Learn Carboxylic Acid MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
91.
The compounds $$P,$$ $$Q$$ and $$S$$
were separately subjected to nitration using $$HN{O_3}/{H_2}S{O_4}$$
mixture. The major product formed in each case respectively,
is :
A
B
C
D
Answer :
92.
Carboxylic acids are more acidic than phenol and alcohol because of
A
intermolecular hydrogen bonding
B
formation of dimers
C
highly acidic hydrogen
D
resonance stabilization of their conjugate base
Answer :
resonance stabilization of their conjugate base
In carboxylates ( conjugate base of carboxylic acids ), resonance is more significant because the two resonating structures are similar, while in phenoxide, the resonating structures are not equivalent, alkoxide ions do not show resonance.
93.
In the presence of a small amount of phosphorous, aliphatic carboxylic acids react with chlorine or bromine to yield a compound in which \[\alpha \] - hydrogen has been replaced by halogen. This reaction is known as :
A
Wolff - Kishner reaction
B
Rosenmund reaction
C
Etard reaction
D
Hell - Volhard - Zelinsky reaction
Answer :
Hell - Volhard - Zelinsky reaction
Hell-Volhard-Zelinsky Reaction :
It is \[\alpha \] - substitution when a carboxylic acid having \[\alpha \] - hydrogens is treated with chlorine or bromine in presence of small amount of red phosphorous.
94.
In the mechanism of Hoffmann reaction, which intermediate rearranges to alkyl isocyanate ?
A
Bromamide
B
Nitrene
C
Nitroso
D
Amide
Answer :
Nitrene
95.
$$\alpha $$ - Hydroxypropanoic acid can be prepared from ethanal by following the steps given in the sequence.
A
Treat with $$HCN$$ followed by acidic hydrolysis.
B
Treat with $$NaHS{O_3}$$ followed by reaction with $$N{a_2}C{O_3}.$$
C
Treat with $${H_2}S{O_4}$$ followed by hydrolysis.
D
Treat with $${K_2}C{r_2}{O_7}$$ in presence of sulphuric acid.
Answer :
Treat with $$HCN$$ followed by acidic hydrolysis.
96.
Benzoic acid may be converted into ethyl benzoate by reaction with
A
sodium ethoxide
B
ethyl chloride
C
dry $$HCl,{C_2}{H_5}OH$$
D
ethanol
Answer :
dry $$HCl,{C_2}{H_5}OH$$
Ethyl benzoate is prepared by reacting benzoic acid and ethanol in the presence of dry $$HCl.$$ This reaction is known as esterification reaction.
$$\mathop {{C_6}{H_5}COO{C_2}{H_5}}\limits_{{\text{Ethyl benzoate}}} + {H_2}O$$
This reaction proceed with equilibrium.
Therefore, $${H_2}O$$ continuously removed from reaction for preparation of ester product.
97.
Identify $$(X)$$ and $$(Y)$$ in the given reaction sequence. \[\xrightarrow[KOH]{KMn{{O}_{4}}}X\xrightarrow{{{H}_{3}}{{O}^{+}}}Y\]
A
B
C
D
Answer :
98.
Phenol on treatment with $$C{O_2}$$ in the presence of $$NaOH$$ followed by acidification produces compound $$X$$ as the major product. $$X$$ on treatment with $${\left( {C{H_3}CO} \right)_2}O$$ in the presence of catalytic amount of $${H_2}S{O_4}$$ produces :
A
B
C
D
Answer :
99.
Identify the correct order of boiling points of the following compounds :
\[\underset{1}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH}}\,\,\,\,\underset{2}{\mathop{\,C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO}}\,\] \[\underset{3}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COOH}}\,\]
A
1 > 2 > 3
B
3 > 1 > 2
C
1 > 3 > 2
D
3 > 2 > 1
Answer :
3 > 1 > 2
Due to $$–I$$ effect of the $$–COOH$$ group, $$H$$ - bonds in acids are much stronger than in alcohols; while aldehydes do not exhibit $$H$$ - bonding.
100.
The correct order of strengths of the carboxylic acids
A
I > II > III
B
II > III > I
C
III > II > I
D
II > I > III
Answer :
II > III > I
Key Idea Order of strengths of the given carboxylic acids can be determined by the concept of $$I$$ - effect.
The oxygen atom present in the ring shows $$I$$ - effect. As the distance between oxygen and $$-COOH$$ group increases, $$-I$$ - effect of oxygen decreases.
Thus, coresponding carboxylic acid will show less acidic nature.
The correct order of strengths of the carboxylic acids is