P - Block Elements MCQ Questions & Answers in Inorganic Chemistry | Chemistry
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151.
Identify $$X$$ in the reaction : \[X+\underset{\left( \text{Steam} \right)}{\mathop{2{{H}_{2}}O}}\,\xrightarrow{\Delta }X{{O}_{2}}+2{{H}_{2}}\]
A
$$C$$
B
$$Pb$$
C
$$Ge$$
D
$$Sn$$
Answer :
$$Sn$$
\[Sn+\underset{\text{Steam}}{\mathop{2{{H}_{2}}O}}\,\xrightarrow{\Delta }Sn{{O}_{2}}+2{{H}_{2}}\]
Tin decomposes steam to form tin dioxide and dihydrogen gas.
152.
Out of $$\left( {\text{i}} \right)Xe{O_3}\left( {{\text{ii}}} \right)XeO{F_4}$$ and $$\left( {{\text{iii}}} \right)Xe{F_6},$$ the molecules having same number of lone pairs on $$Xe$$ are
A
(i) and (ii) only
B
(i) and (iii) only
C
(ii) and (iii) only
D
(i), (ii) and (iii)
Answer :
(i), (ii) and (iii)
153.
Which is not the use of orthoboric acid ?
A
As an antiseptic and eye wash.
B
In glass industry.
C
In glazes for pottery.
D
In borax - bead test.
Answer :
In borax - bead test.
Borax on heating gives $${B_2}{O_3}$$ and $$NaB{O_2}$$ which is glassy mass and used for boraxbead test.
154.
The increasing order of the first ionization enthalpies of the
elements $$B,P,S\,{\text{and}}\,F$$ (Lowest first) is
A
$$B < P < S < F$$
B
$$B < S < P < F$$
C
$$F < S < P < B$$
D
$$P < S < B < F$$
Answer :
$$B < S < P < F$$
The correct order of ionisation enthalpies is
$$F > P > S > B$$
NOTE : On moving along a period ionization enthalapy increases from left to right and decreases from top to bottom in a group. But this trend breaks up in case of atom having fully or half filled stable orbitals.
In this case $$P$$ has a stable half filled electronic configuration hence its ionisation enthalapy is greater in comparision to $$S$$ . Hence the correct order is $$B < S < P < F.$$
155.
First ionisation enthalpy of $$Al$$ is lower than that of $$Mg.$$ This is because
A
the size of $$Al$$ is bigger than $$Mg$$
B
ionisation enthalpy decrease in a period from left to right
C
it is easier to remove electron from unpaired $$3{p^1}$$ than from paired $$3{s^2}$$
D
aluminium is a passive metal while magnesium is active metal
Answer :
it is easier to remove electron from unpaired $$3{p^1}$$ than from paired $$3{s^2}$$
Electronic configuration of $$Al - 1{s^2}2{s^2}2{p^6}3{s^2}3{p^1}$$
Electronic configuration of $$Mg - 1{s^2}2{s^2}2{p^6}3{s^2}$$
It is difficult to remove electron from paired $$3{s^2}$$ - orbital than unpaired $$3{p^1}.$$ Hence, $$I.E.$$ of $$Al$$ is lower than $$Mg.$$
156.
Match the column I with column II and mark the appropriate choice.
Column I
Column II
a.
Galena
1.
Abrasive
b.
Diamond
2.
Metal carbonyls
c.
Carbon monoxide
3.
Hydrides of $$Si$$
d.
Silanes
4.
An ore of lead
A
a - 4, b - 2, c - 1, d - 3
B
a - 4, b - 1, c - 2, d - 3
C
a - 2, b - 1, c - 3, d - 4
D
a - 1, b - 2, c - 3, d - 4
Answer :
a - 4, b - 1, c - 2, d - 3
No explanation is given for this question. Let's discuss the answer together.
157.
Among the following, which one is a wrong statement?
A
$$P{H_5}$$ and $$BiC{l_5}$$ do not exist
B
$$p\pi - d\pi $$ bonds are present in $$S{O_2}$$
C
$$Se{F_4}$$ and $$C{H_4}$$ have same shape
D
$$I_3^ + $$ has bent geometry
Answer :
$$Se{F_4}$$ and $$C{H_4}$$ have same shape
$$P{H_5}$$ does not exist due to very less electronegativity difference between $$P$$ and $$H.$$
Hydrogen is slightly more electronegative than phosphorus, thus could not hold significantly the sharing electrons.
On the other hand, $$BiC{l_5}$$ does not exist due to inert pair effect.
On moving down the group, +5 oxidation state becomes less stable while +3 oxidation state becomes more stable.
In $$S{O_2},p\pi - d\pi $$ and $$p\pi - p\pi $$ both types of bonds are present
Thus, $$Se{F_4}$$ and $$C{H_4}$$ do not have same shape.
Thus, option (C) is incorrect statement.
158.
Which one of the following compounds is not a protonic acid?
A
$$SO{\left( {OH} \right)_2}$$
B
$$S{O_2}{\left( {OH} \right)_2}$$
C
$$B{\left( {OH} \right)_3}$$
D
$$PO{\left( {OH} \right)_3}$$
Answer :
$$B{\left( {OH} \right)_3}$$
$$B{\left( {OH} \right)_3}$$ is not a protonic acid because it does not give proton on ionisation directly, while it acts as Lewis acid due to acceptance of $$O{H^ - }$$ from water and forms a hydrated species.
$$B{\left( {OH} \right)_3} + {H_2}O \to {\left[ {B{{\left( {OH} \right)}_4}} \right]^ - } + {H^ + }$$
159.
Nitrogen is used to fill electric bulbs because
A
it is lighter than air
B
it makes the bulb to glow
C
it does not support combustion
D
it is non toxic
Answer :
it does not support combustion
$${N_2}$$ does not support combustion and thus, it is filled in electric bulbs.
160.
The oxyacid of sulphur that contains a lone pair of electrons on sulphur is