S - Block Elements MCQ Questions & Answers in Inorganic Chemistry | Chemistry

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151. The metallic sodium disolves in liquid ammonia to form a deep blue coloured solution. The deep blue colour is due to formation of :

A solvated electron, $$e\left( {N{H_3}} \right)_x^ - $$
B solvated atomic sodium, $$Na{\left( {N{H_3}} \right)_y}$$
C $$\left( {N{a^ + } + N{a^ - }} \right)$$
D $$NaN{H_2} + {H_2}$$
Answer :   solvated electron, $$e\left( {N{H_3}} \right)_x^ - $$

152. Based on lattice energy and other considerations, which one of the following alkali metal chloride is expected to have the highest melting point ?

A $$NaCl$$
B $$KCl$$
C $$LiCl$$
D $$RbCl$$
Answer :   $$NaCl$$

153. Sodium is heated in air at $${300^ \circ }C$$  to form $$X.$$  $$X$$ absorbs $$C{O_2}$$  and forms $$N{a_2}C{O_3}$$  and $$Y.$$  Which of the following is $$Y?$$

A $${H_2}$$
B $${O_2}$$
C $${H_2}{O_2}$$
D $${O_3}$$
Answer :   $${O_2}$$

154. The correct order of the solubility of sulphates of alkaline earth metals in water is

A $$Be> Ca > Mg > Ba > Sr$$
B $$Mg > Be > Ba > Ca > Sr$$
C $$Be> Mg > Ca > Sr > Ba$$
D $$Mg> Ca > Ba > Be > Sr$$
Answer :   $$Be> Mg > Ca > Sr > Ba$$

155. Which of the following does not illustrate the anomalous properties of lithium ?

A The melting point and boiling point of $$Li$$  are comparatively high
B $$Li$$  is much softer than the other group $$I$$ metals
C $$Li$$  forms a nitride $$L{i_3}N$$  unlike group $$I$$ metals
D The ion of $$Li$$  and its compounds are more heavily hydrated than those of the rest of the group
Answer :   $$Li$$  is much softer than the other group $$I$$ metals

156. Nuclear attraction is often the deciding control factor for the association of neutral molecules to a given metal ion. Which one of the following represents the correct order of stability of the ions? $${\left[ {Be\left( {{H_2}{O_4}} \right)} \right]^{2 + }},{\left[ {Mg{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }},$$       $${\left[ {Ca{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}\,{\text{and}}\,{\left[ {Sr{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}$$

A $${\left[ {Be{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }} > \left[ {{{\left. {Sr{{\left( {{H_2}O} \right)}_4}} \right]}^{2 + }}} \right]$$       $$ > {\left[ {Mg{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }} > {\left[ {Ca{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}$$
B $${\left[ {Ca{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }} > {\left[ {Mg{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}$$       $$ > {\left[ {Be{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }} > {\left[ {Sr{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}$$
C $${\left[ {Sr{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }} > {\left[ {Ca{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}$$       $$ > {\left[ {Mg{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }} > {\left[ {Be{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}$$
D $${\left[ {Be{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }} > {\left[ {Mg{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}$$       $$ > {\left[ {Ca{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }} > {\left[ {Sr{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}$$
Answer :   $${\left[ {Be{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }} > {\left[ {Mg{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}$$       $$ > {\left[ {Ca{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }} > {\left[ {Sr{{\left( {{H_2}O} \right)}_4}} \right]^{2 + }}$$

157. A sodium salt on treatment with $$MgC{l_2}$$   gives white precipitate only on heating. The anion of the sodium salt is

A $$HCO_3^ - $$
B $$CO_3^{2 - }$$
C $$NO_3^ - $$
D $$SO_4^{2 - }$$
Answer :   $$HCO_3^ - $$

158. The metal $$X$$ is prepared by the electrolysis of fused chloride. It reacts with hydrogen to form a colourless solid from which hydrogen is released on treatment with water. The metal is :

A $$Ca$$
B $$Al$$
C $$Zn$$
D $$Cu$$
Answer :   $$Ca$$

159. In the given chemical reactions, \[2P+{{H}_{2}}O+C{{O}_{2}}\to Q\xrightarrow{{{H}_{2}}O\,+\,C{{O}_{2}}}\]       \[2R\xrightarrow{NaCl}S+N{{H}_{4}}Cl\]
Identify $$S.$$

A $$N{a_2}C{O_3}$$
B $$NaOH$$
C $$NaHC{O_3}$$
D $$N{H_3}$$
Answer :   $$NaHC{O_3}$$

160. Match the column I with column II and mark the appropriate choice.
Column I Column II
a. Quick lime 1. Setting fractured bones
b. Plaster of Paris 2. A constituent of chewing gum
c. Slaked lime 3. Manufacture of bleaching powder
d. Limestone 4. Manufacture of dyestuffs

A a - 1, b - 4, c - 2, d - 3
B a - 4, b - 1, c - 3, d - 2
C a - 2, b - 3, c - 1, d - 4
D a - 3, b - 2, c - 4, d - 1
Answer :   a - 4, b - 1, c - 3, d - 2