Co - ordination Compounds MCQ Questions & Answers in Inorganic Chemistry | Chemistry
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31.
Which of the following complexes exists as pair of enantiomers?
A
$$trans - {\left[ {Co{{\left( {N{H_3}} \right)}_4}C{l_2}} \right]^ + }$$
B
$${\left[ {Cr{{\left( {en} \right)}_3}} \right]^{3 + }}$$
C
$$trans - {\left[ {Co{{\left( {en} \right)}_2}C{l_2}} \right]^ + }$$
D
$${\text{All}}\,\,{\text{of}}\,\,{\text{these}}$$
Optical isomerism is common in octahedral complexes of the formula $$\left[ {M{a_2}{b_2}{c_2}} \right],\left[ {M{{\left( {AA} \right)}_3}} \right],$$ etc. $${\left[ {Cr{{\left( {en} \right)}_3}} \right]^{3 + }}$$ shows optical isomerism and exists as a pair of enantiomers.
32.
Match the complex ions given in column I with their colour given in column II and mark the appropriate choice.
No explanation is given for this question. Let's discuss the answer together.
33.
Two isomers of a compound $$Co{\left( {N{H_3}} \right)_3}C{l_3}\left( {M{A_3}{B_3}\,{\text{type}}} \right)$$ are shown in the figures.
The isomers can be classified as
A
(i) $$fac$$ - isomer (ii) $$mer$$ - isomer
B
(i) optical-isomer (ii) $$trans$$ - isomer
C
(i) $$mer$$ - isomer (ii) $$fac$$ - isomer
D
(i) $$trans$$ -isomer (ii) $$cis$$ -isomer
Answer :
(i) $$fac$$ - isomer (ii) $$mer$$ - isomer
34.
Which of the following ligands is expected to be bidentate ?
A
$$C{H_3}N{H_2}$$
B
$$C{H_3}C \equiv N$$
C
$$Br$$
D
$${C_2}O_4^{2 - }$$
Answer :
$${C_2}O_4^{2 - }$$
$${C_2}O_4^{2 - }$$ is a bidentate ligand because it has two donor atoms (sites) and can coordinate to the central ion at two positions.
35.
The structure of which of the following chloro species can be explained on the basis of $$ds{p^2}$$ hybridization ?
A
$${\left[ {PdC{l_4}} \right]^{2 - }}$$
B
$${\left[ {FeC{l_4}} \right]^{2 - }}$$
C
$${\left[ {CoC{l_4}} \right]^{2 - }}$$
D
$${\left[ {NiC{l_4}} \right]^{2 - }}$$
Answer :
$${\left[ {PdC{l_4}} \right]^{2 - }}$$
$${\left[ {PbC{l_4}} \right]^{2 - }}$$ is $$ds{p^2}$$ hybridized and square planar in shape.
36.
The spin only magnetic moment value (in Bohr magneton units) of $$Cr{\left( {CO} \right)_6}$$ is
A
$$0$$
B
$$2.84$$
C
$$4.90$$
D
$$5.92$$
Answer :
$$0$$
Chromium in $$Cr{\left( {CO} \right)_6}$$ is in zero oxidation state and has $${\left[ {Ar} \right]^{18}}3{d^5}4{s^1}$$ as the electronic configuration. However, $$CO$$ is a strong ligand, hence pairing up of electrons takes place leading to following configuration in $$Cr{\left( {CO} \right)_6}.$$
Since the complex has no unpaired electron, its magnetic moment is zero.
37.
Which of the following is not a neutral ligand ?
A
$${H_2}O$$
B
$$N{H_3}$$
C
$$ONO$$
D
$$CO$$
Answer :
$$ONO$$
$$ONO$$ is an anionic ligand $$\left( {ON{O^ - }} \right).$$
38.
In metal carbonyl having general formula $$M{\left( {CO} \right)_x}$$ where, $$M =$$ metal, $$x= 4$$ and the metal is bonded to
A
carbon and oxygen
B
$$C \equiv O$$
C
oxygen
D
carbon
Answer :
carbon
In metal carbonyl $$M\left( {C{O_4}} \right),$$ metal is bonded to the ligand $$CO$$ through carbon atoms. These compounds contain both $$\sigma $$ and $$\pi $$ - bonded complexes.
$$\sigma $$ - bond between metal and carbon atom is formed when a vacant hybrid orbital of the metal atom overlaps with an orbital on $$C$$ - atom of carbon monooxide containing a low pair of electron. Formation of $$\pi $$ - bond is occurs when a filled orbital of the metal atom overlaps with a vacant antibonding $$\pi $$ - orbital of $$C$$ - atom of $$Co.$$
39.
The charges $$x$$ and $$y$$ on the following ions are
$$\eqalign{
& \left( {\text{i}} \right){\left[ {Co{{\left( {N{H_3}} \right)}_2}C{l_4}} \right]^x} \cr
& \left( {{\text{ii}}} \right){\left[ {Fe{{\left( {CN} \right)}_6}} \right]^y} \cr} $$
( Oxidation state of $$Co$$ is +3 and $$Fe$$ is +2 in their respective complexes. )
A
$$x = + 1,y = - 1$$
B
$$x = - 1,y = + 3$$
C
$$x = - 1,y = - 4$$
D
$$x = - 2,y = - 3$$
Answer :
$$x = - 1,y = - 4$$
In $${\left[ {Co{{\left( {N{H_3}} \right)}_2}C{l_4}} \right]^x},$$
oxidation state of $$Co = +3$$
Hence, $$x = + 3 + 2 \times 0 + 4 \times ( - 1){\text{ }} = - 1$$
In $${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^y},$$ oxidation state of $$Fe = +2$$
Hence, $$y = + 2 + 6 \times \left( { - 1} \right) = - 4$$
40.
Red precipitate is obtained when ethanol solution of dimethylglyoxime is added to ammoniacal $$Ni\left( {{\text{II}}} \right){\text{.}}$$ Which of the following statements is not true ?
A
Red complex has a square planar geometry.
B
Complex has symmetrical $$H$$ - bonding
C
Red complex has a tetrahedral geometry.
D
Dimethylglyoxime functions as bidentate ligand.
Answer :
Red complex has a tetrahedral geometry.
Nickel ions are frequently detected by the formation of red precipitate of the complex of nickel dimethylglyoxime, when heated with dimethylglyoxime.