Thermodynamics MCQ Questions & Answers in Heat and Thermodynamics | Physics
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51.
In a Carnot engine, the temperature of reservoir is $${927^ \circ }C$$ and that of sink is $${27^ \circ }C.$$ If the work done by the engine when it transfers heat from reservoir to sink is $$12.6 \times {10^6}J,$$ the quantity of heat absorbed by the engine from the reservoir is
52.
A Carnot engine having an efficiency of $$\frac{1}{{10}}$$ as heat engine, is used as a refrigerator. If the work done on the system is $$10\,J,$$ the amount of energy absorbed from the reservoir at lower temperature is
A
$$1\,J$$
B
$$90\,J$$
C
$$99\,J$$
D
$$100\,J$$
Answer :
$$90\,J$$
Consider schematic diagram for a Carnot engine as shown below.
In case of engine,
$${\text{engine efficiency}} = \frac{{{\text{work}}}}{{{\text{heat absorbed}}}} = \frac{W}{{{q_1}}}$$
$$\eqalign{
& \therefore \frac{W}{{{q_1}}} = \frac{1}{{10}} \Rightarrow \frac{{10\,J}}{{{q_1}}} = \frac{1}{{10}} \cr
& {\text{or}}\,\,{q_1} = 100\,J \cr} $$
When this engine is reversed, it takes in work $$W$$ and heat $${q_2}$$ from cold reservoir and ejects $$100\,J$$ of heat to hot reservoir.
$$\eqalign{
& \therefore W + {q_2} = {q_1} \cr
& \Rightarrow 10 + {q_2} = 100 \cr
& {\text{or}}\,\,{q_2} = 90\,J \cr} $$
53.
Which of the following processes is irreversible?
A
Transfer of heat by radiation
B
Adiabatic changes performed slowly
C
Extremely slow extension of a spring
D
Isothermal changes performed slowly
Answer :
Transfer of heat by radiation
Slow isothermal expansion or compression of an ideal gas is reversible process, while the other given processes are irreversible in nature.
54.
During an isothermal expansion, a confined ideal gas does $$-150\,J$$ of work against its surroundings. This implies that
A
$$300\,J$$ of heat has been added to the gas
B
no heat is transferred because the process is isothermal
C
$$150\,J$$ of heat has been added to the gas
D
$$150\,J$$ of heat has been removed from the gas
Answer :
$$150\,J$$ of heat has been added to the gas
Concept
Apply first law of thermodynamics. According to first law of thermodynamics
$$\Delta U = \Delta Q + \Delta W$$
For isothermal process, $$\Delta U = 0$$
So, $$\Delta Q = - \Delta W$$
Given, $$\Delta W = - 150\,J$$
So, $$\Delta Q = + 150\,J$$
When $$Q$$ is positive, the heat is added to the gas.
55.
Unit mass of a liquid with volume $${V_1}$$ is completely changed into a gas of volume $${V_2}$$ at a constant external pressure $$P$$ and temperature $$T.$$ If the latent heat of evaporation for the given mass is $$L,$$ then the increase in the internal energy of the system is
A
Zero
B
$$P\left( {{V_2} - {V_1}} \right)$$
C
$$L - P\left( {{V_2} - {V_1}} \right)$$
D
$$L$$
Answer :
$$L - P\left( {{V_2} - {V_1}} \right)$$
$$\eqalign{
& Q = mL = 1 \times L = L;W = P\left( {{V_2} - {V_1}} \right) \cr
& {\text{Now }}Q = \Delta U + W \cr
& {\text{or}}\,\,L = \Delta U + P\left( {{V_2} - {V_1}} \right) \cr
& \therefore \Delta U = L - P\left( {{V_2} - {V_1}} \right) \cr} $$
56.
A gas is expanded from volume $${V_0}$$ to $$2{V_0}$$ under three different processes. Process 1 is isobaric process, process 2 is isothermal and process 3 is adiabatic.
Let $$\Delta {U_1},\Delta {U_2}$$ and $$\Delta {U_3}$$ be the change in internal energy of the gas is these three processes. Then -
Since volume is same in all three process therefore temperature will be least having least pressure.
57.
“Heat cannot by it self flow from a body at lower temperature to a body at higher temperature” is a statement or consequence of
A
second law of thermodynamics
B
conservation of momentum
C
conservation of mass
D
first law of thermodynamics
Answer :
second law of thermodynamics
This is a statement of second law of thermodynamics
58.
For an ideal gas four processes are marked as 1,2,3 and 4 on $$P-V$$ diagram as shown in figure. The amount of heat supplied to the gas in the process 1, 2, 3 and 4 are $${Q_1},{Q_2},{Q_3}$$ and $${Q_4}$$ respectively, then correct order of heat supplied to the gas is - [$$AB$$ is process-1, $$AC$$ is process-2, $$AD$$ is adiabatic process-3 and $$AE$$ is process-4]
A
$${Q_1} > {Q_2} > {Q_3} > {Q_4}$$
B
$${Q_1} > {Q_2} > {Q_4} > {Q_3}$$
C
$${Q_1} > {Q_4} > {Q_2} > {Q_3}$$
D
$${Q_1} < {Q_2} < {Q_3} < {Q_4}$$
Answer :
$${Q_1} > {Q_2} > {Q_4} > {Q_3}$$
In process-1 heat supplied $$=$$ area under $$AB$$ curve + $$n \times {c_v} \times 100\,\left( {{\text{isobaric process}}} \right)$$
In process-2 heat supplied $$=$$ area under $$AC$$ curve (isothermal process)
In process-3 heat supplied $$= 0$$ (adiabatic process)
In process-4 heat supplied $$ = n \times {c_v}\,\left( {T - 600} \right)\,\left( {{\text{isobaric process}}} \right)$$
59.
An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity $$C$$ remains constant. If during this process the relation of pressure $$P$$ and volume $$V$$ is given by $$P{V^n}$$ = constant, then $$n$$ is given by (Here $${C_P}$$ and $${C_V}$$ are molar specific heat at constant pressure and constant volume, respectively):
60.
A monoatomic gas at a pressure $$p,$$ having a volume $$V$$ expands isothermally to a volume $$2 V$$ and then adiabatically to a volume $$16 V.$$ The final pressure of the gas is (take $$\gamma = \frac{5}{3}$$ )