightarrow $$ Heat required for a minute $$ = 50 \times 0.6 \times 50 = 1500\,cal.$$
Also from graph, Boiling point of wax is $${200^ \circ }C.$$