Learn Carboxylic Acid MCQ questions & answers in Organic Chemistry are available for students perparing for IIT-JEE, NEET, Engineering and Medical Enternace exam.
121.
Consider the following transformations :
\[C{{H}_{3}}COOH\xrightarrow{CaC{{O}_{3}}}A\xrightarrow{\text{heat}}B\xrightarrow[NaOH]{{{I}_{2}}}C\]
The molecular formula of $$C$$ is
A
\[C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
I
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,OH \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{3}}\]
B
$$IC{H_2} - COC{H_3}$$
C
$$CH{I_3}$$
D
$$C{H_3}I$$
Answer :
$$CH{I_3}$$
122.
An ester is boiled with $$KOH.$$ The product is cooled and acidified with $$conc.$$ $$HCl.$$ A white crystalline acid separates. The ester is
A
methyl acetate
B
ethyl acetate
C
ethyl formate
D
ethyl benzoate
Answer :
ethyl benzoate
123.
The compound used as a preservative, for food products such as tomato ketchup and fruit juices, is
A
sodium salicylate
B
sodium benzoate
C
sodium acetate
D
formic acid
Answer :
sodium benzoate
Sodium benzoate is a white soluble powder. It is used as an antiseptic and as a food preservative.
124.
The carboxyl functional group $$\left( { - COOH} \right)$$ is present in
A
picric acid
B
barbituric acid
C
ascorbic acid
D
aspirin
Answer :
aspirin
125.
An aromatic compound $$\left( X \right)\left( {{C_8}{H_8}O} \right)$$ gives positive 2, 4-$$DNP$$ test. It gives a yellow precipitate of compound $$(Y)$$ on reaction with iodine and sodium hydroxide solution. $$(X)$$ does not give Tollens' test on oxidation under drastic conditions. It gives a carboxylic acid $$\left( Z \right)\left( {{C_7}{H_6}{O_2}} \right).$$ $$(Z)$$ is also formed with $$(Y)$$ during the reaction. $$(X), (Y)$$ and $$(Z)$$ respectively are
126.
In a set of reactions propionic acid yielded a compound $$D.$$
\[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow{SOC{{l}_{2}}}\] \[B\xrightarrow{N{{H}_{3}}}C\xrightarrow[B{{r}_{2}}]{KOH}D\]
The structure of $$D$$ would be
A
$$C{H_3}C{H_2}C{H_2}N{H_2}$$
B
$$C{H_3}C{H_2}CON{H_2}$$
C
$$C{H_3}C{H_2}NHC{H_3}$$
D
$$C{H_3}C{H_2}N{H_2}$$
Answer :
$$C{H_3}C{H_2}N{H_2}$$
For the reaction,
\[\underset{A}{\mathop{C{{H}_{3}}C{{H}_{2}}COOH}}\,\xrightarrow[\begin{smallmatrix}
-S{{O}_{2}} \\
-HCl
\end{smallmatrix}]{SOC{{l}_{2}}}\] \[\underset{B}{\mathop{C{{H}_{3}}C{{H}_{2}}COCl}}\,\]
\[\xrightarrow[-HCl]{N{{H}_{3}}}\underset{C}{\mathop{C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}}}\,\] \[\xrightarrow[\left( -2KB\mathbf{r},-{{K}_{2}}C{{O}_{3}},-2{{H}_{2}}O \right)]{4KOH+B{{r}_{2}}}\underset{\begin{smallmatrix}
D \\
\text{(Ethyl amine)}
\end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\]
Hence, it is also called Hofmann bromamide degradation reaction.
Hence, compound $$'D'$$ is $$C{H_3} - C{H_2} - N{H_2}.$$
Hofmann bromamide reaction degrade the one $$C$$ in amine product from amide.
127.
Benzoyl chloride is prepared from benzoic acid by
129.
What is the missing reagent in the synthesis shown below \[\xrightarrow[\left( \text{ii} \right)\,\text{Reagant}]{\left( \text{i} \right)\,EtONa}\]
\[\xrightarrow[\Delta ]{NaOH,{{H}_{2}}O}\,\,\,\xrightarrow[\left( \text{ii} \right)\,\Delta ]{\left( \text{i} \right)\,{{H}_{2}}O,{{H}^{+}}}\]
A
bromocyclopentane
B
1, 5 - dibromo pentane
C
1, 4 - dibromo butane
D
1, 1 - dibromo cyclopentane
Answer :
1, 4 - dibromo butane
130.
The correct decreasing order for acid strength is :
A
$$N{O_2}C{H_2}COOH > FC{H_2}COOH > $$ $$CNC{H_2}COOH > ClC{H_2}COOH$$
B
$$FC{H_2}COOH > NCC{H_2}COOH > $$ $$N{O_2}C{H_2}COOH > ClC{H_2}COOH$$
C
$$CNC{H_2}COOH > N{O_2}C{H_2}COOH > $$ $$FC{H_2}COOH > ClC{H_2}COOH$$
D
$$N{O_2}C{H_2}COOH > NCC{H_2}COOH > $$ $$FC{H_2}COOH > ClC{H_2}COOH$$
The acidic strength of a compound or an acid depends on the inductive effect $$\left( { - I} \right)$$ . Higher the $$\left( { - I} \right)$$ effect of a substituent higher will be acidic strength. Now, the decreasing order of $$\left( { - I} \right)$$ effect of the given substituents is $$N{O_2} > CN > F > Cl.$$
∴ The correct decreasing order of acidic strength amongst the given carboxylic acids is :
$$N{O_2}C{H_2}COOH > CNC{H_2}COOH > FC{H_2}COOH > ClC{H_2}COOH$$